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Why is it easier to use helium ions rather than neutral helium atoms in such a microscope? (a) Helium atoms are not electrically charged, and only electrically charged particles have wave properties. (b) Helium atoms form molecules, which are too large to have wave properties. (c) Neutral helium atoms are more difficult to focus with electric and magnetic fields. (d) Helium atoms have much larger mass than helium ions do and thus are more difficult to accelerate.

Short Answer

Expert verified
(c) Neutral helium atoms are more difficult to focus with electric and magnetic fields.

Step by step solution

01

Analyze statement (a)

Helium atoms are indeed neutrally charged, however, the statement that only electrically charged particles have wave properties is incorrect. Both charged and neutral particles can exhibit wave-like properties as per the de Broglie wavelength.
02

Analyze statement (b)

Helium atoms do not generally form molecules under standard conditions. As one of the noble gases, it is virtually inert and does not readily form compounds. Moreover, the size of a particle does not affect its wave properties.
03

Analyze statement (c)

This statement is correct. Neutral helium atoms are more difficult to focus using electromagnetic fields compared to helium ions. This is due to the fact that electric and magnetic fields primarily interact with charged particles, allowing for more precise manipulation of their trajectories.
04

Analyze statement (d)

The mass of a helium ion is indeed slightly less than that of a helium atom. However, the difference is not great enough to significantly impact the ease with which these particles can be accelerated.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

De Broglie Wavelength
One of the monumentally significant concepts in quantum physics is that particles can exhibit both wave-like and particle-like properties. This was beautifully encapsulated in the de Broglie hypothesis, named after French physicist Louis de Broglie. He proposed that any particle with momentum, not just light, has an associated wavelength—this is known as the de Broglie wavelength. It's defined by the equation \( \lambda = \frac{h}{p} \), where \( \lambda \) is the wavelength, \( h \) is Planck's constant, and \( p \) is the linear momentum of the particle.

In the context of the exercise, although both helium atoms and ions exhibit wave attributes, ions can be easily manipulated using electromagnetism due to their charge. Charges are central to many technologies, like the microscope mentioned in the exercise. To understand why charge matters, consider that the manipulation of charged particles with electric and magnetic fields is more straightforward, translating to finer control over the particle's trajectory compared to neutral atoms, which lack this convenience.
Electromagnetic Field Manipulation
Electromagnetic fields are an integral part of our daily technology, from MRI machines to particle accelerators. When we talk about electromagnetic field manipulation, it usually entails the use of an electric field, a magnetic field, or a combination of both to control the motion of charged particles. This manipulation comes from the Lorentz force, where a charged particle experiences a force in the presence of these fields.

The ability to manipulate a particle's path is essential in numerous scientific instruments and industrial applications. In the microscope scenario presented, focusing a beam of particles is crucial for achieving high-resolution images. Charged particles, such as helium ions, can be subjected to electric and magnetic fields that can precisely adjust their course, whereas neutral helium atoms lack this level of controllability. This underlines the importance of using charged particles for better precision in instruments that require the steering and focusing of particle beams.
Charged Particles
Charged particles are fundamental components of the universe, playing a pivotal role in chemistry, physics, and biology. A charged particle is an atomic or subatomic particle with an electric charge, positive or negative. Common examples of charged particles include ions, protons, and electrons. These particles are especially important in research and technology because their electrical charge allows for interaction with electromagnetic fields.

A better understanding of charged particles not only enlightens us about atomic structures and chemical reactions but also equips us to develop advanced technologies. For instance, helium ions can be used in microscopy because they respond effectively to electromagnetic fields, allowing for finer control over the imaging process. This responsiveness to electric and magnetic fields is a key reason why charged particles are so valuable in precision technologies where manipulating their trajectory is essential.

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Most popular questions from this chapter

\(\mathrm{CP}\) The moon has a mass of \(7.35 \times 10^{22} \mathrm{~kg}\), and the length of a sidereal day is 27.3 days. (a) Estimate the de Broglie wavelength of the moon in its orbit around the earth. (b) Using \(M_{\text {earth }}\) for the mass of the earth and \(M_{\text {moon }}\) for the mass of the moon, we can use Newton's law of gravitation to determine the radius of the moon's orbit in terms of an integer-valued quantum number \(m\) as \(R_{m}=m^{2} a_{\text {moon }},\) where \(a_{\text {moon }}\) is the analog of the Bohr radius for the earth-moon gravitational system. Determine \(a_{\text {moon }}\) in terms of Newton's constant \(G,\) Planck's constant \(h,\) and the masses \(M_{\text {earth }}\) and \(M_{\text {moon }}\) (c) The mass of the earth is \(M_{\text {earth }}=5.97 \times 10^{24} \mathrm{~kg} .\) Estimate the numerical value of \(a_{\mathrm{moon}}\) (d) The radius of the moon's orbit is \(3.84 \times 10^{8} \mathrm{~m}\). Estimate the moon's quantum number \(m\). (e) The quantized energy levels of the moon are given by \(E=-E_{0} / m^{2}\). Estimate the quantum ground-state energy \(E_{0}\) of the moon.

A \(10.0 \mathrm{~g}\) marble is gently placed on a horizontal tabletop that is \(1,75 \mathrm{~m}\) wide. (a) What is the maximum uncertainty in the horizontal position of the marble? (b) According to the Heisenberg uncertainty principle, what is the minimum uncertainty in the horizontal velocity of the marble? (c) In light of your answer to part (b), what is the longest time the marble could remain on the table? Compare this time to the age of the universe, which is approximately 14 billion years. (Hint: Can you know that the horizontal velocity of the marble is exactly zero?)

Two stars, both of which behave like ideal blackbodies, radiate the same total energy per second. The cooler one has a surface temperature \(T\) and a diameter 3.0 times that of the hotter star. (a) What is the temperature of the hotter star in terms of \(T ?\) (b) What is the ratio of the peak-intensity wavelength of the hot star to the peak-intensity wavelength of the cool star?

CP Light from an ideal spherical black body \(15.0 \mathrm{~cm}\) in diameter is analyzed by using a diffraction grating that has 3850 lines/cm. When you shine this light through the grating. you observe that the peak-intensity wavelength forms a first-order bright fringe at \(\pm 14.4^{\circ}\) from the central bright fringe. (a) What is the temperature of the black body? (b) How long will it take this sphere to radiate \(12.0 \mathrm{MJ}\) of energy at constant temperature?

CP An alpha particle is incident with kinetic energy \(K\) on a gold nucleus at rest. The aim is direct. (a) If \(m\) is the mass of an alpha particle and \(M\) is the mass of a gold nucleus, solve the classical conditions for energy and momentum conservation to determine the recoil speed \(V\) of the nucleus after the collision. (b) Determine an expression for the fractional energy lost to the nucleus. (c) Is your result independent of the initial kinetic energy? (d) An alpha particle has mass \(m=6.64 \times 10^{-27} \mathrm{~kg},\) and a gold nucleus has mass \(M=1.32 \times 10^{-25} \mathrm{~kg}\) If \(K=5.00 \mathrm{MeV},\) then what is the speed \(V\) as a fraction of \(c,\) and what proportion of the original energy is transferred to the gold nucleus? (e) According to the classical analysis, what speed of the incident alpha particle would result in a nuclear speed \(V\) of \(0.10 \mathrm{c} ?\) (f) Is that possible?

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