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A medical technician is trying to determine what percentage of a patient's artery is blocked by plaque. To do this, she measures the blood pressure just before the region of blockage and finds that it is \(1.20 \times 10^{4} \mathrm{~Pa}\), while in the region of blockage it is \(1.15 \times 10^{4} \mathrm{~Pa}\). Furthermore, she knows that blood flowing through the normal artery just before the point of blockage is traveling at \(30.0 \mathrm{~cm} / \mathrm{s}\), and the specific gravity of this patient's blood is 1.06 . What percentage of the cross-sectional area of the patient's artery is blocked by the plaque?

Short Answer

Expert verified
The percentage of cross-sectional area of the patient's artery blocked by plaque is determined using the principle of conservation of flow rate and the principle of conservation of energy in fluids, and requires calculation using the given measurements.

Step by step solution

01

Calculate the velocity in the blocked region

First, using Bernoulli's Principle, we can equate the sum of the pressure energy and kinetic energy before and at the point of the blockage. Mathematically this is done by: \( P1 + 1/2蟻v_1^2 = P2 + 1/2蟻v_2^2 \), where P1 and v1 are the pressure and velocity before blockage, P2 is the pressure at blockage, 蟻 is the blood's density and v2 is the velocity at blockage that we need to find. We find 蟻 by multiplying the specific gravity by the water's density (1000 kg/m^3). Replacing the values and solving for v2 gives us the velocity at blockage.
02

Calculating the percentage of blocked area

We can find the percentage of blocked area by first understanding that the volume flow rate (Q) is the same before and at the point of blockage. Volume flow rate is given by Q = Av, where A is the cross-sectional area and v is the velocity. Therefore, A1v1 = A2v2, where A2 is the cross-sectional area at the point of blockage. Solving this equation for A2/A1 gives us the fraction of area that is not blocked. Subtract this from 1 to find the fraction of area that is blocked and then multiply it by 100 to get the percentage of blocked area.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Blood Flow Dynamics
Understanding blood flow dynamics is crucial when assessing cardiovascular health. Blood flow within our circulatory system is governed by principles similar to those that dictate fluid mechanics, including velocity, pressure, and cross-sectional area of the vessels.

Blood moves from areas of higher pressure to lower pressure, propelled by the contraction of the heart. As blood flows through vessels, its velocity changes depending on the vessel's diameter. In a healthy artery, blood speed is constant; however, when a blockage occurs, such as plaque buildup, the blood flow is disrupted. According to the principle of continuity, the volume flow rate must be conserved, so if an artery is partially blocked, the blood must speed up to maintain the flow rate.

To dig deeper, consider a normal, unblocked artery. Here, blood flow is stable and the pressure is relatively uniform. When an obstruction like plaque narrows the artery, blood is forced through a smaller opening. Hospitals use high-tech imaging and calculations to measure these changes and assess the blockage's impact on blood flow dynamics, largely influenced by Bernoulli's Principle.
Pressure Difference in Blood Vessels
The pressure difference in blood vessels is a significant indicator for diagnosing and evaluating the severity of cardiovascular obstructions such as stenosis. Normally, blood pressure should gradually decrease as it travels through the circulatory system due to viscous losses and distance from the heart.

In the context of Bernoulli's Principle, as blood flows through a constricted region of an artery caused by plaque, its velocity increases which should correspond to a decrease in pressure. This is counterintuitive for many because narrowing of the vessels might seem like it would increase pressure. However, Bernoulli's Principle shows us that where the speed increases, the pressure drops. This decrease in pressure can be measured, and the difference in pressure before and after the blockage can help determine the extent of the blockage. For example, taking measurements right before and within the blockage region, as seen in our exercise, allows us to use the pressure differential to solve for variables that indicate the blockage's severity.
Artery Blockage Calculation
In a medical setting, calculating artery blockage is a life-saving procedure. The data from pressure measurements and blood velocities can be applied to Bernoulli's equation to estimate the extent of a blockage without invasive procedures.

The calculation of artery blockage uses the concept of volume flow rate conservation (A1v1 = A2v2) and involves comparing the blood flow in a normal section of the artery with the flow at the blockage point. By rearranging Bernoulli's equation to solve for the velocity of blood in the blocked section and then using the continuity equation, we derive the cross-sectional area ratio of the blockage to the artery. The exercise provided shows how this calculation is made step by step. The outcome provides medical professionals with a percentage that indicates how much of the artery's cross-sectional area is occluded by plaque, which is vital information for treatment planning.

Healthcare providers rely on this sort of analysis to make educated decisions about the necessity and urgency of interventions like angioplasty or bypass surgery, demonstrating the critical application of physics in medical diagnostics.

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Most popular questions from this chapter

Your uncle is in the below-deck galley of his boat while you are spear fishing in the water nearby. An errant spear makes a small hole in the boat's hull, and water starts to leak into the galley. (a) If the hole is \(0.900 \mathrm{~m}\) below the water surface and has area \(1.20 \mathrm{~cm}^{2},\) how long does it take \(10.0 \mathrm{~L}\) of water to leak into the boat? (b) Do you need to take into consideration the fact that the boat sinks lower into the water as water leaks in?

A pressure difference of \(6.00 \times 10^{4} \mathrm{~Pa}\) is required to maintain a volume flow rate of \(0.800 \mathrm{~m}^{3} / \mathrm{s}\) for a viscous fluid flowing through a section of cylindrical pipe that has radius \(0.210 \mathrm{~m}\). What pressure difference is required to maintain the same volume flow rate if the radius of the pipe is decreased to \(0.0700 \mathrm{~m} ?\)

A hollow plastic sphere is held below the surface of a freshwater lake by a cord anchored to the bottom of the lake. The sphere has a volume of \(0.650 \mathrm{~m}^{3}\) and the tension in the cord is \(1120 \mathrm{~N}\). (a) Calculate the buoyant force exerted by the water on the sphere. (b) What is the mass of the sphere? (c) The cord breaks and the sphere rises to the surface. When the sphere comes to rest, what fraction of its volume will be submerged?

On the afternoon of January \(15,1919,\) an unusually warm day in Boston, a 17.7 -m-high, 27.4-m-diameter cylindrical metal tank used for storing molasses ruptured. Molasses flooded into the streets in a 5-m-deep stream, killing pedestrians and horses and knocking down buildings. The molasses had a density of \(1600 \mathrm{~kg} / \mathrm{m}^{3}\). If the tank was full before the accident, what was the total outward force the molasses exerted on its sides? (Hint: Consider the outward force on a circular ring of the tank wall of width \(d y\) and at a depth \(y\) below the surface. Integrate to find the total outward force. Assume that before the tank ruptured, the pressure at the surface of the molasses was equal to the air pressure outside the tank.)

You are doing experiments from a research ship in the Atlantic Ocean. On a day when the atmospheric pressure at the surface of the water is \(1.03 \times 10^{5} \mathrm{~Pa}\), at what depth below the surface of the water is the absolute pressure (a) twice the pressure at the surface and (b) four times the pressure at the surface?

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