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Two stars, both of which behave like ideal blackbodies, radiate the same total energy per second. The cooler one has a surface temperature \(T\) and a diameter 3.0 times that of the hotter star. (a) What is the temperature of the hotter star in terms of \(T ?\) (b) What is the ratio of the peak-intensity wavelength of the hot star to the peak-intensity wavelength of the cool star?

Short Answer

Expert verified
The temperature of the hotter star is three times that of the cooler star, or \(3T\). The ratio of the peak-intensity wavelength of the hot star to the cool star is \(\frac{1}{3}\).

Step by step solution

01

Establish Stefan-Boltzmann Law equation

Given that both stars radiate the same total energy per second and the diameter of the cooler star is 3.0 times that of the hotter star, the Stefan-Boltzmann Law can be used to formulate the equation \[E_{hot}=E_{cool}\] which simplifies to \[\sigma T_{hot}^4 A_{hot} = \sigma T_{cool}^4 A_{cool}\]. Since area \(A\) is proportional to the square of the diameter \(d\), the equation can be expressed as \[T_{hot}^4 d_{hot}^2 = T_{cool}^4 d_{cool}^2\].
02

Solve for the temperature of the hot star

Given that the diameter of the cooler star is three times that of the hotter star, we substitute \(d_{cool}\) as \(3d_{hot}\). This gives us \[T_{hot}^4 d_{hot}^2 = T_{cool}^4 (3d_{hot})^2\] which simplifies to \[T_{hot}^4 = 9 T_{cool}^4\]. Taking the fourth root on each side we find that \[T_{hot} = 3T_{cool}\].
03

Apply Wien's law to find the ratio of peak-intensity wavelength

Wien's law states that the peak wavelength is inversely proportional to the temperature of the black object. Express this relationship as \[λ_{peak, hot}= λ_{peak, cool} \frac{T_{cool}}{T_{hot}}\]. Substitute \(T_{hot} = 3T_{cool}\) to find that \[λ_{peak, hot}= λ_{peak, cool} \frac{1}{3}\]. Hence, the ratio of the peak-intensity wavelength of the hot star to the peak-intensity wavelength of the cool star is 1/3.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Blackbody Radiation
Blackbody radiation refers to the hypothetical concept of a body that absorbs all incident electromagnetic radiation, regardless of frequency or angle of incidence, and radiates energy in a characteristic spectrum. This idealized model is important in physics as it emits radiation known as blackbody radiation. A good real-world approximation to this model is the radiation from stars, which helps astronomers understand their properties. The radiation emitted covers a range of wavelengths and can be predicted by Planck's radiation law. The Stefan-Boltzmann Law, which was used in the solution of the given exercise, describes the power radiated per unit area of a blackbody and is directly proportional to the fourth power of the blackbody's temperature. This law can be expressed mathematically as:

\[ P = \text{Stefan-Boltzmann constant} (\text{\(\text{\(sigma\)}\)}) \times T^4 \]
Here, \( P \) is the radiative power per unit area, \( \text{\(\text{\(sigma\)}\)} \) is the Stefan-Boltzmann constant, and \( T \) is the absolute temperature of the blackbody in Kelvin. The law is foundational in understanding how much energy stars, like our own sun, radiate into space.
Wien's Law
Wien's Law is a principle that provides a relationship between the peak wavelength of radiation emitted by a blackbody and its temperature. It states that the peak wavelength is inversely proportional to the temperature, meaning that hotter objects will emit light at shorter wavelengths and thus appear bluer, while cooler objects emit at longer wavelengths, appearing redder.

In a mathematical form, Wien's Law is:
\[ \text{\( \text{λ}_{peak} \)} \times T = \text{Wien's displacement constant (b)} \]
Where \( \text{\( \text{λ}_{peak} \)} \) is the peak wavelength, \( T \) is the absolute temperature, and \( b \) is a constant of proportionality called Wien's displacement constant. Wien's Law was leveraged in Step 3 of the exercise solution to find the ratio of the peak-intensity wavelengths of the hot and cool stars. The law is particularly useful for astrophysics and cosmology, as it helps determine the surface temperatures of stars by analyzing the spectra of the light they emit.
Surface Temperature of Stars
The surface temperature of stars is a fundamental characteristic that astronomers use to classify and understand their evolution, composition, and distance. This temperature can be determined by studying the spectrum of light a star emits, which is related to blackbody radiation. When astronomers measure a star's spectrum, they can use Wien's Law to relate the color of the star (the peak wavelength) to its surface temperature.

For instance, in the provided exercise, determining the temperature of the hotter star involved using the Stefan-Boltzmann Law and the concept of blackbody radiation. Knowing the diameter and temperature of one star, and the fact that both stars radiate the same total energy, allowed for the computation of the hotter star's temperature. This calculation is crucial because the temperature affects not only the star's color but also its lifecycle and the types of astronomical phenomena associated with it, such as the type of planets that might orbit it and the likelihood of habitable conditions on those planets.

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Most popular questions from this chapter

CP An alpha particle is incident with kinetic energy \(K\) on a gold nucleus at rest. The aim is direct. (a) If \(m\) is the mass of an alpha particle and \(M\) is the mass of a gold nucleus, solve the classical conditions for energy and momentum conservation to determine the recoil speed \(V\) of the nucleus after the collision. (b) Determine an expression for the fractional energy lost to the nucleus. (c) Is your result independent of the initial kinetic energy? (d) An alpha particle has mass \(m=6.64 \times 10^{-27} \mathrm{~kg},\) and a gold nucleus has mass \(M=1.32 \times 10^{-25} \mathrm{~kg}\) If \(K=5.00 \mathrm{MeV},\) then what is the speed \(V\) as a fraction of \(c,\) and what proportion of the original energy is transferred to the gold nucleus? (e) According to the classical analysis, what speed of the incident alpha particle would result in a nuclear speed \(V\) of \(0.10 \mathrm{c} ?\) (f) Is that possible?

A \(10.0 \mathrm{~g}\) marble is gently placed on a horizontal tabletop that is \(1,75 \mathrm{~m}\) wide. (a) What is the maximum uncertainty in the horizontal position of the marble? (b) According to the Heisenberg uncertainty principle, what is the minimum uncertainty in the horizontal velocity of the marble? (c) In light of your answer to part (b), what is the longest time the marble could remain on the table? Compare this time to the age of the universe, which is approximately 14 billion years. (Hint: Can you know that the horizontal velocity of the marble is exactly zero?)

A photon and a free electron each have an energy of \(6.00 \mathrm{eV}\). (a) What is the wavelength of the photon if it is traveling in air? (b) What is the de Broglie wavelength of the electron? (c) Which wavelength is longer?

The wavelengths \(\lambda\) in the Pickering emission series are given by \(\frac{1}{\lambda}=\left(1.097 \times 10^{7} \mathrm{~m}^{-1}\right)\left[\frac{1}{4}-\frac{1}{(n / 2)^{2}}\right]\) for \(n=5,6,7, \ldots\) and were at- tributed to hydrogen by some scientists. However, Bohr realized that this was not a hydrogen series, but rather belonged to another element, ionized so that it has only one electron. (a) What are the shortest and longest wavelengths in the Pickering series? (b) Which element gives rise to this series, and what is the common final-state quantum number \(n_{\mathrm{L}}\) for each transition in the series?

A beam of alpha particles is incident on a target of lead. A particular alpha particle comes in "head-on" to a particular lead nucleus and stops \(6.50 \times 10^{-14} \mathrm{~m}\) away from the center of the nucleus. (This point is well outside the nucleus.) Assume that the lead nucleus, which has 82 protons, remains at rest. The mass of the alpha particle is \(6.64 \times 10^{-27} \mathrm{~kg} .\) (a) Calculate the electrostatic potential energy at the instant that the alpha particle stops. Express your result in joules and in \(\mathrm{MeV}\). (b) What initial kinetic energy (in joules and in MeV) did the alpha particle have? (c) What was the initial speed of the alpha particle?

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