/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 152 A ballistic pendulum is used to ... [FREE SOLUTION] | 91Ó°ÊÓ

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A ballistic pendulum is used to measure the speed of high-speed projectiles. A \(6-\mathrm{g}\) bullet \(A\) is fired into a \(1-\mathrm{kg}\) wood block \(B\) suspended by a cord with a length of \(l=2.2 \mathrm{m}\). The block then swings through a maximum angle of \(\theta=60^{\circ} .\) Determine \((a)\) the initial speed of the bullet \(v_{0},(b)\) the impulse imparted by the bullet on the block, \((c)\) the force on the cord immediately after the impact.

Short Answer

Expert verified
Initial speed of bullet: 780.65 m/s; Impulse: 4.68 Ns; Force on cord: 19.71 N.

Step by step solution

01

Analyze the Problem

This problem involves a ballistic pendulum, where a bullet collides inelastically with a block, causing it to swing. The objective is to find the bullet's initial speed, the impulse imparted, and the force on the cord just after the collision. We will use principles of conservation of momentum and energy to solve this.
02

Calculate the Maximum Height of the Swing

To find the maximum height, use the geometry of the swing. The block swings to a maximum angle of \(\theta = 60^{\circ}\). The initial and final heights from the swing give us:\[ h = l - l \cos(\theta) = 2.2 - 2.2 \cos(60^\circ) \]\[ h = 2.2 - 1.1 = 1.1 \, \text{m} \]
03

Apply Conservation of Energy

Use conservation of energy to find the velocity just after the collision. At maximum height, all kinetic energy is converted into potential energy:\[ \frac{1}{2}MV^2 = Mg h \]Where \(M = m_{bullet} + m_{block} = 0.006 \text{ kg} + 1 \text{ kg} = 1.006 \, \text{kg}\),\[ V^2 = 2gh \]\[ V = \sqrt{2 \times 9.8 \times 1.1} \approx 4.65 \, \text{m/s} \]
04

Use Conservation of Momentum for Initial Speed

Use conservation of momentum to solve for the bullet's initial speed \(v_0\).The momentum before and after collision:\[ m_{bullet} v_0 = MV \]\[ 0.006 v_0 = 1.006 \times 4.65 \]\[ v_0 = \frac{1.006 \times 4.65}{0.006} \approx 780.65 \, \text{m/s} \]
05

Calculate the Impulse

Impulse is the change in momentum, which is the same as the momentum of the system after the collision since the block starts from rest.\[ I = MV = 1.006 \times 4.65 \]\[ I = 4.68 \, \text{Ns} \]
06

Calculate the Force on the Cord

Right after the impact, the force on the cord has components due to weight and centripetal motion. The tension \(T\) just after impact is calculated as:\[ T = Mg + \frac{MV^2}{l} \]\[ T = 1.006 \times 9.8 + \frac{1.006 \times (4.65)^2}{2.2} \]\[ T = 9.85 + 9.86 = 19.71 \, \text{N} \]
07

Conclusion

We have calculated the bullet's initial speed, impulse imparted to the block, and the tension in the cord right after the collision using principles of conservation of momentum and energy.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conservation of Momentum
In physics, the conservation of momentum describes how the total momentum of an isolated system remains constant when no external forces act on it. This principle plays a vital role in analyzing ballistic pendulum problems where a projectile, like a bullet, embeds itself into another object, such as a wooden block. Initially, just before the collision, the block is at rest, and only the bullet carries momentum. The momentum of the system before the collision is simply the momentum of the bullet, given by:
  • \( p_{initial} = m_{bullet} \times v_{0} \)

After the collision, both the bullet and the block move together as a single unit, and we define its momentum as:
  • \( p_{final} = (m_{bullet} + m_{block}) \times V \)
By setting these equal, due to conservation, we find:
  • \( m_{bullet} \times v_{0} = (m_{bullet} + m_{block}) \times V \)
This equation allows us to calculate the initial speed of the bullet, given the velocity \(V\) after collision of the combined mass. Understanding momentum conservation is crucial for accurately determining the underlying physics in such interactions.
Inelastic Collision
An inelastic collision is characterized by two objects colliding and moving together as a single mass post-collision. Unlike elastic collisions, where objects rebound with conserved kinetic energy, inelastic collisions entail some loss of kinetic energy, converted into other forms, such as thermal or deformation energy. In the ballistic pendulum scenario, the bullet and block experience a completely inelastic collision. They merge and ascend as one entity.
This union affects how we interpret their movement post-impact, because the system's kinetic energy isn't preserved except in the form of the combined mass's new potential energy due to elevation.
  • Characteristic of inelastic collisions is that although total momentum is conserved, kinetic energy generally is not.
  • These principles allow us to find the system's final velocity ('V') right after collision, even when initial kinetic energy is not directly preserved as kinetic energy post-collision.

Understanding the nature of inelastic collisions in a ballistic pendulum setup helps us unravel complex interactions where conservation principles govern the dynamics at play.
Conservation of Energy
The conservation of energy principle applies to isolated systems where energy can neither be created nor destroyed, only transformed. Even in systems experiencing inelastic collisions, while kinetic energy might not be conserved, the total mechanical energy transfers between different forms. In a ballistic pendulum, the kinetic energy of the system immediately after the collision is transformed into potential energy as the block swings upward. When the block reaches the maximum height, its kinetic energy is fully converted to gravitational potential energy:
  • \( KE_{initial} = PE_{final} \)
  • Using the height (\( h \) reached at maximum swing, the potential energy is:
    • \( PE = (m_{bullet} + m_{block}) \times g \times h \)

By equating the initial kinetic energy to this potential energy, we derive expressions for the system's velocity and subsequently resolve the bullet's initial velocity using momentum equations.
Recognizing how energy conservation plays out in such problems is crucial for effectively linking the initial conditions and outcomes reflected through energy and momentum calculations.

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