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A spacecraft of the Trade Federation flies past the planet Coruscant at a speed of \(0.600 c\). A scientist on Coruscant measures the length of the moving spacecraft to be \(74.0 \mathrm{~m}\). The spacecraft later lands on Coruscant, and the same scientist measures the length of the now stationary spacecraft. What value does she get?

Short Answer

Expert verified
The length of the spacecraft when it is stationary is found to be approximately 92.7 meters.

Step by step solution

01

Understand the Problem

The problem states that a spacecraft is moving at a speed of \(0.600c\) measured by a scientist on planet Coruscant. The length of the spacecraft as measured by the scientist while it is moving is \(74.0 m\), and once it has stopped, the scientist measures its length again. This length is called proper length and we are asked to find this.
02

Apply the Formula for Length Contraction

The relationship between an object's length measured in its own rest frame (i.e., proper length) and its length measured in a moving frame (i.e., contracted length) is given by the formula \[L = L_0 / \gamma\] where \(L_0\) is the proper length, \(L\) is the contracted length, and \[\gamma = 1/\sqrt{1-v^2 / c^2}\] is the Lorentz factor.
03

Insert Given Values

From the problem statement, we know that \(L=74m\), \(v=0.600c\) and \(c\) is the speed of light. Insert these values into the formula in step 2.
04

Solve for Proper Length L_0

To find the proper length, First solve the equation for \(1/\gamma\) to get \[1/\gamma =\sqrt{1-(0.600c /c)^2}\] \[\Rightarrow 1/\gamma = \sqrt{1-0.600^2}\] Applying this to the equation \(L = L_0 / \gamma\), we can multiply both sides by \(\gamma\) to isolate \(L_0\) to find \[L_0 = L \cdot \gamma\]
05

Solve the Equation

Use a calculator or perform the arithmetic to find the proper length.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Special Relativity
Special relativity is a fundamental theory in physics developed by Albert Einstein, which revolutionized our understanding of space, time, and energy. The core of this theory is the postulate that the laws of physics are the same in all inertial frames of reference, and as a consequence, the speed of light in a vacuum is the same for all observers, regardless of their motion relative to the light source.

When objects approach the speed of light, termed 'relativistic speeds', we begin to witness some counterintuitive phenomena, such as time dilation and length contraction. Length contraction, specifically, is observed when an object's length is measured by an observer at rest relative to the object as being different from the length measured by an observer moving relative to the object. The moving observer will measure the length to be shorter than the observer at rest, a direct result of the relativistic effects predicted by special relativity.
Proper Length
In the context of special relativity, the term 'proper length' refers to the measurement of the length of an object as taken from the object's rest frame. This is essentially the length of the object as perceived by an observer who is at rest with respect to the object, or in other words, not moving relative to it.

The proper length is seen as the 'true' length of the object because it is free from the distortions of motion-related relativistic effects. It's an intrinsic property of the object, akin to its 'rest length'. When taking the textbook exercise as an example, the proper length of the spacecraft would be the length measured when the spacecraft has landed and is stationary relative to the observer. Understanding this concept is crucial because it’s often the benchmark for comparing how much the observed length contracts when the object is in motion.
Lorentz Factor
The Lorentz factor, commonly denoted as \(\gamma\), is a quantity that arises frequently in special relativity. It quantifies the factor by which time, length, and relativistic mass change for an object while that object is moving relative to an observer. Mathematically, the Lorentz factor is expressed as \[\gamma = \dfrac{1}{\sqrt{1 - \dfrac{v^2}{c^2}}}\] where \(v\) is the velocity of the moving object, and \(c\) is the speed of light.

The factor grows significantly as the velocity approaches the speed of light. For the spacecraft in our exercise traveling at \(0.600c\), we can calculate its Lorentz factor and observe how the length is contracted to \(74.0 m\) as measured by the scientist. Understanding the Lorentz factor is fundamental in calculating various relativistic effects, including how to find the proper length of an object after observing its contracted length.

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Most popular questions from this chapter

A spaceship flies past Mars with a speed of \(0.985 c\) relative to the surface of the planet. When the spaceship is directly overhead, a signal light on the Martian surface blinks on and then off. An observer on Mars measures that the signal light was on for \(75.0 \mu\) s. (a) Does the observer on Mars or the pilot on the spaceship measure the proper time? (b) What is the duration of the light pulse measured by the pilot of the spaceship?

A cube of metal with sides of length \(a\) sits at rest in a frame \(S\) with one edge parallel to the \(x\) -axis. Therefore, in \(S\) the cube has volume \(a^{3}\). Frame \(S^{\prime}\) moves along the \(x\) -axis with a speed \(u .\) As measured by an observer in frame \(S^{\prime},\) what is the volume of the metal cube?

The distance to a particular star, as measured in the earth's frame of reference, is 7.11 light-years ( 1 light-year is the distance that light travels in \(1 \mathrm{y}\) ). A spaceship leaves the earth and takes \(3.35 \mathrm{y}\) to arrive at the star, as measured by passengers on the ship. (a) How long does the trip take, according to observers on earth? (b) What distance for the trip do passengers on the spacecraft measure?

At \(x=x^{\prime}=0\) and \(t=t^{\prime}=0\) a clock ticks aboard an extremely fast spaceship moving past us in the \(+x\) -direction with a Lorentz factor of 100 so \(v \approx c .\) The captain hears the clock tick again \(1.00 \mathrm{~s}\) later. Where and when do we measure the second tick to occur?

You are a scientist studying small aerosol particles that are contained in a vacuum chamber. The particles carry a net charge, and you use a uniform electric field to exert a constant force of \(8.00 \times 10^{-14} \mathrm{~N}\) on one of them. That particle moves in the direction of the exerted force. Your instruments measure the acceleration of the particle as a function of its speed \(v .\) The table gives the results of your measurements for this particular particle. $$ \begin{array}{l|cccccc} \boldsymbol{v} / \boldsymbol{c} & 0.60 & 0.65 & 0.70 & 0.75 & 0.80 & 0.85 \\ \hline \boldsymbol{a}\left(\mathbf{1 0}^{\mathbf{3}} \mathbf{m} / \mathbf{s}^{\mathbf{2}}\right) & 20.3 & 17.9 & 14.8 & 11.2 & 8.5 & 5.9 \end{array} $$ (a) Graph your data so that the data points are well fit by a straight line. Use the slope of this line to calculate the mass \(m\) of the particle. (b) What magnitude of acceleration does the exerted force produce if the speed of the particle is \(100 \mathrm{~m} / \mathrm{s} ?\)

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