/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 17 (a) Calculate the mass of nitrog... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

(a) Calculate the mass of nitrogen present in a volume of \(3000 \mathrm{~cm}^{3}\) if the gas is at \(22.0^{\circ} \mathrm{C}\) and the absolute pressure of \(2.00 \times 10^{-13}\) atm is a partial vacuum easily obtained in laboratories. (b) What is the density (in \(\mathrm{kg} / \mathrm{m}^{3}\) ) of the \(\mathrm{N}_{2}\) ?

Short Answer

Expert verified
The mass of Nitrogen is calculated using n * molar mass, and the density of \( \mathrm{N}_2 \) is calculated using \( \rho = \frac{Mass}{V} \) .

Step by step solution

01

Applying the Ideal Gas Law

Using the Ideal Gas Law, \( PV = nRT \), where P is pressure, V is volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin. Firstly, convert the volume from cm^3 to m^3, temperature from Celsius to Kelvin and pressure from atm to pascal: \( V = 3000 \times 10^{-6} \, m^3 \), \( T = 22.0 + 273.15 \, K = 295.15 \, K \), and \( P = 2.00 \times 10^{-13} \times 1.013 \times 10^{5} \, Pa \). Solve the equation for n: \( n = PV/RT \) \(
02

Calculate the mass of Nitrogen

Knowing that one mole of any gas contains Avogadro's number (\(6.022 \times 10^{23}\)) of molecules, and the molar mass of nitrogen (\(\mathrm{N}_2\)) is 28.0134 g / mole, convert the number of moles to mass: Mass = n * molar mass = \( n \times 28.0134 \times 10^{-3} \, kg \).
03

Calculate the density of Nitrogen

Finally, use the mass and the volume to calculate the density, \( \rho = \frac{Mass}{V} \) .

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mass of Nitrogen
The mass of nitrogen in a given volume of gas can be calculated using the Ideal Gas Law and some basic conversions. The Ideal Gas Law equation is given by \( PV = nRT \), where:
  • \( P \) is the pressure,
  • \( V \) is the volume,
  • \( n \) is the number of moles,
  • \( R \) is the gas constant,
  • \( T \) is the temperature in Kelvin.
Let's break down how to calculate the mass of nitrogen.First, it's important to convert the provided units to the standard units used in the Ideal Gas Law:
  • Convert the volume from \( \mathrm{cm}^3 \) to \( \mathrm{m}^3 \) by multiplying by \(10^{-6}\). So, \( 3000 \, \mathrm{cm}^3 = 3000 \times 10^{-6} \, \mathrm{m}^3 \).
  • Convert the temperature from degrees Celsius to Kelvin by adding 273.15. Thus, \( 22.0^\circ \mathrm{C} = 295.15 \, \mathrm{K} \).
  • Convert the pressure from atm to pascal by multiplying by \( 1.013 \times 10^5 \). Therefore, \(2.00 \times 10^{-13} \, \mathrm{atm} = 2.00 \times 10^{-13} \times 1.013 \times 10^5 \, \mathrm{Pa} \).
Now, solve for \( n \) using the rearranged Ideal Gas Law: \( n = \frac{PV}{RT} \). Once \( n \) is known, multiply it by the molar mass of nitrogen \( (28.0134 \, \mathrm{g/mol} = 28.0134 \times 10^{-3} \, \mathrm{kg/mol}) \) to find the mass.This approach will yield the mass of nitrogen in the given conditions.
Density Calculation
Once we determine the mass of a gas, calculating its density is straightforward. Density (\( \rho \)) is a measure of how much mass is contained within a specific volume and is defined by the equation:\[ \rho = \frac{\text{Mass}}{\text{Volume}} \]For our specific example with nitrogen, now that we have the mass calculated using the Ideal Gas Law, we can plug it into our density formula.Considerations for calculating density:
  • Make sure that the mass is in kilograms \((\mathrm{kg})\), which is derived from the number of moles and the molar mass.
  • Ensure the volume is in cubic meters \((\mathrm{m}^3)\), which was previously converted from cubic centimeters in our earlier calculation.
Simply substitute the values into the density formula to obtain the density of nitrogen in \( \mathrm{kg/m}^3 \). This measurement gives a clear idea of how concentrated the nitrogen molecules are within the given volume.
Conversion of Units
Converting units is a crucial step when working with physics equations like the Ideal Gas Law. Using consistent units ensure accurate calculations. Here's how unit conversion applies in our scenario:**Volume Conversion**The volume was initially given in cubic centimeters \((\mathrm{cm}^3)\). To convert to cubic meters \((\mathrm{m}^3)\), multiply by \(10^{-6}\). This is because there are \(100\) centimeters in a meter, so \((\mathrm{cm})^3\) conversion to \((\mathrm{m})^3\) involves \((10^{-2})^3 = 10^{-6}\).**Temperature Conversion**Temperature provided in Celsius \((^\circ \mathrm{C})\) is converted to Kelvin (\(\mathrm{K}\)) by adding 273.15. This is because the Kelvin scale is an absolute temperature scale and reduces temperature-based discrepancies in calculations.**Pressure Conversion**Pressure in atmospheres \((\mathrm{atm})\) is converted to Pascals \((\mathrm{Pa})\) by multiplying by \(1.013 \times 10^5\). The pascal is the SI unit for pressure, ensuring we maintain uniformity with other SI units like meters and kilograms.Unit conversions are not merely procedural steps; they are vital for ensuring the correct application of formulas and achieving reliable results. Always ensure to cross-check your units for consistency across all measurement parameters.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

During a test dive in \(1939,\) prior to being accepted by the U.S. Navy, the submarine Squalus sank at a point where the depth of water was \(73.0 \mathrm{~m}\). The temperature was \(27.0^{\circ} \mathrm{C}\) at the surface and \(7.0^{\circ} \mathrm{C}\) at the bottom. The density of seawater is \(1030 \mathrm{~kg} / \mathrm{m}^{3}\). (a) A diving bell was used to rescue 33 trapped crewmen from the Squalus. The diving bell was in the form of a circular cylinder \(2.30 \mathrm{~m}\) high, open at the bottom and closed at the top. When the diving bell was lowered to the bottom of the sea, to what height did water rise within the diving bell? (Hint: Ignore the relatively small variation in water pressure between the bottom of the bell and the surface of the water within the bell.) (b) At what gauge pressure must compressed air have been supplied to the bell while on the bottom to expel all the water from it?

A large tank of water has a hose connected to it (Fig. P18.61). The tank is sealed at the top and has compressed air between the water surface and the top. When the water height \(h\) has the value \(3.50 \mathrm{~m}\), the absolute pressure \(p\) of the compressed air is \(4.20 \times 10^{5} \mathrm{~Pa}\). Assume that the air above the water expands at constant temperature, and take the atmospheric pressure to be \(1.00 \times 10^{5} \mathrm{~Pa}\). (a) What is the speed with which water flows out of the hose when \(h=3.50 \mathrm{~m} ?\) (b) As water flows out of the tank, \(h\) decreases. Calculate the speed of flow for \(h=3.00 \mathrm{~m}\) and for \(h=2.00 \mathrm{~m} .\) (c) At what value of \(h\) does the flow stop?

The dark area in Fig. \(\mathbf{P} 18.83\) that appears devoid of stars is a dark nebula, a cold gas cloud in interstellar space that contains enough material to block out light from the stars behind it. A typical dark nebula is about 20 light-years in diameter and contains about 50 hydrogen atoms per cubic centimeter (monatomic hydrogen, not \(\mathrm{H}_{2}\) ) at about \(20 \mathrm{~K}\). (A lightyear is the distance light travels in vacuum in one year and is equal to \(\left.9.46 \times 10^{15} \mathrm{~m} .\right)\) (a) Estimate the mean free path for a hydrogen atom in a dark nebula. The radius of a hydrogen atom is \(5.0 \times 10^{-11} \mathrm{~m}\). (b) Estimate the rms speed of a hydrogen atom and the mean free time (the average time between collisions for a given atom). Based on this result, do you think that atomic collisions, such as those leading to \(\mathrm{H}_{2} \mathrm{~mol}-\) ecule formation, are very important in determining the composition of the nebula? (c) Estimate the pressure inside a dark nebula. (d) Compare the rms speed of a hydrogen atom to the escape speed at the surface of the nebula (assumed spherical). If the space around the nebula were a vacuum, would such a cloud be stable or would it tend to evaporate? (e) The stability of dark nebulae is explained by the presence of the interstellar medium (ISM), an even thinner gas that permeates space and in which the dark nebulae are embedded. Show that for dark nebulae to be in equilibrium with the ISM, the numbers of atoms per volume \((N / V)\) and the temperatures \((T)\) of dark nebulae and the ISM must be related by $$ \frac{(N / V)_{\text {nebula }}}{(N / V)_{\text {ISM }}}=\frac{T_{\text {ISM }}}{T_{\text {nebula }}} $$ (f) In the vicinity of the sun, the ISM contains about 1 hydrogen atom per \(200 \mathrm{~cm}^{3} .\) Estimate the temperature of the ISM in the vicinity of the sun. Compare to the temperature of the sun's surface, about \(5800 \mathrm{~K}\). Would a spacecraft coasting through interstellar space burn up? Why or why not?

For diatomic carbon dioxide gas \(\left(\mathrm{CO}_{2},\right.\) molar mass \(\left.44.0 \mathrm{~g} / \mathrm{mol}\right)\) at \(T=300 \mathrm{~K},\) calculate (a) the most probable speed \(v_{\mathrm{mp}} ;\) (b) the average speed \(v_{\mathrm{av}} ;\) (c) the root-mean-square speed \(v_{\mathrm{rms}}\).

The atmosphere of Mars is mostly \(\mathrm{CO}_{2}\) (molar mass \(44.0 \mathrm{~g} / \mathrm{mol}\) ) under a pressure of \(650 \mathrm{~Pa}\), which we shall assume remains constant. In many places the temperature varies from \(0.0^{\circ} \mathrm{C}\) in summer to \(-100^{\circ} \mathrm{C}\) in winter. Over the course of a Martian year, what are the ranges of (a) the rms speeds of the \(\mathrm{CO}_{2}\), molecules and (b) the density (in \(\mathrm{mol} / \mathrm{m}^{3}\) ) of the atmosphere?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.