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A satellite describes an elliptic orbit of minimum altitude 606 km above the surface of the earth. The semimajor and semiminor axes are 17 440 km and 13 950 km, respectively. Knowing that the speed of the satellite at point C is 4.78 km/s, determine (a) the speed at point A, the perigee, (b) the speed at point B, the apogee.

Short Answer

Expert verified
Speed at perigee: 10.67 km/s. Speed at apogee: 2.90 km/s.

Step by step solution

01

Identify given parameters

Identify the parameters given in the problem. The minimum altitude of the satellite, which is the distance from the Earth's surface to the perigee (point A), is 606 km. The semimajor axis is given as 17,440 km and the semiminor axis as 13,950 km. The speed at point C is 4.78 km/s.
02

Calculate the distance of perigee and apogee from Earth's center

Add Earth's radius (approximately 6,371 km) to the given altitude at the perigee to find the perigee distance \( r_A \). Thus, \( r_A = 6,371 \, \text{km} + 606 \, \text{km} = 6,977 \, \text{km} \). For the semimajor axis, the relationship \( a = \frac{r_A + r_B}{2} \) is used, where \( r_B \) is the distance to the apogee. Therefore, \( r_B = 2a - r_A = 34,880 \, \text{km} - 6,977 \, \text{km} = 27,903 \, \text{km} \).
03

Apply the Vis-viva equation

The Vis-viva equation is given by \( v^2 = GM \left(\frac{2}{r} - \frac{1}{a}\right) \), where \( GM \) is the Earth's standard gravitational parameter (\( 3.986 \times 10^{14} \, \text{m}^3/\text{s}^2 \)). Convert axes to meters: \( a = 17,440 \, \text{km} = 17,440,000 \, \text{m} \).
04

Determine speed at the perigee (Point A)

Convert \( r_A \) to meters: \( r_A = 6,977 \, \text{km} = 6,977,000 \, \text{m} \). Calculate speed using \( v_A^2 = GM \left( \frac{2}{r_A} - \frac{1}{a} \right) \). Substituting gives: \[ v_A^2 = 3.986 \times 10^{14} \left( \frac{2}{6,977,000} - \frac{1}{17,440,000} \right) \]. Solve for \( v_A \).
05

Determine speed at the apogee (Point B)

Convert \( r_B \) to meters: \( r_B = 27,903 \, \text{km} = 27,903,000 \, \text{m} \). Calculate speed using \( v_B^2 = GM \left( \frac{2}{r_B} - \frac{1}{a} \right) \). Substituting gives: \[ v_B^2 = 3.986 \times 10^{14} \left( \frac{2}{27,903,000} - \frac{1}{17,440,000} \right) \]. Solve for \( v_B \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Vis-viva Equation
The Vis-viva equation is an essential tool in satellite orbit mechanics, allowing us to determine a satellite's speed as it orbits around a celestial body, like the Earth. This equation provides the relationship between a satellite's velocity and its position in its orbit by taking into consideration gravitational forces.

The formal expression of the Vis-viva equation is:\[ v^2 = GM \left(\frac{2}{r} - \frac{1}{a}\right) \]
where:
  • \( v \) is the orbital speed of the satellite.
  • \( GM \) is the gravitational parameter of the celestial body, which in the case of Earth is approximately \( 3.986 \times 10^{14} \text{ m}^3/\text{s}^2 \).
  • \( r \) is the distance from the center of the Earth to the satellite at any point in its orbit.
  • \( a \) is the semi-major axis of the orbit, the orbit's "average" radius.
This equation is particularly useful because it simplifies the process of finding the speed of a satellite at different points in its orbit, showing how speed changes based on distance from the central body.
Elliptic Orbits
Elliptic orbits are one of the most common paths taken by satellites as they revolve around Earth. An elliptical orbit is defined as a closed curve resembling an oval, with varying distances from the central body over the course of a full orbit.

In such orbits, the path's shape and characteristics are determined by two main axes:
  • The **semi-major axis** \( a \), which is half of the longest diameter of the ellipse. It represents the "average" distance of the satellite from Earth.
  • The **semi-minor axis** \( b \), which is half of the shortest diameter.
These reference points define the orbit's size and shape.

An elliptic orbit follows Kepler's laws of planetary motion, which state that a satellite will move faster when it gets closer to the Earth (perigee) and slower when it's further away (apogee). This variation in speed is crucial for understanding satellite dynamics and is directly linked to the elliptical nature of the orbit itself.
Perigee and Apogee Speeds
Perigee and apogee are critical points of any elliptical orbit, marking the closest and farthest points from Earth, respectively.

- **Perigee (Point A):** This is where the satellite experiences its highest velocity. At perigee, the gravitational pull is strongest, pulling the satellite to its maximum speed. Using the Vis-viva equation, we can calculate this speed since the orbit's radius is at its minimum. - **Apogee (Point B):** In contrast, the satellite moves at its slowest around the apogee. The larger distance decreases gravitational influence, leading to a drop in velocity. Again, the Vis-viva equation is applied using the orbit’s maximum radius to find the speed here.

Understanding the difference in speeds is crucial because it dictates energy requirements for satellites performing orbital maneuvers. Operations like orbit changes or satellite deployment often happen by taking advantage of these speed differentials, ensuring efficient fuel use and accurate navigation.

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