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Tell It to the Judge. (a) How fast must you be approaching a red traffic light \((\lambda=675 \mathrm{nm})\) for it to appear yellow \((\lambda=575 \mathrm{nm}) ?\) Express your answer in terms of the speed of light. (b) If you used this as a reason not to get a ticket for running a red light, how much of a fine would you get for speeding? Assume that the fine is \(\$ 1.00\) for each kilometer per hour that your speed exceeds the posted limit of \(90 \mathrm{~km} / \mathrm{h}\).

Short Answer

Expert verified
Part (a), you would need to be travelling at approximately \(0.176c\) towards the light for it to appear yellow. Part (b), you would receive a fine for roughly $6300 for exceeding speed limits, thereby avoiding a ticket for running a red light.

Step by step solution

01

Recall Doppler Formula

Firstly, we need to remember the formula to calculate Doppler shift for light. This formula is \(v = c \cdot \((\frac{\lambda_o}{\lambda_s}) - 1\)\), where \(v\) is the observer's velocity, \(c\) is the speed of light, \(\lambda_o\) is the observed wavelength, and \(\lambda_s\) is the source wavelength.
02

Substitute given values

From the question, we know that the observed wavelength, \(\lambda_o = 575 nm\) (yellow light) and the source wavelength, \(\lambda_s = 675 nm\) (red light). Let's put these values into the formula. The speed of light, \(c = 3.00 \cdot 10^8 m/s\)
03

Solve for v

Now compute the observer's velocity by solving the equation. The velocity \(v\) will be negative, which indicates that the object is moving towards the light source.
04

Compute Fine

With the velocity obtained in the previous step, we can calculate the fine. We are told in the problem that the fine is $1.00 for each kilometer per hour that our speed exceeds the posted limit of 90 km/h. So, convert the velocity from m/s to km/h and subtract 90 km/h from it to find by how much was the limit exceeded.
05

Calculate total fine

Multiply the excess speed by the fine rate to get the total fine.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Doppler Shift Formula
The Doppler shift formula is an essential tool when it comes to understanding how the observed frequency or wavelength of a wave changes relative to the motion of the source or observer. In the realm of light, this formula is given by:
\[\begin{equation} v = c \times \bigg(\frac{\lambda_{\text{o}}}{\lambda_{\text{s}}} - 1\bigg)\end{equation}\]
where:
  • \(v\) represents the velocity of the observer relative to the source (it will be negative if approaching the source),
  • \(c\) stands for the speed of light in a vacuum (3.00 \times 10^8 m/s),
  • \(\lambda_{\text{o}}\) is the wavelength of the light as observed, and
  • \(\lambda_{\text{s}}\) is the wavelength of the light as emitted by the source.
This formula allows us to calculate the speed at which an observer must move to perceive a change in color of light, which is due to the shift in the frequency of the observed light. In practical terms, if approaching a red traffic light quickly enough, it could appear yellow, much like in the exercise provided.
Relativistic Doppler Effect
While the classical Doppler shift formula is suitable for everyday speeds, extreme velocities close to the speed of light require the relativistic Doppler effect to be considered. This comes into play because, according to Einstein's theory of relativity, as one's velocity increases towards the speed of light, time dilation and length contraction occur. These relativistic effects alter the perceived wavelength and frequency of light.
In such cases, the formula is modified to accommodate these effects:
\[\begin{equation} \lambda_{\text{o}} = \lambda_{\text{s}} \sqrt{\frac{1+\frac{v}{c}}{1-\frac{v}{c}}}\end{equation}\]
Although not necessary for everyday conditions, such as the traffic light scenario, it's crucial for astronomical observations and GPS satellite calculations where relativistic speeds are at play.
Speed of Light
The speed of light, denoted by \(c\), is a fundamental constant in physics, clocking in at approximately 3.00 \times 10^8 meters per second (m/s) in a vacuum. It represents the maximum speed at which all conventional matter, energy, and information in the universe can travel. In terms of the Doppler effect, \(c\) is a critical component of the formulas used to calculate changes in wavelengths as a consequence of relative motion. The constancy of the speed of light is the cornerstone of the theory of relativity, which reconciles mechanics with electromagnetism.
Wavelength and Frequency Relationship
Wavelength and frequency are inversely related in the context of a wave's properties, where the wavelength is the distance between two consecutive peaks of a wave, and frequency is the number of waves that pass a point per unit of time. This relationship is expressed by the equation:
\[\begin{equation} c = \lambda \times f\end{equation}\]
where \(\lambda\) is the wavelength, \(f\) is the frequency, and \(c\) remains the speed of light. When applying this to light, if the source or the observer moves, this relationship illustrates why the observed frequency and wavelength change, leading to the Doppler shift we observe in phenomena like a changing traffic light color or the redshift observed in distant galaxies.

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Most popular questions from this chapter

Muons are unstable subatomic particles that decay to electrons with a mean lifetime of \(2.2 \mu \mathrm{s}\) They are produced when cosmic rays bombard the upper atmosphere about \(10 \mathrm{~km}\) above the earth's surface, and they travel very close to the speed of light. The problem we want to address is why we see any of them at the earth's surface. (a) What is the greatest distance a muon could travel during its \(2.2 \mu\) s lifetime? (b) According to your answer in part (a), it would seem that muons could never make it to the ground. But the \(2.2 \mu \mathrm{s}\) lifetime is measured in the frame of the muon, and muons are moving very fast. At a speed of \(0.999 c,\) what is the mean lifetime of a muon as measured by an observer at rest on the earth? How far would the muon travel in this time? Does this result explain why we find muons in cosmic rays? (c) From the point of view of the muon, it still lives for only \(2.2 \mu \mathrm{s},\) so how does it make it to the ground? What is the thickness of the \(10 \mathrm{~km}\) of atmosphere through which the muon must travel, as measured by the muon? Is it now clear how the muon is able to reach the ground?

(a) At what speed is the momentum of a particle twice as great as the result obtained from the nonrelativistic expression \(m v ?\) Express your answer in terms of the speed of light. (b) A force is applied to a particle along its direction of motion. At what speed is the magnitude of force required to produce a given acceleration twice as great as the force required to produce the same acceleration when the particle is at rest? Express your answer in terms of the speed of light.

The negative pion \(\left(\pi^{-}\right)\) is an unstable particle with an average lifetime of \(2.60 \times 10^{-8} \mathrm{~s}\) (measured in the rest frame of the pion). (a) If the pion is made to travel at very high speed relative to a laboratory, its average lifetime is measured in the laboratory to be \(4.20 \times 10^{-7} \mathrm{~s}\). Calculate the speed of the pion expressed as a fraction of \(c\). (b) What distance, measured in the laboratory, does the pion travel during its average lifetime?

One way to strictly enforce a speed limit would be to alter the laws of nature. Suppose the speed of light were \(65 \mathrm{mph}\) and your workplace was 30 miles from your home. Assume you travel to work at a typical driving speed of 60 mph. (a) If you drove at that speed for the round trip to and from work, light, how much would your wristwatch lag your kitchen clock each day? (b) Estimate the length of your car. (c) If you were driving at your estimated driving speed, how long would your car be when viewed from the roadside? (d) What would be the speed relative to you of similar cars traveling toward you in the opposite lane with the same ground speed as you? (e) How long would you measure those cars to be? (f) If the total mass of you and your car was \(2000 \mathrm{~kg}\), how much work would be required to get you up to speed? (Note: Your rest mass energy in this world is \(m c^{2}\), where \(c=65\) mph. ) (g) How much work would be required in the real world, where the speed of light is \(3.0 \times 10^{8} \mathrm{~m} / \mathrm{s},\) to get you up to speed?

A baseball coach uses a radar device to measure the speed of an approaching pitched baseball. This device sends out electromagnetic waves with frequency \(f_{0}\) and then measures the shift in frequency \(\Delta f\) of the waves reflected from the moving baseball. If the fractional frequency shift produced by a baseball is \(\Delta f / f_{0}=2.86 \times 10^{-7},\) what is the baseball's speed in \(\mathrm{km} / \mathrm{h} ?\) (Hint: Are the waves Doppler- shifted a second time when reflected off the ball?)

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