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Compute the kinetic energy of a proton (mass \(\left.1.67 \times 10^{-27} \mathrm{~kg}\right)\) using both the nonrelativistic and relativistic expressions, and compute the ratio of the two results (relativistic divided by nonrelativistic) for speeds of (a) \(8.00 \times 10^{7} \mathrm{~m} / \mathrm{s}\) and (b) \(2.85 \times 10^{8} \mathrm{~m} / \mathrm{s}\)

Short Answer

Expert verified
The ratio of relativistic to nonrelativistic kinetic energies for the given speeds are approximately 1 (or very close to 1) for non-relativistic speeds and much higher for relativistic speeds.

Step by step solution

01

Nonrelativistic Kinetic Energy

Calculate the nonrelativistic kinetic energy for both speeds using formula \(0.5 \times m \times v^2\), where \(m = 1.67 \times 10 ^ -27 kg\) and \(v\) is the given speed.
02

Relativistic Kinetic Energy

Calculate the relativistic kinetic energy for both speeds using formula \(\gamma \times m \times c^2 - m \times c^2\), where \(m = 1.67 \times 10 ^ -27 kg\), \(c = 3 \times 10^8 m/s\), \(v\) is the given speed and \(\gamma\) is calculated as \(\frac{1}{\sqrt{1-(v^2/c^2)}}\).
03

Ratio of kinetic energies

Obtain the ratio of the relativistic kinetic energy to the nonrelativistic kinetic energy for both speeds.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Nonrelativistic Kinetic Energy
The concept of nonrelativistic kinetic energy arises in classical mechanics, which works well for objects moving much slower than the speed of light. It's a measure of the energy an object possesses due to its motion. To calculate this for simple cases, we use the formula: \( KE_{nr} = 0.5 \times m \times v^2 \), where \(m\) is the mass of the object and \(v\) is its velocity.

When dealing with a proton at velocities that are not near the speed of light, this formula gives us a good approximation of its kinetic energy. For example, if a proton is traveling at a speed of \(8.00 \times 10^7 \mathrm{m/s}\), the nonrelativistic kinetic energy would be considered an accurate representation of the proton's energy due to its motion.
Relativistic Kinetic Energy
Relativistic kinetic energy comes into play when dealing with particles moving at or near the speed of light, in accordance with Einstein's theory of relativity. The nonrelativistic kinetic energy formula fails to account for the effects of relativity at high velocities. Instead, we use the relativistic kinetic energy formula: \( KE_{rel} = \gamma \times m \times c^2 - m \times c^2 \), where \(m\) is the mass of the object, \(c\) is the speed of light, and \(\gamma\) is the Lorentz factor calculated by the equation \(\gamma = \frac{1}{\sqrt{1-(v^2/c^2)}}\).

For objects moving at significant fractions of the speed of light, like a proton at \(2.85 \times 10^8 \mathrm{m/s}\), relativistic kinetic energy will be much different from nonrelativistic kinetic energy. The Lorentz factor \(\gamma\) causes the energy to increase substantially as the velocity approaches the speed of light, a reflection of the fact that mass becomes a more critical factor in an object's energy as its speed increases.
Ratio of Kinetic Energies
Understanding the ratio of relativistic to nonrelativistic kinetic energies is useful for appreciating how classical mechanics transitions to relativistic mechanics. This ratio can be expressed as: \( \frac{KE_{rel}}{KE_{nr}} \).

At low speeds, this ratio will be close to 1, indicating that relativistic effects are negligible and classical mechanics prevails. However, as the speed increases to a significant fraction of the speed of light, the ratio grows greater than 1, reflecting the fact that relativistic effects cannot be ignored.

To illustrate, at a proton speed of \(8.00 \times 10^7 \mathrm{m/s}\), the ratio might be close to 1, suggesting nonrelativistic kinetic energy is a sufficient approximation. In contrast, at speeds like \(2.85 \times 10^8 \mathrm{m/s}\), the ratio will be much larger, emphasizing the importance of taking into account the principles of relativity.

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Most popular questions from this chapter

If a muon is traveling at \(0.999 c,\) what are its momentum and kinetic energy? (The mass of such a muon at rest in the laboratory is 207 times the electron mass.)

A proton (rest mass \(1.67 \times 10^{-27} \mathrm{~kg}\) ) has total energy that is 4.00 times its rest energy. What are (a) the kinetic energy of the proton; (b) the magnitude of the momentum of the proton; (c) the proton's speed?

A baseball coach uses a radar device to measure the speed of an approaching pitched baseball. This device sends out electromagnetic waves with frequency \(f_{0}\) and then measures the shift in frequency \(\Delta f\) of the waves reflected from the moving baseball. If the fractional frequency shift produced by a baseball is \(\Delta f / f_{0}=2.86 \times 10^{-7},\) what is the baseball's speed in \(\mathrm{km} / \mathrm{h} ?\) (Hint: Are the waves Doppler- shifted a second time when reflected off the ball?)

As a research scientist at a linear accelerator, you are studying an unstable particle. You measure its mean lifetime \(\Delta t\) as a function of the particle's speed relative to your laboratory equipment. You record the speed of the particle \(u\) as a fraction of the speed of light in vacuum \(c .\) The table gives the results of your measurements. $$ \begin{array}{l|lllllll} u / c & 0.70 & 0.80 & 0.85 & 0.88 & 0.90 & 0.92 & 0.94 \\ \hline \Delta t\left(10^{-8} \mathrm{~s}\right) & 3.57 & 4.41 & 5.02 & 5.47 & 6.05 & 6.58 & 7.62 \end{array} $$ (a) Your team leader suggests that if you plot your data as \((\Delta t)^{2}\) versus \(\left(1-u^{2} / c^{2}\right)^{-1},\) the data points will be fit well by a straight line. Construct this graph and verify the team leader's prediction. Use the best-fit straight line to your data to calculate the mean lifetime of the particle in its rest frame. (b) What is the speed of the particle relative to your lab equipment (expressed as \(u / c\) ) if the lifetime that you measure is four times its rest-frame lifetime?

One way to strictly enforce a speed limit would be to alter the laws of nature. Suppose the speed of light were \(65 \mathrm{mph}\) and your workplace was 30 miles from your home. Assume you travel to work at a typical driving speed of 60 mph. (a) If you drove at that speed for the round trip to and from work, light, how much would your wristwatch lag your kitchen clock each day? (b) Estimate the length of your car. (c) If you were driving at your estimated driving speed, how long would your car be when viewed from the roadside? (d) What would be the speed relative to you of similar cars traveling toward you in the opposite lane with the same ground speed as you? (e) How long would you measure those cars to be? (f) If the total mass of you and your car was \(2000 \mathrm{~kg}\), how much work would be required to get you up to speed? (Note: Your rest mass energy in this world is \(m c^{2}\), where \(c=65\) mph. ) (g) How much work would be required in the real world, where the speed of light is \(3.0 \times 10^{8} \mathrm{~m} / \mathrm{s},\) to get you up to speed?

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