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An electron is in a bound state of a hydrogen atom. The energy state of the atom is labeled with principal quantum number \(n .\) In the Bohr model description of this bound state, the electron has linear momentum \(p=6.65 \times 10^{-25} \mathrm{~kg} \cdot \mathrm{m} / \mathrm{s} .\) In the Bohr model description. what are (a) the kinetic energy of the electron, (b) the angular momentum of the electron, and (c) the quantum number \(n ?\)

Short Answer

Expert verified
The kinetic energy, angular momentum, and principal quantum number of the electron according to the Bohr's model are calculated based on the given linear momentum and known physical constants. These require application of the concepts and formulas from classical mechanics and quantum mechanics.

Step by step solution

01

Calculate the Kinetic Energy

According to classical mechanics, the kinetic energy (K) of the electron can be calculated using its linear momentum \(p\) with the formula: \[K = \frac{{p^2}}{{2m}}\]where \(m\) is the mass of the electron. Plug in the given values for \(p\) and the known value for the mass of an electron \(9.11 \times 10^{-31} \, \mathrm{kg}\) into the formula and calculate the kinetic energy.
02

Calculate the Angular Momentum

According to the Bohr's model, the angular momentum \(L\) of the electron is given by \[L = n\hbar\]where \(\hbar\) is the reduced Planck constant and has a value of \(1.0545718 \times 10^{-34} \, \mathrm{m^2kg/s}\). The quantum number \(n\) can be determined by associating the angular momentum to the linear momentum through a geometric reasoning in Bohr's model. Thus, we have:\[L = mvr = p.r\]By associating the two formulas the quantum number \(n\) can be calculated substituting the known values into the formula.
03

Determine the Quantum Number \(n\)

The formula obtained in Step 2 leads to:\[n = \frac{{p.r}}{{\hbar}}\]The value of the radius \(r\) in Bohr's atom model corresponds to \(r = \frac{{n^2\hbar^2}}{{m.ke^2}}\), where \(k\) is the Coulomb constant and \(e\) is the elementary charge. The quantum number \(n\) can be solved as a solution of a resultant non-linear equality from the substitution of \(r\) in the previous formula.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinetic Energy of Electron
The kinetic energy of an electron within an atom is a crucial concept to grasp when studying the Bohr model of the hydrogen atom. It describes the energy that the electron possesses due to its motion. In classical mechanics, the kinetic energy is calculated as \( \frac{p^2}{2m} \) where \( p \) is the linear momentum of the electron, and \( m \) is its mass. An electron moving around the nucleus in a hydrogen atom has a specific kinetic energy related to its orbit.

By applying the provided momentum value \( 6.65 \times 10^{-25} \, \text{kg} \cdot \text{m/s} \) and the electron mass \( 9.11 \times 10^{-31} \, \text{kg} \) into this formula, you can determine the kinetic energy for the electron in its orbit. This calculation holds true within the framework of the Bohr model, offering a simplified way to understand an electron's behavior at the quantum level, which is more adequately described by quantum mechanics.
Angular Momentum of Electron
The angular momentum of the electron is a fundamental concept in both classical mechanics and quantum mechanics. In the context of the Bohr model, angular momentum is quantized, meaning it can only take on specific discrete values. Bohr postulated that the angular momentum of an electron is an integer multiple of \( \hbar \) (the reduced Planck constant), where \( n \) is the principal quantum number.

Thus, \( L = n\hbar \), which signifies the direct relationship between the angular momentum and the electron's allowed energy levels (which are indexed by the quantum number \( n \) ). This was a revolutionary step in understanding atomic structure, as it diverged from classical expectations by suggesting that not all orbits are permissible—only those that satisfy this quantization condition.
Principal Quantum Number
The principal quantum number \( n \) is integral to the Bohr model and quantum mechanics as it dictates the size and energy of the electron's orbit in a hydrogen atom. It's an integer that can be any positive value, and each value corresponds to a different energy level or shell.

In the given exercise, the principal quantum number can be determined through the relationship between the electron's linear momentum and its angular momentum. Using the formulas from the steps, the principal quantum number is isolated, and its value can be determined mathematically. The larger the principal quantum number, the higher the energy level and the further the electron is from the nucleus. This concept, introduced in the Bohr model, laid the early groundwork for the complex quantum mechanical models that followed.
Quantum Mechanics
Quantum mechanics is the branch of physics that deals with the behavior of particles at the atomic and subatomic levels. Unlike classical mechanics, quantum mechanics recognizes that on the very small scales, energy and properties like the angular momentum of particles like electrons cannot vary smoothly, but instead exist in discrete 'quanta'.

The groundbreaking Bohr model of the hydrogen atom was an early quantum mechanical model that included quantized angular momentum and energy levels. Although it has since been replaced by more complex and accurate quantum mechanical models, the Bohr model still offers valuable insights into the quantum realm. It introduces the concept of quantization, which has become the cornerstone of modern quantum mechanics, helping to explain complex phenomena like electron orbitals, the shapes of molecules, and the behavior of photons.

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Most popular questions from this chapter

The wavelengths \(\lambda\) in the Pickering emission series are given by \(\frac{1}{\lambda}=\left(1.097 \times 10^{7} \mathrm{~m}^{-1}\right)\left[\frac{1}{4}-\frac{1}{(n / 2)^{2}}\right]\) for \(n=5,6,7, \ldots\) and were at- tributed to hydrogen by some scientists. However, Bohr realized that this was not a hydrogen series, but rather belonged to another element, ionized so that it has only one electron. (a) What are the shortest and longest wavelengths in the Pickering series? (b) Which element gives rise to this series, and what is the common final-state quantum number \(n_{\mathrm{L}}\) for each transition in the series?

Wavelength of an Alpha Particle. An alpha particle \(\left(m=6.64 \times 10^{-27} \mathrm{~kg}\right)\) emitted in the radioactive decay of uranium- 238 has an energy of \(4.20 \mathrm{MeV}\). What is its de Broglie wavelength?

(a) A nonrelativistic free particle with mass \(m\) has kinetic energy \(K\). Derive an expression for the de Broglie wavelength of the particle in terms of \(m\) and \(K\). (b) What is the de Broglie wavelength of an \(800 \mathrm{eV}\) electron?

In the second type of helium-ion microscope, a \(1.2 \mathrm{MeV}\) ion passing through a cell loses \(0.2 \mathrm{MeV}\) per \(\mu \mathrm{m}\) of cell thickness. If the energy of the ion can be measured to \(6 \mathrm{keV},\) what is the smallest difference in thickness that can be discemed? (a) \(0.03 \mu \mathrm{m}\) (b) \(0.06 \mu \mathrm{m}\) (c) \(3 \mu \mathrm{m} ;\) (d) \(6 \mu \mathrm{m}\)

(a) The \(x\) -coordinate of an electron is measured with an uncertainty of \(0.30 \mathrm{~mm}\). What is the \(x\) -component of the electron's velocity, \(v_{x},\) if the minimum percent uncertainty in a simultaneous measurement of \(v_{x}\) is \(1.0 \% ?\) (b) Repeat part (a) for a proton.

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