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\(A} science-fiction author asks for your help. He wants to write about a newly discovered spherically symmetric planet that has the same average density as the earth but with a \)25 \%\( larger radius. (a) What is \)g$ on this planet? (b) If he decides to have his explorers weigh the same on this planet as on earth, how should he change its average density?

Short Answer

Expert verified
The gravity on the new planet would be \(1.95\) times that of the Earth's and the average density on the new planet would need to be \(95%\) higher than Earth for the explorers to have the same weight as they do on Earth.

Step by step solution

01

Find the gravity of this new planet

Since we are given that the planet has a \(25 \%\) larger radius, we have \( R_{planet} = 1.25 \cdot R_{earth} \). Substituting the values for M as \( \rho \frac{4}{3} \pi R^{3} \) and \( R = 1.25 \cdot R_{earth} \) in the formula for gravity, we get \( g_{planet} = G \frac{\rho \frac{4}{3}\pi(1.25 R_{earth})^{3}}{(1.25 R_{earth})^{2}} = (1.25)^{3} \cdot G \frac{\rho \frac{4}{3}\pi R_{earth}^{3}}{R_{earth}^{2}} = (1.25)^{3} \cdot g_{earth} \)
02

Determine the change in average density to maintain the same weight

If weight is same on both Earth and the new planet, then \( g_{planet} = g_{earth} \), which implies that \( (1.25)^{3} \cdot g_{earth} = g_{earth} \). So, \( (1.25)^{3} \cdot \rho_{earth} = \rho_{planet} \). Thus, the new density \( \rho_{planet} \) = \(1.95 \cdot \rho_{earth}\), meaning the average density should be 95% higher for the explorers to weigh the same on this new planet as on Earth.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Spherical Symmetry
In physics and astronomy, spherical symmetry is a condition where a body, like a planet, is perfectly round in shape with all points on its surface at identical distances from its center. This characteristic simplifies calculations pertaining to gravitational forces, as only the radius of the sphere is needed to describe its shape.
For example, when discussing gravitational acceleration on planets, we assume spherical symmetry to easily calculate how gravity will act at different points on or around the planet. All real planets are only approximately spherical due to rotational effects and surface features, but the concept is a useful simplification.
Planetary Density
Planetary density is a measure of how much mass a planet has in a given volume, defined as mass divided by volume. For a spherical planet, the equation is \(\rho = \frac{M}{\frac{4}{3}\pi R^3}\), with \(M\) as the mass and \(R\) as the radius.
Density plays a crucial role in determining a planet's gravitational field because it influences how much matter there is to exert gravitational pull. When we say a new planet has the same density as Earth, it means it has the same amount of mass per unit volume. This helps in predicting other characteristics like gravity at the planet’s surface if we know its radius.
Radius of Planet
The radius of a planet is the distance from its center to its surface. It's a critical factor in the calculation of gravitational acceleration. On Earth, this radius is approximately 6,371 kilometers. A planet with a 25% larger radius than Earth means that its size has scaled up by this percentage, impacting its gravitational characteristics.
The increase in radius means a larger volume and hence a larger mass if the density remains unchanged. On a larger planet, the gravitational force at the surface may change because the gravitational potential is spread over a larger area.
Weight and Mass
Weight and mass are often confused but are distinct concepts in physics. Mass refers to the amount of matter in an object and remains constant irrespective of location. Weight, however, is the force exerted by gravity on that mass. This force changes based on the gravitational pull of where the object is, described by \(\text{Weight} = m \cdot g\), where \(m\) is mass, and \(g\) is gravitational acceleration.
On different planets, gravitational acceleration varies depending on their mass and radius. Therefore, an object's weight can differ from planet to planet even though its mass does not change. In the context of the science-fiction author’s planetary physics, the explorers would weigh the same if the planet's gravity matched Earth's precisely by adjusting its density accordingly.

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Most popular questions from this chapter

A narrow uniform rod has length \(2 a\). The linear mass density of the rod is \(\rho,\) so the mass \(m\) of a length \(l\) of the rod is \(\rho l\). (a) A point mass is located a perpendicular distance \(r\) from the center of the rod. Calculate the magnitude and direction of the force that the rod exerts on the point mass. (Hint: Let the rod be along the \(y\) -axis with the center of the rod at the origin, and divide the rod into infinitesimal segments that have length \(d y\) and that are located at coordinate \(y\). The mass of the segment is \(d m=\rho d y\). Write expressions for the \(x\) - and \(y\) -components of the force on the point mass, and integrate from \(-a\) to \(+a\) to find the components of the total force. Use the integrals in Appendix B.) (b) What does your result become for \(a \gg r ?\) (Hint: Use the power series for \((1+x)^{n}\) given in Appendix B.) (c) For \(a \gg r,\) what is the gravitational field \(g=\boldsymbol{F}_{g} / m\) at a distance \(r\) from the rod? (d) Consider a cylinder of radius \(r\) and length \(L\) whose axis is along the rod. As in part (c), let the length of the rod be much greater than both the radius and length of the cylinder. Then the gravitational ficld is constant on the curved side of the cylinder and perpendicular to it, so the gravitational flux \(\Phi_{g}\) through this surface is cqual to \(g A\), where \(A=2 \pi r L\) is the area of the curved side of the cylinder (see Problem 13.59 ). Calculate this flux. Write your result in terms of the mass \(M\) of the portion of the rod that is inside the cylindrical surface. How does your result depend on the radius of the cylindrical surface?

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A satellite with mass \(848 \mathrm{~kg}\) is in a circular orbit with an orbital speed of \(9640 \mathrm{~m} / \mathrm{s}\) around the earth. What is the new orbital speed after friction from the earth's upper atmosphere has done \(-7.50 \times 10^{9} \mathrm{~J}\) of work on the satellite? Does the speed increase or decrease?

Binary Star-Equal Masses. Two identical stars with mass \(M\) orbit around their center of mass. Each orbit is circular and has radius \(R,\) so that the two stars are always on opposite sides of the circle. (a) Find the gravitational force of one star on the other. (b) Find the orbital speed of each star and the period of the orbit. (c) How much energy would be required to separate the two stars to infinity?

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