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A hot-air balloon stays aloft because hot air at atmospheric pressure is less dense than cooler air at the same pressure. If the volume of the balloon is \(500.0 \mathrm{~m}^{3}\) and the surrounding air is at \(15.0^{\circ} \mathrm{C}\) what must the temperature of the air in the balloon be for it to lift a total load of \(290 \mathrm{~kg}\) (in addition to the mass of the hot air)? The density of air at \(15.0^{\circ} \mathrm{C}\) and atmospheric pressure is \(1.23 \mathrm{~kg} / \mathrm{m}^{3}\).

Short Answer

Expert verified
The temperature of the air in the balloon needs to be -67.05 C in order for it to lift a total load of 290 kg.

Step by step solution

01

Calculate the total mass of the balloon

Firstly, calculate the mass of the air inside the balloon using the density and volume of air at 15.0 C. Use the formula, \(mass = density \times volume\), giving us \(mass = 1.23 kg/m^3 \times 500.0 m^3 = 615.0 kg\). Then, calculate the total mass of the balloon (air inside the balloon plus the load), which is \(615 kg + 290 kg = 905 kg\).
02

Find the density of hot air inside the balloon

Considering that the balloon is floating, the weight of the displaced cooler air must be equal to the weight of the balloon itself. With that, we calculate the density of the hot air inside the balloon using \(\rho_{hot} = \frac{m_{balloon}}{V_{balloon}} = \frac{905kg}{500m^3} = 1.81 kg/m^3\).
03

Calculate the temperature of balloon using ideal gas law

Now we will convert the respective temperatures to absolute temperatures in kelvins. T_cool_air (temperature of cooler surrounding air) = 15.0 C = 15.0 + 273.15 = 288.15 K. Note that the density of a gas is inversely proportional to its temperature. Therefore, we set up a ratio using the densities and temperatures of the hot and cooler air. From this relation, we determine the absolute temperature of the hot air inside balloon is \(T_{hot} = T_{cool} * (\frac{ \rho_{cool} }{ \rho_{hot} }) = 288.15K * (\frac{1.23 kg/m^3 }{ 1.81 kg/m^3 }) = 206.1 K\).The result is given in absolute temperature (kelvin), we need to convert it back to Celsius, giving us -67.05 C.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Density and Buoyancy
When we consider how a hot-air balloon operates, we're actually exploring the principles of density and buoyancy. Density describes how tightly packed a substance's mass is within a given volume. For gases, it's crucial to understand that warmer air is less dense than cooler air because the heat causes air molecules to move faster and spread out more.

Buoyancy, on the other hand, is a force that's all about an object being immersed in a fluid (which could be a liquid or a gas like air). It refers to the ability of a fluid to exert an upward force on an object placed in it. This is why boats float and why hot-air balloons rise into the sky—buoyant force. For the balloon to stay afloat, the air inside it must be less dense than the surrounding air. That's accomplished by heating the air, thus decreasing its density and allowing the balloon to rise as the cooler, denser air pushes it upwards from below.

The total weight that a balloon can lift, which includes the mass of the balloon fabric, the basket, and its occupants, is determined by the difference in the density of the air inside and outside the balloon. The greater the difference, the higher the lifting force, allowing the balloon to carry more weight.
Ideal Gas Law
The behavior of gases under various conditions is described by the ideal gas law, represented by the equation PV = nRT. This equation relates the pressure (P), volume (V), number of moles of gas (n), temperature (T in Kelvin), and the ideal gas constant (R). When dealing with hot-air balloons, we often assume that the pressure inside and outside the balloon are the same, that is, atmospheric pressure.

In the context of hot-air balloons, the ideal gas law allows us to calculate what must happen to the air inside the balloon to achieve the necessary buoyancy. In our exercise, we needed to find the temperature that would make the air less dense and consequently increase the volume without changing the pressure. By manipulating the variables of the ideal gas law — keeping the pressure and number of moles constant — it becomes clear that increasing the temperature results in an increase in volume. This relationship is a cornerstone in understanding how the temperature of the air inside the balloon affects its buoyancy.
Temperature and Volume Relationship
The relationship between temperature and volume is a key factor in explaining how a hot-air balloon works. This relationship is known as Charles's Law in chemistry and physics, which states that at constant pressure, the volume of a gas is directly proportional to its temperature when measured in Kelvin. This means that if you increase the temperature, the volume will also increase, provided that the pressure remains constant.

In our exercise, we applied this principle to determine the temperature the air in the balloon must be to lift the specified load. After calculating the required density of hot air for the balloon to be buoyant, we could then use the established relationship between temperature and volume to find the exact temperature needed. Essentially, the balloon's volume doesn't change drastically, but its temperature does, in order to achieve the lower density needed to lift the balloon. Lowering the density means raising the volume of air in each cubic meter inside the balloon, which can only be done by increasing the temperature.

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Most popular questions from this chapter

Oxygen \(\left(\mathrm{O}_{2}\right)\) has a molar mass of \(32.0 \mathrm{~g} / \mathrm{mol} .\) What is (a) the average translational kinetic energy of an oxygen molecule at a temperature of \(300 \mathrm{~K} ;\) (b) the average value of the square of its speed; (c) the rootmean-square speed; (d) the momentum of an oxygen molecule traveling at this speed? (e) Suppose an oxygen molecule traveling at this speed bounces back and forth between opposite sides of a cubical vessel \(0.10 \mathrm{~m}\) on a side. What is the average force the molecule exerts on one of the walls of the container? (Assume that the molecule's velocity is perpendicular to the two sides that it strikes.) (f) What is the average force per unit area? (g) How many oxygen molecules traveling at this speed are necessary to produce an average pressure of 1 atm? (h) Compute the number of oxygen molecules that are contained in a vessel of this size at \(300 \mathrm{~K}\) and atmospheric pressure. (i) Your answer for part (h) should be three times as large as the answer for part \((\mathrm{g})\). Where does this discrepancy arise?

Solid water (ice) is slowly warmed from a very low temperature. (a) What minimum external pressure \(p_{1}\) must be applied to the solid if a melting phase transition is to be observed? Describe the sequence of phase transitions that occur if the applied pressure \(p\) is such that \(p

You blow up a spherical balloon to a diameter of \(50.0 \mathrm{~cm}\) until the absolute pressure inside is 1.25 atm and the temperature is \(22.0^{\circ} \mathrm{C}\). Assume that all the gas is \(\mathrm{N}_{2},\) of molar mass \(28.0 \mathrm{~g} / \mathrm{mol}\). (a) Find the mass of a single \(\mathrm{N}_{2}\), molecule. (b) How much translational kinetic energy does an average \(\mathrm{N}_{2}\) molecule have? (c) How many \(\mathrm{N}_{2}\) molecules are in this balloon? (d) What is the total translational kinetic energy of all the molecules in the balloon?

Consider an ideal gas at \(27^{\circ} \mathrm{C}\) and 1.00 atm. To get some idea how close these molecules are to each other, on the average, imagine them to be uniformly spaced, with each molecule at the center of a small cube. (a) What is the length of an edge of each cube if adjacent cubes touch but do not overlap? (b) How does this distance compare with the diameter of a typical molecule? (c) How does their separation compare with the spacing of atoms in solids, which typically are about \(0.3 \mathrm{nm}\) apart?

The vapor pressure is the pressure of the vapor phase of a substance when it is in equilibrium with the solid or liquid phase of the substance. The relative humidity is the partial pressure of water vapor in the air divided by the vapor pressure of water at that same temperature, expressed as a percentage. The air is saturated when the humidity is \(100 \%\). (a) The vapor pressure of water at \(20.0^{\circ} \mathrm{C}\) is \(2.34 \times 10^{3} \mathrm{~Pa}\). If the air temperature is \(20.0^{\circ} \mathrm{C}\) and the relative humidity is \(60 \%,\) what is the partial pressure of water vapor in the atmosphere (that is, the pressure due to water vapor alone)? (b) Under the conditions of part (a), what is the mass of water in \(1.00 \mathrm{~m}^{3}\) of air? (The molar mass of water is \(18.0 \mathrm{~g} / \mathrm{mol}\). Assume that water vapor can be treated as an ideal gas.)

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