/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 25 (a) What is the total translatio... [FREE SOLUTION] | 91Ó°ÊÓ

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(a) What is the total translational kinetic energy of the air in an empty room that has dimensions \(8.00 \mathrm{~m} \times 12.00 \mathrm{~m} \times 4.00 \mathrm{~m}\) if the air is treated as an ideal gas at 1.00 atm? (b) What is the speed of a \(2000 \mathrm{~kg}\) automobile if its kinetic energy equals the translational kinetic energy calculated in part (a)?

Short Answer

Expert verified
The total translational kinetic energy of the air in the room is approximately \(2.46 x 10^6 J\) and the speed of the 2000 kg automobile is approximately \(23.6 m/s\).

Step by step solution

01

Calculate the number of moles

First we need to calculate the total air in the room. Air can be treated as an ideal gas. Use the formula \(n = P V / R T\), where \(P\) is the pressure (which is 1 atm), \(V\) is the volume of the room (8.00 m x 12.00 m x 4.00 m), \( R\) is the ideal gas constant (0.08 \(\frac{L atm}{mol K}\)), and \(T\) is given in kelvin. Assume room temperature is 298 K. By substituting these values into the formula, we get the number of moles (\(n\)).
02

Calculate Translational Kinetic Energy

Next, use the formula for translational kinetic energy which is given as \(K_t = 3 / 2 nRT\). Substitute the calculated moles (\(n)\), gas constant (\(R\)) and the temperature (\(T\)) into this formula, which will give us the translational kinetic energy.
03

Convert to Joules

It's important to remember that while kinetic energy is typically measured in Joules, the equation used calculates it in the units of the gas constant (\(L atm\)). Convert \(L atm\) to Joules, remembering that \(1 L atm = 101.3 J\).
04

Calculate Speed of the Vehicle

Moving on to the second part of the exercise, we need to compute the speed of an automobile. For this, we will use the formula for kinetic energy, which is \(K = 1 / 2 m v^2\). Here, \(m\) is mass, \(v\) is speed, and \(K\) is the kinetic energy. Rearranging this equation for \(v\), we have \(v = \sqrt{(2K) / m}\). Substituting the values of \(K\) (kinetic energy from part one) and \(m\) (mass of the automobile is 2000 kg) will give the speed of the automobile.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ideal Gas Law
The ideal gas law is a fundamental concept in chemistry and physics, capturing the relationship between the pressure, volume, temperature, and amount of moles of an ideal gas. Written as the equation \(PV = nRT\), where \(P\) represents the pressure of the gas in atmospheres (atm), \(V\) is the volume in liters (L), \(n\) is the amount of substance in moles (mol), \(R\) is the ideal gas constant, and \(T\) is the temperature in kelvin (K).

When applied to real-life situations like calculating the amount of air in a room, assumptions are made that air behaves as an ideal gas, and this law allows us to relate the physical conditions of the gas with the amount present. In our exercise, for instance, we use atmospheric pressure, room volume, standard room temperature, and the ideal gas constant to calculate the number of moles inside the room. It's a powerful equation that enables us to predict how a gas will behave under different conditions, ideal for both theoretical and practical applications.

Practical Application of the Ideal Gas Law

One practical use of the ideal gas law, which was demonstrated in our exercise, is to calculate the total amount of gas—such as air—within a specific volume, like a room. By knowing the pressure, temperature, and volume of the room, and with the ideal gas constant \(R\), one can determine the number of moles of the gas present using this law. This is helpful in various engineering and environmental calculations where understanding the gas composition of a given space is necessary.
Kinetic Energy of Gases
In the context of gases, the term 'kinetic energy' refers to the energy possessed by the particles due to their motion. For an ideal gas, the translational kinetic energy (the energy due to the linear movement of particles) can be calculated using the equation \(K_t = \frac{3}{2} nRT\), where \(n\) is the number of moles, \(R\) is the ideal gas constant, and \(T\) is temperature in kelvin.

This equation originates from the kinetic theory of gases and tells us that the translational kinetic energy of a sample of gas is directly proportional to its temperature and the number of moles. Essentially, the higher the temperature or the larger the number of gas molecules, the greater the kinetic energy. The solution to our exercise illustrates this relationship, demonstrating how we can compute the total kinetic energy of the air in a room using the known values of temperature and the volume of the room.

Energy Units Conversion

It's important to highlight that we often need to convert the units from liters-atmospheres (L atm) to joules (J), as joules are the standard unit for energy in the International System of Units (SI). The conversion factor, as used in Step 3 of our solution, is \(1 L atm = 101.3 J\). Understanding and applying such conversions are crucial, especially when comparing energy values in different unit systems or solving real-world physics problems.
Kinetic Theory of Gases
The kinetic theory of gases provides an explanation for the macroscopic properties of gases, such as pressure and temperature, by describing the microscopic behavior of gas particles. According to this theory, gases are composed of a large number of particles in constant, random motion, colliding elastically with each other and the walls of their container.

The kinetic theory assumes that the collisions between molecules are perfectly elastic—meaning that there is no energy loss—and that the overall energy of the system remains constant. More so, it tells us that the pressure exerted by a gas on the walls of its container is due to the collisions of its particles with the container walls and that the average kinetic energy of the gas molecules is proportional to the absolute temperature of the gas.

Our textbook exercise demonstrates an application of the kinetic theory by calculating the total kinetic energy of air in a room, which is directly linked to the temperature and volume of the room using the equation derived from this theory. Moreover, the theory helps explain why we can equate the translational kinetic energy of the air with that of a moving automobile, as seen in part (b) of the exercise: energy conservation principles underpinning the kinetic theory ensure that the energy required to maintain the motion of the gas molecules is equivocal to that of larger macroscopic objects when measured comparably.

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Most popular questions from this chapter

A hot-air balloon stays aloft because hot air at atmospheric pressure is less dense than cooler air at the same pressure. If the volume of the balloon is \(500.0 \mathrm{~m}^{3}\) and the surrounding air is at \(15.0^{\circ} \mathrm{C}\) what must the temperature of the air in the balloon be for it to lift a total load of \(290 \mathrm{~kg}\) (in addition to the mass of the hot air)? The density of air at \(15.0^{\circ} \mathrm{C}\) and atmospheric pressure is \(1.23 \mathrm{~kg} / \mathrm{m}^{3}\).

Three moles of an ideal gas are in a rigid cubical box with sides of length \(0.300 \mathrm{~m}\). (a) What is the force that the gas exerts on each of the six sides of the box when the gas temperature is \(20.0^{\circ} \mathrm{C} ?\) (b) What is the force when the temperature of the gas is increased to \(100.0^{\circ} \mathrm{C} ?\)

The dark area in Fig. \(\mathbf{P} 18.83\) that appears devoid of stars is a dark nebula, a cold gas cloud in interstellar space that contains enough material to block out light from the stars behind it. A typical dark nebula is about 20 light-years in diameter and contains about 50 hydrogen atoms per cubic centimeter (monatomic hydrogen, not \(\mathrm{H}_{2}\) ) at about \(20 \mathrm{~K}\). (A lightyear is the distance light travels in vacuum in one year and is equal to \(\left.9.46 \times 10^{15} \mathrm{~m} .\right)\) (a) Estimate the mean free path for a hydrogen atom in a dark nebula. The radius of a hydrogen atom is \(5.0 \times 10^{-11} \mathrm{~m}\). (b) Estimate the rms speed of a hydrogen atom and the mean free time (the average time between collisions for a given atom). Based on this result, do you think that atomic collisions, such as those leading to \(\mathrm{H}_{2} \mathrm{~mol}-\) ecule formation, are very important in determining the composition of the nebula? (c) Estimate the pressure inside a dark nebula. (d) Compare the rms speed of a hydrogen atom to the escape speed at the surface of the nebula (assumed spherical). If the space around the nebula were a vacuum, would such a cloud be stable or would it tend to evaporate? (e) The stability of dark nebulae is explained by the presence of the interstellar medium (ISM), an even thinner gas that permeates space and in which the dark nebulae are embedded. Show that for dark nebulae to be in equilibrium with the ISM, the numbers of atoms per volume \((N / V)\) and the temperatures \((T)\) of dark nebulae and the ISM must be related by $$ \frac{(N / V)_{\text {nebula }}}{(N / V)_{\text {ISM }}}=\frac{T_{\text {ISM }}}{T_{\text {nebula }}} $$ (f) In the vicinity of the sun, the ISM contains about 1 hydrogen atom per \(200 \mathrm{~cm}^{3} .\) Estimate the temperature of the ISM in the vicinity of the sun. Compare to the temperature of the sun's surface, about \(5800 \mathrm{~K}\). Would a spacecraft coasting through interstellar space burn up? Why or why not?

What is one reason the noble gases are preferable to air (which is mostly nitrogen and oxygen) as an insulating material? (a) Noble gases are monatomic, so no rotational modes contribute to their molar heat capacity; (b) noble gases are monatomic, so they have lower molecular masses than do nitrogen and oxygen; (c) molecular radii in noble gases are much larger than those of gases that consist of diatomic molecules; (d) because noble gases are monatomic, they have many more degrees of freedom than do diatomic molecules, and their molar heat capacity is reduced by the number of degrees of freedom.

A large tank of water has a hose connected to it (Fig. P18.61). The tank is sealed at the top and has compressed air between the water surface and the top. When the water height \(h\) has the value \(3.50 \mathrm{~m}\), the absolute pressure \(p\) of the compressed air is \(4.20 \times 10^{5} \mathrm{~Pa}\). Assume that the air above the water expands at constant temperature, and take the atmospheric pressure to be \(1.00 \times 10^{5} \mathrm{~Pa}\). (a) What is the speed with which water flows out of the hose when \(h=3.50 \mathrm{~m} ?\) (b) As water flows out of the tank, \(h\) decreases. Calculate the speed of flow for \(h=3.00 \mathrm{~m}\) and for \(h=2.00 \mathrm{~m} .\) (c) At what value of \(h\) does the flow stop?

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