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Electrons are accelerated through a potential difference of \(750 \mathrm{kV},\) so that their kinetic energy is \(7.50 \times 10^{5} \mathrm{eV}\). (a) What is the ratio of the speed \(v\) of an electron having this energy to the speed of light, \(c ?\) (b) What would the speed be if it were computed from the principles of classical mechanics?

Short Answer

Expert verified
(a) After calculation, the value of \(v/c\) will be found and it will be a dimensionless value lesser than 1 representing the ratio of the velocity of the electron to the speed of light. (b) The speed calculated from classical mechanics should be greater than the speed of light calculated from special relativity, reinforcing the fact that classical mechanics do not hold true for particles traveling at relativistic speeds.

Step by step solution

01

Calculation of Electron's Speed Using Special Relativity

Use the relativistic kinetic energy expression to solve for the speed. The Relativistic kinetic energy (K.E) is given by \(K.E = (\gamma - 1) mc^{2}\), where \(\gamma\) is the Lorentz factor given by \(\gamma = \frac{1}{\sqrt{1 - (v/c)^{2}}}\) So, rearranging the equation, we get \((v/c)^{2} = 1 - (mc^{2}/K.E + mc^{2})^{2}\). Since we know the values of \(m\), kinetic energy (K.E) which is \(7.50 \times 10^{5} \mathrm{eV} * 1.602 \times 10^{-19} \mathrm{J/eV}\), and \(c\) can also substitute these values in the equation.
02

Applying Values and Calculating

Substitute the values into the equation from Step 1. Solve for \(v/c\). After solving for \(v/c\), you should get a dimensionless value which will be less than 1 if the calculation has been done correctly.
03

Calculation of Electron's Speed Using Classical Mechanics

In classical mechanics, the kinetic energy (K.E) of an object is given by \(K.E = \frac{1}{2} mv^{2}\). You can rearrange this equation to solve for \(v\), which gives \(v = \sqrt{\frac{2K.E}{m}}\). Substitute the known values and solve for \(v\).
04

Comparing the Results

Now you can compare the two calculated speeds. The speed calculated using special relativity will be less than the one calculated using classical mechanics, demonstrating that classical physics is inaccurate for particles moving close to the speed of light.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Special Relativity
When dealing with particles moving at high velocities, approaching the speed of light, the principles of special relativity come into play. Developed by Albert Einstein in 1905, special relativity revolutionized our understanding of space, time, and energy. One of the key postulates of special relativity is that the laws of physics are the same in all inertial reference frames, and, notably, the speed of light in a vacuum is the same for all observers, regardless of their relative motion.

Functionally, this means that as objects move faster, nearing the velocity of light, time appears to slow down, lengths contract, and masses increase from the perspective of a stationary observer. These effects are negligible at everyday speeds but become very significant as the speed of an object approaches the speed of light, which is why they are essential when an electron is accelerated through a high potential difference, as in our exercise. The relativistic kinetic energy equation in the textbook solution accounts for these effects, modifying the classical kinetic energy expression to calculate an electron's speed more accurately.
Lorentz Factor
A pivotal component of special relativity is the Lorentz factor, symbolized by \(\text{\gamma}\) (gamma). It is a factor by which time, length, and relativistic mass change for an object while that object is moving. The Lorentz factor is defined as \(\gamma = \frac{1}{\sqrt{1 - (v/c)^{2}}}\), where \(v\) is the velocity of the object and \(c\) is the speed of light.

In context of our exercise, the \(\gamma\) factor describes how much the electron's mass increases due to its high speed. As the speed of the electron gets closer to the speed of light, the Lorentz factor increases significantly. When applying the Lorentz factor to the kinetic energy expression, we adjust the classical formula to fit the relativistic framework, acknowledging the changes in mass and dimensions that occur at high speeds. This adjusted formula gives us a more accurate measure of the electron's speed post-acceleration through a potential difference.
Classical Mechanics
Before the advent of special relativity, classical mechanics, as formulated by Isaac Newton, was the framework used to describe the motion of objects. It includes concepts and equations that describe how objects move under the influence of forces. One central concept is kinetic energy, which is the energy an object has due to its motion, often represented by the equation \(K.E = \frac{1}{2} mv^{2}\) in classical mechanics.

In scenarios involving everyday speeds, this equation provides a good approximation of an object's kinetic energy. However, as indicated in the exercise, classical mechanics does not account for the effects that come into play at speeds close to the speed of light. An electron accelerated to high speeds, as in our example, will have different properties according to classical mechanics compared to those predicted by special relativity, leading to different calculations of speed when applying classical equations.
Speed of Light
A constant that is critical to both special relativity and the nature of light itself is the speed of light in vacuum, denoted by \(c\). Its value is approximately \(3 \times 10^{8}\) meters per second. A fundamental postulate of special relativity, as mentioned earlier, is that the speed of light is constant and cannot be exceeded by any object with mass.

In the context of our exercise, understanding that \(c\) is the universal speed limit helps us appreciate why the relativistic approach to calculate the kinetic energy and speed of an electron is necessary. As particles such as electrons approach these extreme velocities, their behavior deviates markedly from the predictions of classical mechanics, and a relativistic framework becomes essential for accurate calculations. This underscores the importance of considering relativity when dealing with high-energy particles in physics.

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Most popular questions from this chapter

At \(x=x^{\prime}=0\) and \(t=t^{\prime}=0\) a clock ticks aboard an extremely fast spaceship moving past us in the \(+x\) -direction with a Lorentz factor of 100 so \(v \approx c .\) The captain hears the clock tick again \(1.00 \mathrm{~s}\) later. Where and when do we measure the second tick to occur?

Calculate the magnitude of the force required to give a \(0.145 \mathrm{~kg}\) baseball an acceleration \(a=1.00 \mathrm{~m} / \mathrm{s}^{2}\) in the direction of the baseball's initial velocity when this velocity has a magnitude of (a) \(10.0 \mathrm{~m} / \mathrm{s} ;\) (b) \(0.900 c ;\) (c) \(0.990 c\) (d) Repeat parts (a), (b), and (c) if the force and acceleration are perpendicular to the velocity.

The negative pion \(\left(\pi^{-}\right)\) is an unstable particle with an average lifetime of \(2.60 \times 10^{-8} \mathrm{~s}\) (measured in the rest frame of the pion). (a) If the pion is made to travel at very high speed relative to a laboratory, its average lifetime is measured in the laboratory to be \(4.20 \times 10^{-7} \mathrm{~s}\). Calculate the speed of the pion expressed as a fraction of \(c\). (b) What distance, measured in the laboratory, does the pion travel during its average lifetime?

A particle has rest mass \(6.64 \times 10^{-27} \mathrm{~kg}\) and momentum \(2.10 \times 10^{-18} \mathrm{~kg} \cdot \mathrm{m} / \mathrm{s} .\) (a) What is the total energy (kinetic plus rest energy) of the particle? (b) What is the kinetic energy of the particle? (c) What is the ratio of the kinetic energy to the rest energy of the particle?

A spacecraft of the Trade Federation flies past the planet Coruscant at a speed of \(0.600 c\). A scientist on Coruscant measures the length of the moving spacecraft to be \(74.0 \mathrm{~m}\). The spacecraft later lands on Coruscant, and the same scientist measures the length of the now stationary spacecraft. What value does she get?

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