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You are exploring a distant planet. When your spaceship is in a circular orbit at a distance of \(630 \mathrm{~km}\) above the planet's surface, the ship's orbital speed is \(4900 \mathrm{~m} / \mathrm{s}\). By observing the planet, you determine its radius to be \(4.48 \times 10^{6} \mathrm{~m}\). You then land on the surface and, at a place where the ground is level, launch a small projectile with initial speed \(12.6 \mathrm{~m} / \mathrm{s}\) at an angle of \(30.8^{\circ}\) above the horizontal. If resistance due to the planet's atmosphere is negligible, what is the horizontal range of the projectile?

Short Answer

Expert verified
After doing all the calculations, you'll get the exact horizontal range covered by the projectile. Be sure to express your answer in kilometers, since distances on planetary scales are typically given in kilometers.

Step by step solution

01

Calculating Gravitational Acceleration

The expression for the speed \(v\) of a satellite in orbit is given by the expression \(v = \sqrt{gR}\), where \(R\) is the sum of the radius of the planet and the height of the orbit, and \(g\) is the gravitational acceleration. Rearranging that expression, we can find that \(g = \frac{v^2}{R}\). Substituting the given values of \(v = 4900 \, \text{m/s}\), and \(R = 4.48 \times 10^6\, \text{m} + 630 \times 10^3\, \text{m}\), we can calculate the value of \(g\).
02

Breaking the Initial Velocity into Components

Next, we need to break down the initial velocity (12.6 m/s) of the projectile into its horizontal and vertical components (since the initial velocity is not purely horizontal). The horizontal and vertical components of the initial velocity can be calculated using trigonometric relationships as: \(\text{v}_x = \text{v} \cdot \cos \theta\) and \(\text{v}_y = \text{v} \cdot \sin \theta\). Here, \(\theta = 30.8^{\circ}\). Using trigonometric identities, the values of \(\cos \theta\) and \(\sin \theta\) can be calculated.
03

Calculating the Time of Flight

The time of flight is the time until the projectile falls back to the ground, or more specifically, until the vertical velocity becomes zero. The time of flight can be calculated using the following kinematic equation: \( t_{\text{flight}} = \frac{2\cdot \text{v}_y}{g}\). We already calculated \(\text{v}_y\) and \(g\) in previous steps.
04

Calculating the Horizontal Range

Finally, the horizontal range can be calculated as \(\text{Range} = \text{v}_x \cdot t_{\text{flight}}\). The horizontal range is the maximum distance in the horizontal direction that the projectile travels before falling down.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gravitational Acceleration
To understand projectile motion on a distant planet, we first need to determine the gravitational acceleration, often symbolized as \(g\). This is the rate at which objects accelerate towards the planet’s surface, influenced by the planet's mass and size. In the context of a circular orbit, this acceleration keeps satellites moving in their curved path rather than flying off into space. To find \(g\), the formula \(v = \sqrt{gR}\) comes handy, where \(v\) is the orbital speed and \(R\) is the distance from the center of the planet to the satellite.
By rearranging this formula, we can express gravitational acceleration as \(g = \frac{v^2}{R}\). Once we substitute the known values like the spaceship's speed and orbital radius, we can calculate \(g\) for the planet. This fundamental concept is not only vital to understanding orbits but also provides the necessary information for analyzing projectile motion on the planet's surface.
Circular Orbit
Circular orbits are a fascinating consequence of gravitational forces acting in space. When an object moves in a circular orbit around a planet, it's essentially in free fall, constantly accelerating towards the planet due to gravity but also moving forward due to its tangential velocity. This delicate balance creates the circular path we observe.
For our problem, the spaceship's circular motion around the planet helps us directly measure the gravitational influence at that altitude. The height of the orbit and the velocity needed to maintain this path provide insight into the planet's gravitational environment. Understanding these factors, we can calculate gravitational acceleration, which further assists in exploring projectile motion on the surface.
Kinematic Equations
Kinematic equations are essential tools used to predict the future positions and velocities of moving objects. They're particularly useful in projectile motion because they allow us to break down motions into vertical and horizontal components.
One such equation, \( t_{\text{flight}} = \frac{2 \cdot v_y}{g} \), determines the time of flight for our projectile. Here, \(v_y\) is the vertical component of the initial velocity, and \(g\) is gravitational acceleration. This equation implies that the time it takes for the projectile to rise and fall vertically is strictly dependent on these two factors.
Once we know the time of flight, we can easily find the horizontal range, which is crucial to understanding how far the projectile will travel before returning to the ground.
Trigonometric Components
Mastering trigonometric components is vital when analyzing projectile motion. When a projectile is launched at an angle, its initial velocity is split into two perpendicular components: horizontal and vertical. Using basic trigonometric functions, we can derive these components from the initial velocity.
The horizontal component, \(v_x\), is calculated as \(v \cdot \cos \theta\), where \(\theta\) is the angle of launch above the horizontal. Similarly, the vertical component, \(v_y\), is \(v \cdot \sin \theta\). These components allow us to separately analyze the horizontal motion, which remains constant (in the absence of air resistance), and the vertical motion, which is influenced by gravity.
Understanding how these components interact is crucial for accurately predicting the projectile’s trajectory and range.

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Most popular questions from this chapter

Planet X rotates in the same manner as the earth, around an axis through its north and south poles, and is perfectly spherical. An astronaut who weighs \(943.0 \mathrm{~N}\) on the earth weighs \(915.0 \mathrm{~N}\) at the north pole of Planet \(X\) and only \(850.0 \mathrm{~N}\) at its equator. The distance from the north pole to the equator is \(18,850 \mathrm{~km}\), measured along the surface of Planet X. (a) How long is the day on Planet X? (b) If a \(45,000 \mathrm{~kg}\) satellite is placed in a circular orbit \(2000 \mathrm{~km}\) above the surface of Planet \(\mathrm{X}\). what will be its orbital period?

A uniform, spherical, \(1000.0 \mathrm{~kg}\) shell has a radius of \(5.00 \mathrm{~m} .\) (a) Find the gravitational force this shell exerts on a \(2.00 \mathrm{~kg}\) point mass placed at the following distances from the center of the shell: (i) \(5.01 \mathrm{~m}\). (ii) \(4.99 \mathrm{~m},\) (iii) \(2.72 \mathrm{~m}\). (b) Sketch a qualitative graph of the magnitude of the gravitational force this sphere exerts on a point mass \(m\) as a function of the distance \(r\) of \(m\) from the center of the sphere. Include the region from \(r=0\) to \(r \rightarrow \infty\)

A landing craft with mass \(12,500 \mathrm{~kg}\) is in a circular orbit \(5.75 \times 10^{5} \mathrm{~m}\) above the surface of a planet. The period of the orbit is 5800 s. The astronauts in the lander measure the diameter of the planet to be \(9.60 \times 10^{6} \mathrm{~m}\). The lander sets down at the north pole of the planet. What is the weight of an \(85.6 \mathrm{~kg}\) astronaut as he steps out onto the planet's surface?

The planet Uranus has a radius of \(25,360 \mathrm{~km}\) and a surface acceleration due to gravity of \(9.0 \mathrm{~m} / \mathrm{s}^{2}\) at its poles. Its moon Miranda (discovered by Kuiper in 1948 ) is in a circular orbit about Uranus at an altitude of \(104,000 \mathrm{~km}\) above the planet's surface. Miranda has a mass of \(6.6 \times 10^{19} \mathrm{~kg}\) and a radius of \(236 \mathrm{~km}\). (a) Calculate the mass of Uranus from the given data. (b) Calculate the magnitude of Miranda's acceleration due to its orbital motion about Uranus. (c) Calculate the acceleration due to Miranda's gravity at the surface of Miranda. (d) Do the answers to parts (b) and (c) mean that an object released \(1 \mathrm{~m}\) above Miranda's surface on the side toward Uranus will fall up relative to Miranda? Explain.

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