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What gauge pressure is required in the city water mains for a stream from a fire hose connected to the mains to reach a vertical height of \(15.0 \mathrm{~m} ?\) (Assume that the mains have a much larger diameter than the fire hose.

Short Answer

Expert verified
The required gauge pressure in the city water mains for the water to reach a height of 15.0 m is 147,000 Pa.

Step by step solution

01

Identify known quantities

The height that the water mains need to reach is \(15.0 m\). The acceleration due to gravity (\(g\)) is \(9.8 m/s^2\).
02

Apply Bernoulli's equation

Bernoulli's principle states that the sum of the potential energy, the kinetic energy, and the fluid pressure of a fluid system is constant. As we're looking at the stream at its highest point, the kinetic energy will be 0 and we can apply Bernoulli’s equation in the following form for fluid leaving the hose: \(P + \frac{1}{2} \rho v^2 + \rho gh = constant\). In this case, let one point be in the hose where pressure is \(P\), elevation is 0 (for simplicity), and velocity \(v\) will be large because the hose is a lot narrower than the water mains. The other point is at the top of the water stream, where pressure is atmospheric pressure, velocity is essentially 0, and elevation is \(h\). Thus, the equation can be written as \(P + \frac{1}{2} \rho v^2 = P_{atm} + \rho gh\).
03

Solve for Pressure

Rewrite the equation to solve for \(P\). This gives us: \(P = P_{atm} + \rho gh - \frac{1}{2} \rho v^2\). Since the velocity \(v\) in the mains is much less than in the hose we can ignore its contribution. This simplifies the equation to: \(P = P_{atm} + \rho gh\). Because we are looking for gauge pressure, that is pressure in excess of atmospheric pressure, we ignore \(P_{atm}\) resulting in: \(P = \rho gh\).
04

Substitute values and solve

Substitute the given height and the density of water (\(1000 kg/m^3\)) into the equation: \(P = 1000 kg/m^3 * 9.8 m/s^2 * 15 m = 147000 Pa\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gauge Pressure Calculation
Understanding gauge pressure is crucial when solving many fluid mechanics problems, especially those related to fluid flow in pipes or hoses, like in the exercise concerning the water stream from a fire hose.

Gauge pressure is the pressure of a system above atmospheric pressure. In fluid dynamics, when we speak about pressure in pipes or hoses, we often refer to gauge pressure. This is because the operation of such fluid systems is influenced by the pressure difference between the inside and the outside atmosphere, not the absolute pressure.

When calculating gauge pressure, we take the absolute pressure and subtract the atmospheric pressure (\(P_{atm}\)). Since atmospheric pressure acts on all sides of a fluid system, it doesn’t contribute to the flow of fluid within the system, which is why it’s removed from equations in these problems. The gauge pressure is thus given by the equation: \[P_{gauge} = P - P_{atm}\] where \(P\) is the absolute pressure.

In the context of fluid reaching a certain height, we only consider the gauge pressure that is required to push the water to that height against gravity, ignoring the atmospheric pressure. Hence, in the exercise, the final gauge pressure needed for the water stream to reach 15 meters vertically was calculated by considering only the product of the fluid density (\(\rho\rho gh\)) because the atmospheric pressure cancels out when we assess gauge pressure.
Fluid Mechanics
Fluid mechanics is the branch of physics concerned with the behavior of fluids at rest (fluid statics) and in motion (fluid dynamics). It is fundamental in understanding how fluids behave under various forces and in different conditions, and it is particularly essential in applications like hydraulic systems, aeronautics, and many engineering tasks.

In the case of our exercise, where we are determining the pressure needed for a water stream from a fire hose to reach a certain height, fluid mechanics principles guide us to use Bernoulli’s equation, which is one of the key equations in fluid dynamics. This equation relates the velocity, pressure, and height of a fluid flow in an idealized scenario to describe conservation of energy in a flowing fluid.

Understanding the relationship between these factors allows us to infer that if the kinetic energy of the fluid at the top of the stream is zero (because the velocity is zero), the energy must be present as gravitational potential energy and pressure energy. Thus, the gauge pressure in the mains must be enough to overcome gravitational forces and push the water to the desired height.
Height of Water Stream
The height a water stream reaches when emitted from a hose or nozzle involves the interplay of several physical principles. In this exercise, we were tasked with determining the necessary gauge pressure to achieve a vertical stream height of 15 meters.

The fluid's exit speed, the angle of release, and the surrounding air pressure all influence the height of the stream. Bernoulli's equation assists in correlating these variables by indicating that as the stream rises, kinetic energy is converted into potential energy. As the fluid rises and its velocity at the peak reaches zero, the kinetic energy term in Bernoulli's equation becomes negligible. At this peak height, the fluid has maximum gravitational potential energy.

It’s also vital to note that the pressure at the top of the stream, where the fluid has stopped moving, is equal to the atmospheric pressure, because the fluid is exposed to the atmosphere and is at rest. Therefore, accounting for these conditions in our fluid mechanics exercise can provide a clearer picture of the factors that determine how high a water stream can reach.

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Most popular questions from this chapter

You are doing experiments from a research ship in the Atlantic Ocean. On a day when the atmospheric pressure at the surface of the water is \(1.03 \times 10^{5} \mathrm{~Pa}\), at what depth below the surface of the water is the absolute pressure (a) twice the pressure at the surface and (b) four times the pressure at the surface?

Scientists have found evidence that Mars may once have had an ocean \(0.500 \mathrm{~km}\) deep. The acceleration due to gravity on Mars is \(3.71 \mathrm{~m} / \mathrm{s}^{2}\). (a) What would be the gauge pressure at the bottom of such an ocean, assuming it was freshwater? (b) To what depth would you need to go in the earth's ocean to experience the same gauge pressure?

An ore sample weighs \(17.50 \mathrm{~N}\) in air. When the sample is suspended by a light cord and totally immersed in water, the tension in the cord is \(11.20 \mathrm{~N}\). Find the total volume and the density of the sample.

In intravenous feeding, a needle is inserted in a vein in the patient's arm and a tube leads from the needle to a reservoir of fluid (density \(\left.1050 \mathrm{~kg} / \mathrm{m}^{3}\right)\) located at height \(h\) above the arm. The top of the reservoir is open to the air. If the gauge pressure inside the vein is \(5980 \mathrm{~Pa}\), what is the minimum value of \(h\) that allows fluid to enter the vein? Assume the needle diameter is large enough that you can ignore the viscosity (see Section 12.6 ) of the fluid.

Water is flowing in a pipe with a varying cross-sectional area, and at all points the water completely fills the pipe. At point 1 the cross-sectional area of the pipe is \(0.070 \mathrm{~m}^{2},\) and the magnitude of the fluid velocity is \(3.50 \mathrm{~m} / \mathrm{s}\). (a) What is the fluid speed at points in the pipe where the cross-sectional area is (a) \(0.105 \mathrm{~m}^{2}\) and (b) \(0.047 \mathrm{~m}^{2}\) ? (c) Calculate the volume of water discharged from the open end of the pipe in 1.00 hour.

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