/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 140 A \(1.62-\) oz golf ball is hit ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A \(1.62-\) oz golf ball is hit with a golf club and leaves it with a velocity of \(100 \mathrm{mi} / \mathrm{h}\). We assume that for \(0 \leq t \leq t_{0},\) where \(t_{0}\) is the duration of the impact, the magnitude \(F\) of the force exerted on the ball can be expressed as \(F=F_{m} \sin \left(\pi t / t_{0}\right) .\) Knowing that \(t_{0}=0.5 \mathrm{ms}\), determine the maximum value \(F_{m}\) of the force exerted on the ball.

Short Answer

Expert verified
The maximum force exerted on the ball is approximately 6490 N.

Step by step solution

01

Convert Units

First, convert the velocity of the golf ball from miles per hour to meters per second. The conversion factors are: 1 mile = 1609.34 meters and 1 hour = 3600 seconds.Convert 100 mi/h: \[100 \text{ mi/h} \times \frac{1609.34 \text{ m}}{1 \text{ mile}} \times \frac{1 \text{ hour}}{3600 \text{ seconds}} = 44.70 \text{ m/s}\]
02

Calculate Mass

Convert the mass of the golf ball from ounces to kilograms. The conversion factor is: 1 ounce = 0.0283495 kilograms.Convert 1.62 oz:\[1.62 \text{ oz} \times 0.0283495 \text{ kg/oz} = 0.0459 \text{ kg}\]
03

Use Impulse-Momentum Theorem

The impulse-momentum theorem relates the impulse on an object to its change in momentum:\[F_{m} \Delta t = \Delta p = m \Delta v\] Substitute \(m = 0.0459 \text{ kg}\), \(\Delta v = 44.70 \text{ m/s}\), and \(\Delta t = 0.5 \times 10^{-3} \text{ s}\).
04

Expression for Force and Time

Given force function: \[F = F_{m} \sin\left(\frac{\pi t}{t_{0}}\right)\]The peak force occurs when \(\sin\left(\frac{\pi t}{t_{0}}\right) = 1\), meaning \(F = F_{m}\). We can use this to calculate \(F_{m}\).
05

Solve for Maximum Force \(F_m\)

Using impulse-momentum theorem:\[F_{m} \times \int_{0}^{t_0} \sin\left(\frac{\pi t}{t_0}\right) dt = \Delta p\]The integral of \(\sin\left(\frac{\pi t}{t_0}\right)\) over [0, \(t_0\)] is \(\frac{2}{\pi}t_0\). So:\[F_{m} \times \frac{2}{\pi} \times 0.5 \times 10^{-3} \text{ s} = 0.0459 \text{ kg} \times 44.70 \text{ m/s}\]Calculate for \(F_{m}\):\[F_{m} = \frac{0.0459 \times 44.70}{0.5 \times 10^{-3} \times \frac{2}{\pi}}\approx 6490 \text{ N}\]
06

Conclusion

The maximum force \(F_m\) exerted on the golf ball by the club is approximately 6490 N.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Impulse Calculation
The impulse-momentum theorem is a key concept in physics, which states that the change in momentum of an object is equal to the impulse applied to it. In mathematical terms, this is expressed as:
\[ F \cdot \Delta t = \Delta p \]where \( F \) is the average force applied, \( \Delta t \) is the time duration over which the force is applied, and \( \Delta p \) is the change in momentum.

To understand impulse, consider it as the effect of a force applied over a certain period of time. This concept is crucial when calculating how a force, such as a golf club's strike, affects an object like a golf ball. The impulse can be calculated by integrating the force function over the time interval of interest. Thus, knowing the force and the duration, you can determine how the velocity of the object changes, highlighting the interchange between force and motion.
Force Function Sinusoidal
In the given exercise, the force applied to the golf ball is represented by a sinusoidal function:
\[ F(t) = F_m \cdot \sin \left(\frac{\pi t}{t_0}\right) \]where \( F_m \) is the maximum force, \( t \) is the time, and \( t_0 \) is the total duration of the force application.

This sinusoidal pattern of the force is typical in many real-world situations where the force gradually increases, peaks, and then decreases. Think of a gentle push that gains intensity before slowly fading away. A sinusoidal function is useful as it smoothly transitions force values, making the calculation of the overall impact more realistic.

The maximum force, \( F_m \), is achieved when the sine factor is at its peak value of 1. This situation occurs at a certain instant during the impact. Understanding sinusoidal force helps us model real-world forces accurately and predict outcomes using mathematical analysis.
Momentum Change
Momentum is the product of an object's mass and velocity. A change in momentum, expressed as \( \Delta p \), represents how an object's motion is altered due to external forces. In the impulse-momentum theorem context, momentum change is the result of impulse applied over time:
\[ \Delta p = m \cdot \Delta v \]where \( m \) is the mass and \( \Delta v \) is the change in velocity.

In the golf ball exercise, the initial velocity is zero before the hit, making the change in velocity directly the final velocity. The momentum change can thus be calculated using the determined velocity from the units conversion section.

Recognizing how momentum changes allow us to understand the dynamics of an impact, such as how fast the golf ball will travel after being hit. Momentum conservation is a fundamental principle in both simple and complex physics problems.
Unit Conversion
Unit conversion is crucial in physics to ensure consistency and understanding of given measurements. In this exercise, several conversions are necessary:
  • Velocity from miles per hour to meters per second
  • Mass from ounces to kilograms
Understanding these conversions allows us to apply the correct units in our calculations, ensuring accuracy.

For velocity, use conversion factors like 1 mile equals 1609.34 meters and 1 hour equals 3600 seconds:
\[ 100 \text{ mi/h} \times \frac{1609.34 \text{ m}}{1 \text{ mile}} \times \frac{1 \text{ hour}}{3600 \text{ seconds}} = 44.70 \text{ m/s} \]

For mass, use the factor 1 ounce equals 0.0283495 kilograms:
\[ 1.62 \text{ oz} \times 0.0283495 \text{ kg/oz} = 0.0459 \text{ kg} \]

Once fully converted, these values can be seamlessly integrated into further calculations, making unit conversion a foundational step in problem-solving.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Collar \(A\) has a mass of \(3 \mathrm{kg}\) and is attached to a spring of constant \(1200 \mathrm{N} / \mathrm{m}\) and of undeformed length equal to \(0.5 \mathrm{m}\). The system is set in motion with \(r=0.3 \mathrm{m}, v_{\theta}=2 \mathrm{m} / \mathrm{s}\), and \(v_{r}=0 .\) Neglecting the mass of the rod and the effect of friction, determine \((a)\) the maximum distance between the origin and the collar, \((b)\) the corresponding speed. (Hint: Solve the equation obtained for \(r\) by trial and error.)

A 1.5 -lb ball that can slide on a horizontal frictionless surface is attached to a fixed point \(O\) by means of an elastic cord of constant \(k=1\) lb/in. and undeformed length 2 ft. The ball is placed at point \(A,\) 3 ft from \(O,\) and given an initial velocity \(v_{0}\) perpendicular to \(O A\). Determine ( \(a\) ) the smallest allowable value of the initial speed \(v_{0}\) if the cord is not to become slack, (b) the closest distance \(d\) that the ball will come to point \(O\) if it is given half the initial speed found in part \(a .\)

At an intersection, car \(B\) was traveling south and car \(A\) was traveling \(30^{\circ}\) north of east when they slammed into each other. Upon investigation it was found that after the crash the two cars got stuck and skidded off an angle of \(10^{\circ}\) north of east. Each driver claimed that he was going at the speed limit of \(50 \mathrm{km} / \mathrm{h}\) and that he tried to slow down but couldn’t avoid the crash because the other driver was going a lot faster. Knowing that the masses of cars A and B were 1500 kg and 1200 kg, respectively, determine (a) which car was going faster, (b) the speed of the faster of the two cars if the slower car was traveling at the speed limit.

A 35 000-Mg ocean liner has an initial velocity of 4 km/h. Neglecting the frictional resistance of the water, determine the time required to bring the liner to rest by using a single tugboat that exerts a constant force of 150 kN.

(a) Determine the kinetic energy per unit mass that a missile must have after being fired from the surface of the earth if it is to reach an infinite distance from the earth. (b) What is the initial velocity of the missile (called the escape velocity)? Give your answers in SI units and show that the answer to part b is independent of the firing angle.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.