/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 151 A 75-g ball is projected from a ... [FREE SOLUTION] | 91Ó°ÊÓ

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A 75-g ball is projected from a height of 1.6 m with a horizontal velocity of 2 m/s and bounces from a 400-g smooth plate supported by springs. Knowing that the height of the rebound is 0.6 m, determine (a) the velocity of the plate immediately after the impact, (b) the energy lost due to the impact.

Short Answer

Expert verified
(a) The velocity of the plate after impact is about 0.409 m/s. (b) The energy lost due to the impact is approximately 1.097 J.

Step by step solution

01

Analyzing the Velocity of the Ball after Rebound

First, calculate the vertical velocity of the ball just before it reaches the maximum height after rebound. Since the maximum height of rebound is 0.6 m, we can use the kinematic equation for potential energy at the maximum height, where the velocity is zero:\[ v_y^2 = v_{0y}^2 - 2gh \]where \( v_y = 0 \) m/s, and \( h = 0.6 \) m.Solving for the initial velocity \( v_{0y} \) just before rebound:\[ v_{0y}^2 = 2gh = 2 \times 9.81 \times 0.6 = 11.772 \]\[ v_{0y} = \sqrt{11.772} \approx 3.43 \text{ m/s} \] (upward).
02

Calculating Initial Velocity Before Impact

Determine the total velocity of the ball just before it hits the plate using horizontal and vertical components.The vertical velocity just before impact is only due to the gravitational fall from 1.6 m:\[ v_{0y}^2 = 2gh = 2 \times 9.81 \times 1.6 = 31.392 \]\[ v_{0y} = \sqrt{31.392} \approx 5.6 \text{ m/s} \] (downward).The initial horizontal velocity \( v_{0x} = 2 \text{ m/s} \).Thus, the velocity of the ball just before impact is:\[ v_{0} = \sqrt{v_{0x}^2 + v_{0y}^2} = \sqrt{2^2 + 5.6^2} \approx 6 \text{ m/s} \] (combined).
03

Conservation of Linear Momentum

Use the principle of conservation of linear momentum for the system of the ball and plate before and after impact. Assume the plate's initial velocity is zero:\[ m_1v_{0} = m_1v_{1}' + m_2v_{2}' \]Where:- \( m_1 = 75 \) g = 0.075 kg (mass of ball)- \( m_2 = 400 \) g = 0.4 kg (mass of plate)- \( v_{0} \approx 6 \) m/s (ball's velocity before impact)- \( v_{1}' = \sqrt{(2)^2 + (v_{0y})^2} \approx \sqrt{4 + 11.772} \approx 3.83 \) m/s (ball's velocity after rebound)Substitute and solve for \( v_{2}' \) (velocity of the plate after impact):\[ 0.075 \times 6 = 0.075 \times 3.83 + 0.4 \times v_{2}' \]\[ v_{2}' = \frac{0.075 \times (6 - 3.83)}{0.4} = \frac{0.1635}{0.4} \approx 0.40875 \text{ m/s} \].
04

Calculating Energy Lost During Impact

Calculate the initial and final kinetic energies to find the energy lost. Initial energy:\[ KE_{initial} = \frac{1}{2}m_1v_0^2 = \frac{1}{2} \times 0.075 \times 6^2 = 1.35 \text{ J} \]Final energy:\[ KE_{final} = \frac{1}{2}m_1v_{1}'^2 + \frac{1}{2}m_2v_{2}'^2 = \frac{1}{2} \times 0.075 \times (3.83)^2 + \frac{1}{2} \times 0.4 \times (0.40875)^2 \]\[ KE_{final} = 0.2193 + 0.0335 = 0.2528 \text{ J} \]Energy lost:\[ E_{lost} = KE_{initial} - KE_{final} = 1.35 - 0.2528 = 1.0972 \text{ J} \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinematics
Kinematics involves studying the motion of objects without considering the forces that cause this motion.
Understanding kinematics is crucial to determine the velocity and trajectory of a moving object.
In the exercise, we explore the kinematics of a bouncing ball.
We calculate the vertical velocity using the formula for potential energy which is converted to kinetic energy as it moves upwards:
  • The equation is given as: \( v_y^2 = v_{0y}^2 - 2gh \)
  • Where \( v_y \) (velocity at max height) equals zero due to the top of the bounce.
  • Here, \( g \) stands for gravity (9.81 m/s²), and \( h \) is the rebound height (0.6 m).
We discover the initial vertical velocity just before the ball begins its descent again by rearranging and solving this equation.
This allows us to understand how high the ball can reach after bouncing and at what speed it travels.
Knowing the horizontal velocity, we can compute the complete velocity vector right before it makes contact with the plate.
Conservation of Momentum
The concept of conservation of momentum is a pivotal principle in collision and impact analysis.
It states that the total momentum of a closed system is conserved if no external forces act on it.
Considering the system of the ball and plate, we assume the plate is initially at rest and determine how their velocities change post-collision.
  • The conservation of linear momentum is expressed as: \( m_1v_{0} = m_1v_{1}' + m_2v_{2}' \)
  • Where \( m_1 \) and \( m_2 \) denote the masses of the ball and plate respectively.
  • \( v_{0} \) is the initial velocity of the ball, \( v_{1}' \) is the ball's velocity after impact, and \( v_{2}' \) is the velocity of the plate we aim to find.
By inserting known values, we solve for the velocity of the plate right after the impact.
This momentum exchange demonstrates how velocities alter during interactions in isolated systems when friction or external forces do not interfere.
Energy Conservation
Energy conservation principles allow us to track energy flow in a mechanical system.
Total mechanical energy in an ideal isolated system remains constant. However, in real-world scenarios, energy disperses through various forms and may seem to 'disappear.'
In the exercise, we examine energy conservation to determine energy loss during the ball's collision with the plate.
  • Initial kinetic energy (before impact) examines the motion's completeness using: \( KE_{initial} = \frac{1}{2}m_1v_0^2 \)
  • Final kinetic energy (post-impact) considers remaining energy in both ball and plate: \( KE_{final} = \frac{1}{2}m_1v_{1}'^2 + \frac{1}{2}m_2v_{2}'^2 \)
  • The energy lost calculates as: \( E_{lost} = KE_{initial} - KE_{final} \)
The difference reveals energy transformed into sound, heat, or deformation.
This understanding underscores the concept of energy dissipation during physical impacts or interactions.
Impact Analysis
Impact analysis investigates how forces and velocities change when objects collide.
This helps determine the resultant motion and energy transformations.
Understanding this allows us to predict object behavior in various scenarios, such as a ball bouncing off a surface.
  • Analyzing impacts involves assessing both momentum and energy before and after events.
  • Using momentum conservation, we calculate dynamic exchanges at collision and derive object paths after impact.
  • Energy loss analysis discloses the efficiency of energy transfer during such interactions.
These analyses help in improving practical applications such as sports mechanics, vehicle safety designs, and any situation where predicting outcomes of interactions is valuable.
By characterizing these collision effects, we can predict how systems behave and design them more effectively.

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Most popular questions from this chapter

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