/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 29 (a) An electron with initial kin... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

(a) An electron with initial kinetic energy \(32 \mathrm{eV}\) encounters a square barrier with height \(41 \mathrm{eV}\) and width \(0.25 \mathrm{nm}\). What is the probability that the electron will tunnel through the barrier? (b) A proton with the same kinetic energy encounters the same barrier. What is the probability that the proton will tunnel through the barrier?

Short Answer

Expert verified
The calculation yields that the electron has a significantly higher probability to tunnel through the barrier compared to the proton, due to its smaller mass. This disparity between the two particles is a consequence of the particle's mass being inversely proportional to the tunneling probability.

Step by step solution

01

Calculate the Energy Difference and Velocity

Calculate the energy difference between the barrier and the kinetic energy of the particle, \( \Delta E = E_{barrier}-E_{particle} = 41eV-32eV = 9eV \). Also, calculate the velocity, \( v = \sqrt{(2E_{particle})/m} \), for both particles using their respective masses (electron: \( m_e = 9.10938356 \times 10^{-31} kg \), proton: \( m_p = 1.67262192 \times 10^{-27} kg \)).
02

Calculate the Tunneling Probability

Use the formula for tunneling, \(T = e^{-2 \sqrt{(2m_a \Delta E)}w/h}\), where \(T\) is the tunneling probability, \(w\) is the width of the barrier, \( \Delta E \) is the energy difference, and \( h \) is the reduced Planck's constant. Compute \(T\) for both electron and proton.
03

Convert Units

Ensure all units are in the International System (SI) before performing the computation. For example, convert electric volt (eV) into Joules (J), express the width of the barrier in meters (m), and use the reduced Planck's constant in J.s.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinetic Energy
Kinetic energy is the energy that an object possesses due to its motion. In this context, we're looking at the kinetic energy of particles such as electrons and protons. The kinetic energy of a particle is given by the formula \( KE = \frac{1}{2}mv^2 \), where \( m \) is the mass of the particle and \( v \) is its velocity.
This property is crucial when discussing quantum tunneling because it helps determine the potential for a particle to overcome a barrier. For instance, in our exercise, the kinetic energy of each particle (electron and proton) is \(32 \mathrm{eV}\).
This initial energy partially dictates the probability of the particle being able to tunnel through a barrier that has a higher potential energy threshold.
Square Barrier
A square barrier refers to a potential energy barrier that has a constant height for a certain width. This means the particle will encounter the same amount of resistance across the barrier that it must "tunnel" through.
The square barrier in this problem has a height of \(41 \mathrm{eV}\) and a width of \(0.25 \mathrm{nm}\). These values set up the potential challenge an electron or proton would face when encountering the barrier.
Although the kinetic energy of the particles is less than the barrier height, quantum mechanics provides a mathematical framework to explore the possibility of tunneling through.
Tunneling Probability
Tunneling probability is the likelihood that a quantum particle will pass through a potential barrier that it classically would not be able to surpass due to its kinetic energy being lower than the barrier height.
We calculate this probability using the formula \( T = e^{-2 \sqrt{(2m \Delta E)}w/\hbar} \), where \( \Delta E \) is the energy difference between the barrier height and particle's kinetic energy, \( m \) is the particle's mass, \( w \) is the width of the barrier, and \( \hbar \) is the reduced Planck's constant.
This probability is exponentially dependent on the mass and energy difference, meaning lighter particles like electrons have a higher chance of tunneling than heavier particles like protons.
Differential Equations
Differential equations are a type of mathematical equation that involve functions and their derivatives. In quantum mechanics, these equations describe how quantum states change over time.
The Schrödinger equation is a fundamental differential equation used in quantum mechanics to determine the wave function of a quantum system.
For quantum tunneling, solving this equation under the potential barrier gives us the exponential decay form that leads to the tunneling probability. It provides insights into the behavior and characteristics of particles interacting with potential barriers, such as wave-like properties and probabilities.
Planck's Constant
Planck's constant \( h \) is a fundamental constant in physics that describes the quantization of physical properties. The reduced version, denoted as \( \hbar = \frac{h}{2\pi} \), frequently appears in quantum mechanics equations.
This constant is pivotal in determining the scale at which quantum effects become significant. In the exercise, it's used to calculate the tunneling probability of particles traveling through a barrier.
Planck's constant helps link the energy of particles to the frequency of their associated wave, thus, playing a critical role in understanding and calculating the quantum tunneling phenomena.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The penetration distance \(\eta\) in a finite potential well is the distance at which the wave function has decreased to \(1 / e\) of the (b) wave function at the classical turning point: $$ \psi(x=L+\eta)=\frac{1}{e} \psi(L) $$ The penetration distance can be shown to be $$\eta=\frac{\hbar}{\sqrt{2 m\left(U_{0}-E\right)}}$$ The probability of finding the particle beyond the penetration distance is nearly zero. (a) Find \(\eta\) for an electron having a kinetic energy of \(13 \mathrm{eV}\) in a potential well with \(U_{0}=20 \mathrm{eV} .\) (b) Find \(\eta\) for a \(20.0 \mathrm{MeV}\) proton trapped in a 30.0 -MeV-deep potential well.

When low-energy electrons pass through an ionized gas, electrons of certain energies pass through the gas as if the gas atoms weren't there and thus have transmission coefficients (tunneling probabilities) \(T\) equal to unity. The gas ions can be modeled approximately as a rectangular barrier. The value of \(T=1\) occurs when an integral or half-integral number of de Broglie wavelengths of the electron as it passes over the barrier equal the width \(L\) of the barrier. You are planning an experiment to measure this effect. To assist you in designing the necessary apparatus, you estimate the electron energies \(E\) that will result in \(T=1\). You assume a barrier height of \(10 \mathrm{eV}\) and a width of \(1.8 \times 10^{-10} \mathrm{~m} .\) Calculate the three lowest values of \(E\) for which \(T=1\)

A free particle moving in one dimension has wave function $$ \Psi(x, t)=A\left[e^{i(k x-\omega t)}-e^{i(2 k x-4 \omega t)}\right] $$ where \(k\) and \(\omega\) are positive real constants. (a) At \(t=0\) what are the two smallest positive values of \(x\) for which the probability function \(|\Psi(x, t)|^{2}\) is a maximum? (b) Repeat part (a) for time \(t=2 \pi / \omega .\) (c) Calculate \(v_{\text {av }}\) as the distance the maxima have moved divided by the elapsed time. Compare your result to the expression \(v_{\mathrm{av}}=\left(\omega_{2}-\omega_{1}\right) /\left(k_{2}-k_{1}\right)\) from Example 40.1

An electron with initial kinetic energy \(6.0 \mathrm{eV}\) encounters a barrier with height \(11.0 \mathrm{eV}\). What is the probability of tunneling if the width of the barrier is (a) \(0.80 \mathrm{nm}\) and (b) \(0.40 \mathrm{nm} ?\)

An electron is bound in a square well of width \(1.50 \mathrm{nm}\) and 40.25 depth \(U_{0}=6 E_{1-\mathrm{IDW}}\). If the electron is initially in the ground level and absorbs a photon, what maximum wavelength can the photon have and still liberate the electron from the well?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.