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One of the wavelengths of light emitted by hydrogen atoms under normal laboratory conditions is \(\lambda=656.3 \mathrm{nm},\) in the red portion of the electromagnetic spectrum. In the light emitted from a distant galaxy this same spectral line is observed to be Doppler-shifted to \(\lambda=953.4 \mathrm{nm},\) in the infrared portion of the spectrum. How fast are the emitting atoms moving relative to the earth? Are they approaching the earth or receding from it?

Short Answer

Expert verified
The emitting atoms are moving at approximately 1.35 * 10^8 m/s relative to Earth, moving away from it.

Step by step solution

01

Use the Redshift formula

The redshift formula relates the observed wavelength \(\lambda\), the rest wavelength \(\lambda_0\), and the relative speed \(v\) of the source using the formula: \[ z = \frac{\Delta\lambda}{\lambda_0} = \frac{\lambda - \lambda_0}{\lambda_0} = \frac{v}{c}\], where: \(\Delta\lambda\) is the change in wavelength, \(v\) is the speed of the source, and \(c\) is the speed of light.
02

Compute for relative speed

Insert the given values \(\lambda\) = 953.4 nm, \(\lambda_0\) = 656.3 nm, and \(c\) = 3 * 10^8 m/s into the equation to calculate \(v\). \[ v = zc = \frac{\lambda - \lambda_0}{\lambda_0} * c \]
03

Determine the direction of motion

If the spectral line is redshifted (i.e., shifted to a longer wavelength), the galaxy is receding from us. If it were blueshifted (shifted to a shorter wavelength), it would be approaching us.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Redshift
In astronomy, redshift is a crucial concept used to determine how objects in space are moving in relation to us here on Earth. When we say that something is 'redshifted,' it means that the light emitted by that object has moved towards the red end of the spectrum. This shift happens when an object, like a galaxy or a star, moves away from us. The greater the shift towards red, the faster the object is receding. This concept is significant because it allows astronomers to measure how the universe is expanding. When distant galaxies show redshift, it indicates they are moving away. This discovery has been a fundamental piece of evidence for the Big Bang theory and the ongoing expansion of the universe. For students trying to understand redshift, remember:
  • Redshift equals longer wavelengths.
  • Redshift indicates objects moving away.
  • The shift magnitude helps calculate speed and distance.
Spectral Line
A spectral line is like a fingerprint for atoms and molecules. Each type of atom emits and absorbs light at specific wavelengths. These wavelengths appear as lines in a spectrum and are unique for each element. For instance, hydrogen emits light at a precise wavelength of 656.3 nanometers in normal conditions. This is in the red part of the spectrum. When observing distant galaxies, their spectral lines shift. This shift helps scientists understand various cosmic phenomena, such as star formation, black holes, and dark matter density. The spectral lines can be shifted due to pressure, temperature, or because objects are moving due to the Doppler effect. Recognizing these lines helps scientists study the universe's chemical composition and the physical conditions of celestial objects. In essence, spectral lines:
  • Act as unique identifiers for elements.
  • Show shifts due to movement or environmental changes.
  • Help in analyzing cosmic conditions and compositions.
Relative Speed Calculation
Calculating the relative speed of objects in space, like galaxies, is possible by using the redshift data. The relationship between redshift and velocity is given by the formula:\[ z = \frac{\Delta\lambda}{\lambda_0} = \frac{v}{c} \]Where:
  • \( z \) is the redshift,
  • \( \Delta\lambda \) = change in wavelength,
  • \( \lambda_0 \) = original wavelength,
  • \( v \) = relative speed of the galaxy,
  • \( c \) = speed of light.
To compute the speed, we rearrange the formula to calculate \( v \):\[ v = zc = \frac{\lambda - \lambda_0}{\lambda_0} \times c \]Here, the observed wavelength \( \lambda \) is compared to the original wavelength \( \lambda_0 \) to find the shift \( \Delta\lambda \). With this shift and knowing the speed of light \( c \), we can determine how fast an object like a galaxy is moving relative to us. This method helps in understanding not just motion, but also the nature of the universe's expansion.

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Most popular questions from this chapter

The net force \(\vec{F}\) on a particle of mass \(m\) is directed at \(30.0^{\circ}\) counterclockwise from the \(+x\) -axis. At one instant of time, the particle is traveling in the \(+x\) -direction with a speed (measured relative to the earth) of \(0.700 c .\) At this instant, what is the direction of the particle's acceleration?

One way to strictly enforce a speed limit would be to alter the laws of nature. Suppose the speed of light were \(65 \mathrm{mph}\) and your workplace was 30 miles from your home. Assume you travel to work at a typical driving speed of 60 mph. (a) If you drove at that speed for the round trip to and from work, light, how much would your wristwatch lag your kitchen clock each day? (b) Estimate the length of your car. (c) If you were driving at your estimated driving speed, how long would your car be when viewed from the roadside? (d) What would be the speed relative to you of similar cars traveling toward you in the opposite lane with the same ground speed as you? (e) How long would you measure those cars to be? (f) If the total mass of you and your car was \(2000 \mathrm{~kg}\), how much work would be required to get you up to speed? (Note: Your rest mass energy in this world is \(m c^{2}\), where \(c=65\) mph. ) (g) How much work would be required in the real world, where the speed of light is \(3.0 \times 10^{8} \mathrm{~m} / \mathrm{s},\) to get you up to speed?

Tell It to the Judge. (a) How fast must you be approaching a red traffic light \((\lambda=675 \mathrm{nm})\) for it to appear yellow \((\lambda=575 \mathrm{nm}) ?\) Express your answer in terms of the speed of light. (b) If you used this as a reason not to get a ticket for running a red light, how much of a fine would you get for speeding? Assume that the fine is \(\$ 1.00\) for each kilometer per hour that your speed exceeds the posted limit of \(90 \mathrm{~km} / \mathrm{h}\).

You are a scientist studying small aerosol particles that are contained in a vacuum chamber. The particles carry a net charge, and you use a uniform electric field to exert a constant force of \(8.00 \times 10^{-14} \mathrm{~N}\) on one of them. That particle moves in the direction of the exerted force. Your instruments measure the acceleration of the particle as a function of its speed \(v .\) The table gives the results of your measurements for this particular particle. $$ \begin{array}{l|cccccc} \boldsymbol{v} / \boldsymbol{c} & 0.60 & 0.65 & 0.70 & 0.75 & 0.80 & 0.85 \\ \hline \boldsymbol{a}\left(\mathbf{1 0}^{\mathbf{3}} \mathbf{m} / \mathbf{s}^{\mathbf{2}}\right) & 20.3 & 17.9 & 14.8 & 11.2 & 8.5 & 5.9 \end{array} $$ (a) Graph your data so that the data points are well fit by a straight line. Use the slope of this line to calculate the mass \(m\) of the particle. (b) What magnitude of acceleration does the exerted force produce if the speed of the particle is \(100 \mathrm{~m} / \mathrm{s} ?\)

Electrons are accelerated through a potential difference of \(750 \mathrm{kV},\) so that their kinetic energy is \(7.50 \times 10^{5} \mathrm{eV}\). (a) What is the ratio of the speed \(v\) of an electron having this energy to the speed of light, \(c ?\) (b) What would the speed be if it were computed from the principles of classical mechanics?

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