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A flask contains a mixture of neon (Ne), krypton (Kr), and radon (Rn) gases. Compare (a) the average kinetic energies of the three types of atoms and (b) the root-mean-square speeds. (Hint: Appendix D shows the molar mass (in \(\mathrm{g} / \mathrm{mol}\) ) of each element under the chemical symbol for that element.)

Short Answer

Expert verified
The average kinetic energies of Ne, Kr, and Rn are equal. The root-mean-square speed is highest for Ne, lower for Kr, and lowest for Rn, assuming they are at the same temperature.

Step by step solution

01

Evaluate the Average Kinetic Energy

We know that the average kinetic energy of a gas molecule is given by the equation: \[ KE_{avg} = \frac{3}{2} kT \]. Here, \(k\) represents Boltzmann's constant and \(T\) represents the temperature. If we assume that the three gases are at the same temperature, then their average kinetic energies will be the same since it is solely dependent on temperature and not on the type or molar mass of the gas. Therefore, the average kinetic energies of Ne, Kr, and Rn are equal.
02

Calculate the Root-Mean-Square Speeds

The root-mean-square speed is given by the formula: \[v_{rms} = \sqrt{\frac{3kT}{m}}\], where \(m\) is the molar mass of the gas. Smaller atoms are lighter, thus they move faster. Conversely, larger atoms are heavier and move slower. Therefore, the root-mean-square speed is inversely proportional to the square root of the molar mass. Appendix D should provide the necessary values for molar masses. Substituting the molar masses of Ne, Kr, and Rn into the equation will yield the root-mean-square speeds for each.
03

Compare the Root-Mean-Square Speeds

Using the values obtained from step 2, the root-mean-square speeds for each of the gases can be compared. The gas with the lightest molar mass (Ne) will have the highest root-mean-square speed, while the gas with the heaviest molar mass (Rn) will have the lowest root-mean-square speed.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Average Kinetic Energy
When we talk about the kinetic energy of gases, one of the fundamental concepts to grasp is the average kinetic energy. This is the energy that gas molecules have on average due to their motion. In a sample of gas, myriad molecules move at different speeds and in various directions. However, when we average their kinetic energies, we get a value that represents the whole gas.

The average kinetic energy of gas molecules can be calculated with the equation: \[ KE_{avg} = \frac{3}{2} kT \]Here, \(k\) is known as Boltzmann's constant, and \(T\) is the absolute temperature in Kelvin. Importantly, the average kinetic energy is directly proportional to the temperature. This means that regardless of the type of gas, if its temperature remains the same, its average kinetic energy stays constant as well. If we consider our given flask containing different gases at the same temperature, it becomes clear that the average kinetic energy is identical for neon (Ne), krypton (Kr), and radon (Rn).

Understanding the Implications

Imagine an invisible dance of molecules all moving and colliding. Although each type of molecule may dance to a different beat, the average kinetic energy reveals the overall intensity of the dance. This is a critical concept in thermodynamics and highlights the equality of energy distribution at a given temperature.
Root-Mean-Square Speed of Gas Molecules
Diving deeper into the behavior of gas molecules, we encounter the concept of root-mean-square speed (rms speed). This value gives us an indication of the molecules' speed in a gas. Unlike average kinetic energy, the rms speed does take into account the mass of the molecules.

The equation for the rms speed is: \[v_{rms} = \sqrt{\frac{3kT}{m}}\]where \(m\) is the molar mass of the gas molecule, and the other terms remain consistent with the kinetic energy equation. The square root is used to assure the speed comes out as a positive value, as it represents magnitude without direction.

Speed Varies with Molar Mass

As the equation shows, the rms speed is inversely proportional to the square root of the molar mass of a gas molecule. Consequently, lighter molecules, like those of neon, zip around faster compared to heavier molecules, like those of radon. Understanding the relationship between molar mass and rms speed is essential for predicting how different gases will behave under the same conditions. It's a dance of sorts where lighter partners can move swiftly, while heavier ones take a more measured pace.
Boltzmann's Constant
At the heart of the kinetic molecular theory lies Boltzmann's constant (\(k\)), a fundamental physical constant that relates the average kinetic energy of particles in a gas to the temperature of the gas. Its value is approximately \(1.38 \times 10^{-23} \) J/K (joules per kelvin).

Boltzmann's constant acts as a bridge between the macroscopic world that we can observe (like temperature) and the microscopic world of atoms and molecules in motion. By using this constant, we can link the temperature we feel to the unseen agitation of a sea of particles.

The Universal Gas Constant

It's also noteworthy to mention the universal gas constant (\(R\)), which is used in the ideal gas law. It's related to Boltzmann's constant by the number of molecules in a mole (Avogadro's number), specifically \(R = k \times N_A\). Through understanding Boltzmann's constant, we gather insight not only into energy per particle but also the larger thermodynamic properties of gases.
Molar Mass and Gas Properties
Gas properties can vary widely depending on their molar mass, which is the mass of one mole of a substance usually expressed in g/mol. For gases, the molar mass is critical in determining both the rms speed and how they will conduct themselves under various conditions.

In our earlier discussion on rms speeds, we learned that the speed is inversely related to the square root of the molar mass. This concept is integral when examining how gases diffuse or how quickly a gas will effuse through a small opening. Gases of lower molar mass spread more rapidly due to their higher speeds.

Understanding Molar Mass Effects

Reflect on how different balloons filled with helium (a very light gas) and carbon dioxide (a heavier gas) will behave. The helium balloon rises and diffuses quickly into the atmosphere, while the carbon dioxide-filled balloon rises more slowly and diffuses less rapidly. This illustrates the tangible effects of molar mass on gas properties in the world around us.

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Most popular questions from this chapter

(a) What is the total translational kinetic energy of the air in an empty room that has dimensions \(8.00 \mathrm{~m} \times 12.00 \mathrm{~m} \times 4.00 \mathrm{~m}\) if the air is treated as an ideal gas at 1.00 atm? (b) What is the speed of a \(2000 \mathrm{~kg}\) automobile if its kinetic energy equals the translational kinetic energy calculated in part (a)?

A physics lecture room at 1.00 atm and \(27.0^{\circ} \mathrm{C}\) has a volume of \(216 \mathrm{~m}^{3}\). (a) Use the ideal-gas law to estimate the number of air molecules in the room. Assume that all of the air is \(\mathrm{N}_{2} .\) Calculate (b) the particle density - that is, the number of \(\mathrm{N}_{2}\), molecules per cubic centimeter-and (c) the mass of the air in the room.

A cylinder \(1.00 \mathrm{~m}\) tall with inside diameter \(0.120 \mathrm{~m}\) is used to hold propane gas (molar mass \(44.1 \mathrm{~g} / \mathrm{mol}\) ) for use in a barbecue. It is initially filled with gas until the gauge pressure is \(1.30 \times 10^{6} \mathrm{~Pa}\) at \(22.0^{\circ} \mathrm{C}\). The temperature of the gas remains constant as it is partially emptied out of the tank, until the gauge pressure is \(3.40 \times 10^{5} \mathrm{~Pa}\). Calculate the mass of propane that has been used.

A hot-air balloon stays aloft because hot air at atmospheric pressure is less dense than cooler air at the same pressure. If the volume of the balloon is \(500.0 \mathrm{~m}^{3}\) and the surrounding air is at \(15.0^{\circ} \mathrm{C}\) what must the temperature of the air in the balloon be for it to lift a total load of \(290 \mathrm{~kg}\) (in addition to the mass of the hot air)? The density of air at \(15.0^{\circ} \mathrm{C}\) and atmospheric pressure is \(1.23 \mathrm{~kg} / \mathrm{m}^{3}\).

Consider an ideal gas at \(27^{\circ} \mathrm{C}\) and 1.00 atm. To get some idea how close these molecules are to each other, on the average, imagine them to be uniformly spaced, with each molecule at the center of a small cube. (a) What is the length of an edge of each cube if adjacent cubes touch but do not overlap? (b) How does this distance compare with the diameter of a typical molecule? (c) How does their separation compare with the spacing of atoms in solids, which typically are about \(0.3 \mathrm{nm}\) apart?

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