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Can the first type of helium-ion microscope, used for surface imaging. produce helium ions with a wavelength of \(0.1 \mathrm{pm} ?\) (a) Yes; the voltage required is \(21 \mathrm{kV}\). (b) Yes; the voltage required is \(42 \mathrm{kV}\). (c) No; a voltage higher than \(50 \mathrm{kV}\) is required. (d) No; a voltage lower than \(10 \mathrm{kV}\) is required.

Short Answer

Expert verified
The required voltage to get a wavelength of \( 0.1 \, pm \) is closer to \( 42 \, kV \). Thus, the correct answer is (b) Yes; the voltage required is \( 42 \, kV \).

Step by step solution

01

Identify Given Parameters

The wavelength given is \( \lambda = 0.1 \, pm \) and the charge of helium ion is the same as the electron charge \( e = 1.6 \times 10^{-19} \, C \)
02

Use De Broglie's Equation

Place the values into the De Broglie's equation to find the velocity: \(v = \frac{h}{m \lambda} \) where \( h = 6.63 \times 10^{-34} \, Js \) is the Planck's constant and \( m \) is the rest mass of a helium ion. The rest mass of a helium nucleus can be calculated from the mass of a helium atom \( 4 \, amu \) after subtracting the mass of two electrons.
03

Obtain Kinetic Energy

Now, express the kinetic energy (KE) in terms of \( v = \sqrt{\frac{2(KE)}{m}} \) and equate that velocity to the velocity obtained from the De Broglie's equation.
04

Obtain Required Voltage

The kinetic energy can be related back to the voltage applied by using the equation \( KE = eV \), where \( V \) is the voltage applied. Solve for \( V \) to get the required voltage.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

De Broglie's Equation
De Broglie's equation is a fundamental concept that bridges the gap between wave and particle nature, and it plays a significant role in the field of quantum mechanics. This equation relates the wavelength of a particle to its momentum and is given by: \[ \lambda = \frac{h}{p} \] where \( \lambda \) is the wavelength, \( h \) is Planck's constant \( (6.63 \times 10^{-34} \, \text{Js}) \), and \( p \) is the momentum of the particle. To calculate momentum, we use the formula \( p = mv \), where \( m \) is the mass and \( v \) is the velocity of the particle. Therefore, substituting in, the equation becomes: \[ \lambda = \frac{h}{mv} \] This concept is especially crucial for analyzing particles at quantum scales, such as helium ions in a helium-ion microscope, where wavelengths can affect the precision and quality of imaging.
Wavelength and Voltage Relationship
Understanding the relationship between wavelength and voltage is vital for applying De Broglie's equation in practical scenarios, like determining if a helium-ion microscope can produce helium ions at a specific wavelength. To find the necessary voltage for a desired ion wavelength, we first determine the velocity using De Broglie's equation: \[ v = \frac{h}{m \lambda} \] Given a specific wavelength as a target, we can find the velocity needed. This velocity can then be linked to kinetic energy (KE) through the expression: \[ KE = \frac{1}{2} mv^2 \] Since kinetic energy is directly related to the applied voltage \( V \) by the equation: \( KE = eV \), where \( e \) is the electron charge, we can solve for V: \[ V = \frac{1}{2} \frac{mv^2}{e} \] Thus, we connect the dots from wavelength to required voltage, providing insights into the energy needs for manipulating helium ions in a microscope.
Kinetic Energy and Voltage
The concepts of kinetic energy and voltage are intertwined in the realm of particle physics and are particularly relevant to the functioning of devices like helium-ion microscopes. Kinetic energy (KE) is the energy that a particle like a helium ion possesses due to its motion, and is given by the formula: \[ KE = \frac{1}{2} mv^2 \] In contexts where particles are accelerated through a potential difference (voltage), the kinetic energy gained can be directly related to the voltage. The equation that describes this relationship is: \[ KE = eV \] Where \( e \) is the electron charge and \( V \) is the applied voltage.
  • If you know the kinetic energy that a particle needs to achieve a specific velocity, you can easily find the voltage required using the relationship \( V = \frac{KE}{e} \).
  • This helps in determining the proper energy conditions when using instruments like helium-ion microscopes for imaging at specific wavelengths.
This relationship simplifies the process of finding out what voltage should be used in practical applications.
Electron Charge and Helium Ion
Electron charge and helium ions are crucial concepts to consider when discussing the behavior of particles in devices like microscopes. A helium ion is essentially a helium atom that has lost its electrons, gaining a positive charge equal to that of an electron but opposite in sign. Therefore, the charge of a helium ion can be described as:- The magnitude of the charge \( e = 1.6 \times 10^{-19} \text{ C} \), identical in magnitude to the electron but positive.- Helium ions, being heavier than electrons, possess a greater rest mass, which influences their dynamics when accelerated by an electric field.In the context of a helium-ion microscope, understanding this charge helps determine the particle's trajectory and wavelength. This is because only charged particles can be manipulated using electric and magnetic fields, thereby enabling their application in precise imaging tasks.
Helium ions, due to their charge and mass, provide certain advantages in imaging, such as higher precision and resolution, because their trajectories can be accurately controlled with the required voltage.

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