/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 66 The planet Uranus has a radius o... [FREE SOLUTION] | 91Ó°ÊÓ

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The planet Uranus has a radius of \(25,360 \mathrm{~km}\) and a surface acceleration due to gravity of \(9.0 \mathrm{~m} / \mathrm{s}^{2}\) at its poles. Its moon Miranda (discovered by Kuiper in 1948 ) is in a circular orbit about Uranus at an altitude of \(104,000 \mathrm{~km}\) above the planet's surface. Miranda has a mass of \(6.6 \times 10^{19} \mathrm{~kg}\) and a radius of \(236 \mathrm{~km}\). (a) Calculate the mass of Uranus from the given data. (b) Calculate the magnitude of Miranda's acceleration due to its orbital motion about Uranus. (c) Calculate the acceleration due to Miranda's gravity at the surface of Miranda. (d) Do the answers to parts (b) and (c) mean that an object released \(1 \mathrm{~m}\) above Miranda's surface on the side toward Uranus will fall up relative to Miranda? Explain.

Short Answer

Expert verified
a) The mass of Uranus can be found using the given radius and surface gravity, giving a result in kg. b) Miranda's acceleration due to its orbital motion about Uranus can be found using its distance from Uranus and the mass of Uranus, yielding a result in \( \mathrm{m}/\mathrm{s^{2}} \). c) The acceleration due to Miranda's gravity can be found using its radius and mass, yielding another value in \( \mathrm{m}/\mathrm{s^{2}} \). d) Comparison of the values from (b) and (c) will reveal whether an object released 1 meter above Miranda's surface will move upwards or downwards relative to Miranda.

Step by step solution

01

Calculation of the mass of Uranus

The acceleration due to gravity on the surface of Uranus is given by \( g = G \frac{M}{R^2} \), where \( G \) is the gravitational constant, \( M \) is the mass of Uranus, and \( R \) is the radius of Uranus. By rearranging for \( M \), we get \( M = \frac{g R^2}{G} \). Substituting the given values for \( g \), \( R \), and \( G \), we get the mass of Uranus.
02

Calculation of the magnitude of Miranda's acceleration due to its orbital motion about Uranus

The acceleration of an object in circular orbit is given by \( a = \frac{G M_{U}}{r^2} \), where \( M_{U} \) is the mass of Uranus calculated in the previous step, and \( r \) is the distance of Miranda from the center of Uranus. The value of \( r \) can be obtained by adding Miranda’s altitude above Uranus’ surface to the radius of Uranus. The obtained \( r \) can be substituted into the equation along with \( M_{U} \) and \( G \) to give Miranda's orbital acceleration.
03

Calculation the acceleration due to Miranda's gravity at the surface of Miranda

Using the formula \( a = G \frac{M_{M}}{r^2} \), where \( M_{M} \) is the mass of Miranda, and \( r \) the radius of Miranda, both provided in the question, and \( G \) is the universal gravitational constant, we can calculate the acceleration due to Miranda's gravity at the surface of Miranda.
04

Interpretation of results

If Miranda's orbital acceleration is greater than Miranda's surface gravity, then an object released \(1 \mathrm{~m}\) above Miranda's surface will fall upwards relative to Miranda. However, if Miranda's surface gravity is larger, then the object will fall downwards towards Miranda. Comparing the results from parts (b) and (c) will yield the answer.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Acceleration Due to Gravity
Understanding acceleration due to gravity is essential for solving gravitational physics problems. It's the rate at which an object speeds up as it falls towards a massive body, like a planet or moon, due to the force of gravity. This acceleration is typically represented by the symbol \(g\) and can be calculated using the equation \(g = G \frac{M}{R^2}\), where \(G\) is the gravitational constant, \(M\) is the mass of the celestial body, and \(R\) is the radius of the body.

For example, the surface acceleration due to gravity at the poles of Uranus was given as \(9.0 \mathrm{m/s^2}\). Using this value, and knowing Uranus's radius, one can compute the planet's mass. When an object is in free fall near the surface of a celestial body, it will accelerate towards the center at the rate of \(g\), assuming no air resistance or other forces are acting upon the object.
Circular Orbit Motion
Circular orbit motion involves an object moving around another object along a circular path due to the gravitational pull of the central object. This kind of motion is ubiquitous in our universe, as observed in moons orbiting planets or planets around stars. An object in circular orbit experiences centripetal acceleration, which maintains its circular path and is always directed towards the center of the orbit.

The formula to calculate this acceleration, \(a\), for a moon like Miranda orbiting Uranus is given by \(a = \frac{G M_U}{r^2}\), where \(M_U\) is the mass of Uranus and \(r\) is the distance from Miranda to the center of Uranus. To find \(r\), add the altitude of Miranda's orbit to Uranus's radius. This equation is central to understanding how the moon's speed allows it to stay in orbit without falling into Uranus or shooting off into space.
Gravitational Constant
The gravitational constant (\(G\)) is a key value in the field of physics, particularly in the realm of gravitation. It appears in Newton's law of universal gravitation and is used to quantify the strength of the gravitational force between two masses. The approximate value of \(G\) is \(6.674 \times 10^{-11} \text{Nm}^2/\text{kg}^2\).

The significance of \(G\) becomes clear when we perform calculations that involve the force of gravity or the gravitational attraction between bodies. It's a constant of proportionality, meaning that while the force of gravity between two objects depends on their masses and the distance between them, \(G\) remains unchanged universally. This constant allows us to compare gravitational effects across different planets and moons.
Mass Calculation of Celestial Bodies
To calculate the mass of celestial bodies like planets and moons, one can apply the principles of gravitation. The formula used for mass calculation is derived from the law of universal gravitation, specifically adapted to determine the body's mass based on its gravitational effects. Using the formula \(M = \frac{g R^2}{G}\), we can calculate a celestial body's mass by knowing the acceleration due to gravity (\(g\)) on its surface, its radius (\(R\)), and the universal gravitational constant (\(G\)).

In our example problem, we were able to deduce the mass of Uranus using the given values of \(g\) and Uranus’s radius (\(R\)). Likewise, for Miranda, utilizing the formula \(a = G \frac{M_M}{r^2}\), we can calculate the acceleration due to Miranda's gravity at its surface, which in turn allows us to solve for its mass when \(a\) and \(r\) are known. This approach is critical for understanding not just individual celestial bodies but also their interactions and the mechanics of their orbits.

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Most popular questions from this chapter

At the Galaxy's Core. Astronomers have observed a small, massive object at the center of our Milky Way galaxy (see Section 13.8). A ring of material orbits this massive object; the ring has a diameter of about 15 light-years and an orbital speed of about \(200 \mathrm{~km} / \mathrm{s}\) (a) Determine the mass of the object at the center of the Milky Way galaxy. Give your answer both in kilograms and in solar masses (one solar mass is the mass of the sun). (b) Observations of stars, as well as theories of the structure of stars, suggest that it is impossible for a single star to have a mass of more than about 50 solar masses. Can this massive object be a single, ordinary star? (c) Many astronomers believe that the massive object at the center of the Milky Way galaxy is a black hole. If so, what must the Schwarzschild radius of this black hole be? Would a black hole of this size fit inside the earth's orbit around the sun?

What is the escape speed from a \(300-\mathrm{km}\) -diameter asteroid with a density of \(2500 \mathrm{~kg} / \mathrm{m}^{3} ?\)

The acceleration due to gravity at the north pole of Neptune is approximately \(11.2 \mathrm{~m} / \mathrm{s}^{2} .\) Neptune has mass \(1.02 \times 10^{26} \mathrm{~kg}\) and radius \(2.46 \times 10^{4} \mathrm{~km}\) and rotates once around its axis in about \(16 \mathrm{~h}\). (a) What is the gravitational force on a \(3.00 \mathrm{~kg}\) object at the north pole of Neptune? (b) What is the apparent weight of this same object at Neptune's equator? (Note that Neptune's "surface" is gaseous, not solid, so it is impossible to stand on it.)

A rocket with mass \(5.00 \times 10^{3} \mathrm{~kg}\) is in a circular orbit of radius \(7.20 \times 10^{6} \mathrm{~m}\) around the earth. The rocket's engines fire for a period of time to increase that radius to \(8.80 \times 10^{6} \mathrm{~m},\) with the orbit again circular. (a) What is the change in the rocket's kinetic energy? Does the kinetic energy increase or decrease? (b) What is the change in the rocket's gravitational potential energy? Does the potential energy increase or decrease? (c) How much work is done by the rocket engines in changing the orbital radius?

DATA For a spherical planet with mass \(M,\) volume \(V,\) and radius \(R,\) derive an expression for the acceleration due to gravity at the planet's surface, \(g\), in terms of the average density of the planet, \(\rho=M / V,\) and the planet's diameter, \(D=2 R .\) The table gives the values of \(D\) and \(g\) for the eight major planets: $$ \begin{array}{lrc} \text { Planet } & D(\mathrm{~km}) & g\left(\mathrm{~m} / \mathrm{s}^{2}\right) \\ \hline \text { Mercury } & 4879 & 3.7 \\ \text { Venus } & 12,104 & 8.9 \\ \text { Earth } & 12,756 & 9.8 \\ \text { Mars } & 6792 & 3.7 \\ \text { Jupiter } & 142,984 & 23.1 \\ \text { Saturn } & 120,536 & 9.0 \\ \text { Uranus } & 51,118 & 8.7 \\ \text { Neptune } & 49.528 & 11.0 \end{array} $$ (a) Treat the planets as spheres. Your equation for \(g\) as a function of \(\rho\) and \(D\) shows that if the average density of the planets is constant, a graph of \(g\) versus \(D\) will be well represented by a straight line. Graph 8 as a function of \(D\) for the eight major planets. What does the graph tell you about the variation in average density? (b) Calculate the average density for each major planet. List the planets in order of decreasing density, and give the calculated average density of each. (c) The earth is not a uniform sphere and has greater density near its center. It is reasonable to assume this might be true for the other planets. Discuss the effect this has on your analysis. (d) If Saturn had the same average density as the earth, what would be the value of \(g\) at Saturn's surface?

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