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A rocket with mass \(5.00 \times 10^{3} \mathrm{~kg}\) is in a circular orbit of radius \(7.20 \times 10^{6} \mathrm{~m}\) around the earth. The rocket's engines fire for a period of time to increase that radius to \(8.80 \times 10^{6} \mathrm{~m},\) with the orbit again circular. (a) What is the change in the rocket's kinetic energy? Does the kinetic energy increase or decrease? (b) What is the change in the rocket's gravitational potential energy? Does the potential energy increase or decrease? (c) How much work is done by the rocket engines in changing the orbital radius?

Short Answer

Expert verified
This procedure will help to solve the problem. By putting the given numeric values into the derived formulas one can get the desired results for kinetic energy change, potential energy change and the work done by rocket engines.

Step by step solution

01

Calculate initial and final kinetic energy

The formula for kinetic energy, \(KE = \frac{1}{2} m v^2\). Here \(m\) is the mass of the rocket and \(v\) is the speed of the rocket. In a circular orbit, the speed of the rocket is determined by gravitational force, so \(v^2 = GM / r\). Thus, \(KE_{initial} = \frac{1}{2}m \frac{GM}{r_{initial}}\) and \(KE_{final} = \frac{1}{2}m \frac{GM}{r_{final}}\), where \(G\) is the gravitational constant, \(M\) is the mass of the Earth, \(r_{initial}\) and \(r_{final}\) are the radii of the initial and final orbits.
02

Calculate the change in kinetic energy

The change in kinetic energy is simply the final kinetic energy minus the initial kinetic energy, so \(\Delta KE = KE_{final} - KE_{initial}\)
03

Calculate initial and final gravitational potential energy

The formula for gravitational potential energy is \(U = - \frac{GMm}{r}\). Thus, \(U_{initial} = - \frac{GMm}{r_{initial}}\) and \(U_{final} = - \frac{GMm}{r_{final}}\)
04

Calculate the change in gravitational potential energy

The change in gravitational potential energy is the final potential energy minus the initial potential energy, so \(\Delta U = U_{final} - U_{initial}\)
05

Calculate the work done by the rocket engines

The total amount of work done by the rocket engines is the sum of the changes in kinetic and potential energy. So the work done, \(W = \Delta KE + \Delta U\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinetic Energy in Orbits
Kinetic energy is the energy an object possesses due to its motion. In the context of celestial mechanics, when an object is in orbit, its kinetic energy keeps it moving along its path around the central body, counterbalancing the gravitational pull. For a satellite or rocket in a circular orbit, this energy is calculated using the formula

\[\begin{equation} KE = \frac{1}{2} m v^2 \end{equation}\]

where \(m\) represents its mass and \(v\) its orbital velocity. Crucially, the speed must be high enough to sustain the orbit but not too high to escape the central body's gravitational pull.

For a circular orbit, where gravity provides the centripetal force, the velocity can be expressed through gravitational parameters as

\[\begin{equation} v^2 = \frac{GM}{r} \end{equation}\]

with \(G\) as the gravitational constant, and \(M\) as the mass of the central body, such as Earth. Here, \(r\) stands for the orbit's radius. From the provided exercise, the kinetic energy changes as the radius of the orbit changes, demonstrating its inverse relationship with the orbit's radius: as the radius increases, the kinetic energy decreases, since the velocity is lower at a higher orbit.
Gravitational Potential Energy
Gravitational potential energy in the context of orbital mechanics is the energy stored due to an object's position in a gravitational field. It is given by

\[\begin{equation} U = - \frac{GMm}{r} \end{equation}\]

The negative sign indicates that work needs to be done against the gravitational pull to move objects such as a rocket to larger orbits, hence increasing its potential energy.

The interplay between gravitational potential energy and kinetic energy is crucial for understanding orbits. While the kinetic energy resists the gravitational pull by keeping the object in motion, the gravitational potential energy pulls the object toward the central body due to gravity.

In the scenario of the exercise, when the rocket's orbit radius is increased, the gravitational potential energy increases because the rocket is further away from Earth and has 'climbed out' of the gravitational well to a certain extent. This increase in potential energy reflects the work required to reach a higher orbit.
Work Done in Changing Orbit
The work done by rocket engines, or any other force in altering an orbit, can be thought of as the energy required to transition an object from one orbit to another. This work is equivalent to the change in the object's total mechanical energy, which is the sum of its kinetic and potential energy.

Following the analysis of the exercise, the formula to express work done is

\[\begin{equation} W = \Delta KE + \Delta U \end{equation}\]

Work thus is done when the rocket engines fire and change the rocket's orbit. It's important to note that the total mechanical energy will be conserved if there are no external forces doing work on the system; however, in this case, the rocket engine does external work.

In the situation of the example, the kinetic energy decreases but the gravitational potential energy increases. As a result, the work done is effectively the energy invested into the system to increase the potential energy, and it can either come from the chemical energy of fuel in the case of rocket engines or from other sources like gravity assists in space maneuvers.

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Most popular questions from this chapter

Tidal Forces near a Black Hole. An astronaut inside a spacecraft, which protects her from harmful radiation, is orbiting a black hole at a distance of \(120 \mathrm{~km}\) from its center. The black hole is 5.00 times the mass of the sun and has a Schwarzschild radius of \(15.0 \mathrm{~km} .\) The astronaut is positioned inside the spaceship such that one of her \(0.030 \mathrm{~kg}\) ears is \(6.0 \mathrm{~cm}\) farther from the black hole than the center of mass of the spacecraft and the other ear is \(6.0 \mathrm{~cm}\) closer. (a) What is the tension between her ears? Would the astronaut find it difficult to keep from being torn apart by the gravitational forces? (Since her whole body orbits with the same angular velocity, one ear is moving too slowly for the radius of its orbit and the other is moving too fast. Hence her head must exert forces on her cars to keep them in their orbits.) (b) Is the center of gravity of her head at the same point as the center of mass? Explain.

Two spherically symmetric planets with no atmosphere have the same average density, but planet \(B\) has twice the radius of planet \(A\). A small satellite of mass \(m_{A}\) has period \(T_{A}\) when it orbits planet \(A\) in a circular orbit that is just above the surface of the planet. A small satellite of mass \(m_{B}\) has period \(T_{B}\) when it orbits planet \(B\) in a circular orbit that is just above the surface of the planet. How does \(T_{B}\) compare to \(T_{A} ?\) with a density of \(2500 \mathrm{~kg} / \mathrm{m}^{3} ?\)

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At the Galaxy's Core. Astronomers have observed a small, massive object at the center of our Milky Way galaxy (see Section 13.8). A ring of material orbits this massive object; the ring has a diameter of about 15 light-years and an orbital speed of about \(200 \mathrm{~km} / \mathrm{s}\) (a) Determine the mass of the object at the center of the Milky Way galaxy. Give your answer both in kilograms and in solar masses (one solar mass is the mass of the sun). (b) Observations of stars, as well as theories of the structure of stars, suggest that it is impossible for a single star to have a mass of more than about 50 solar masses. Can this massive object be a single, ordinary star? (c) Many astronomers believe that the massive object at the center of the Milky Way galaxy is a black hole. If so, what must the Schwarzschild radius of this black hole be? Would a black hole of this size fit inside the earth's orbit around the sun?

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