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An ore sample weighs \(17.50 \mathrm{~N}\) in air. When the sample is suspended by a light cord and totally immersed in water, the tension in the cord is \(11.20 \mathrm{~N}\). Find the total volume and the density of the sample.

Short Answer

Expert verified
The volume of the ore sample is 0.00064 cubic meters and its density is 27343.75 kilograms per cubic meter.

Step by step solution

01

Calculate the Buoyant Force

The buoyant force can be calculated by finding the difference between the weight of the object in air and the apparent weight of the object in water. The formula is \(F_b = Weight_{air} - Weight_{water}\). So, \(F_b = 17.50N - 11.20N = 6.3N\)
02

Calculate the Volume of the Sample

The buoyant force is equal to the weight of the water displaced by the sample. To find the volume of displaced water, which equals the volume of the sample, use the formula \(Volume= \frac{F_b}{density_{water} \cdot g}\), where \(g\) is the acceleration due to gravity (approximately \(9.8 m/s^2\)), and the density of water is approximated to \(1000 kg/m^3\). Therefore, \(Volume = \frac{6.3N}{1000 kg/m^3 * 9.8 m/s^2} = 0.00064 m^3\).
03

Calculate the Density of the Sample

The density of the sample can be determined by dividing its weight by its volume. The formula is \(Density = \frac{Weight_{air}}{Volume} = \frac{17.50N}{0.00064 m^3} = 27343.75 kg/m^3\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Physics Problem Solving
Physics problems, such as calculating the buoyant force on a submerged object, often involve a multi-step process that requires understanding of fundamental principles and the ability to apply them in a systematic way.

During problem-solving, it's crucial first to identify what is sought and then determine what is given. In the ore sample question, we start by looking for the buoyant force which is a stepping stone to further calculations. We recognize this force as the key to unlocking the volume and density of the sample.

  • Identify the Concepts: Understand that buoyant force is the force exerted by a fluid that opposes an object's weight.
  • List Known Variables: Here we know the weights in air and water, and we have constants like the density of water and gravitational acceleration.
  • Apply Relevant Formulas: Use formulas like the one for buoyant force, \( F_b = Weight_{air} - Weight_{water} \), to start with.
  • Carry out Calculations: Perform step-by-step calculations to find volume and density thereafter.
  • Check Results: Finally, verify the calculations against physical reality to ensure they make sense.

Breaking problems down in this way makes them more manageable and helps to avoid oversights and mistakes.
Density Calculation
Density is a fundamental concept in physics that represents the mass per unit volume of a substance. The formula to calculate the density (\( \rho \)) of an object is: \( \rho = \frac{mass}{volume} \).

However, when the mass is not directly known, as in the ore sample problem, we can substitute mass with weight divided by the acceleration due to gravity (\( g \)), realizing that weight is mass affected by gravity: \( \rho = \frac{Weight}{g \cdot Volume} \).

Practical Considerations for Density Calculation

When dealing with real-world objects, remember that:
  • The object's weight must be measured or given.
  • The volume can sometimes be calculated indirectly, like in this exercise where we find it through buoyant force.
  • Units must be consistent to avoid errors in calculation.
  • Measuring instruments and conditions (like temperature and pressure) can affect density, so consider these factors when precision is paramount.
Understanding how to manipulate the density formula is crucial for solving a variety of physics problems.
Archimedes' Principle
Archimedes' Principle is a key concept when calculating buoyant forces. It states that the upward buoyant force exerted on an object completely or partially submerged in a fluid is equal to the weight of the fluid that the object displaces.

This principle is what allows the calculation of buoyancy in the ore sample problem. According to Archimedes' Principle, the buoyant force on the ore sample can be found by determining the weight of the volume of water displaced when the ore is fully submerged.

Application in Calculations

The principle allows us to set up equations where the buoyant force (\( F_b \)) equals the weight of the displaced fluid, leading to the formula \( F_b = density_{fluid} \cdot volume_{displaced} \cdot g \).
  • This formula is the basis for finding the volume of the sample since the weight of the displaced water has the same magnitude as the buoyant force acting on the ore.
  • Once the volume is known, we can easily work out the density of the sample.
Understanding how Archimedes' Principle applies to real-world scenarios aids in comprehending the behavior of objects in fluids and is a cornerstone of fluid mechanics.

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Most popular questions from this chapter

A gallon of milk in a full plastic jug is sitting on the edge of your kitchen table. Estimate the vertical distance between the top surface of the milk and the bottom of the jug. Also estimate the distance from the tabletop to the floor. You punch a small hole in the side of the jug just above the bottom of the jug, and milk flows out the hole. When the milk first starts to flow out the hole, what horizontal distance does it travel before reaching the floor? Assume the milk is in free fall after it has passed through the hole, and neglect the viscosity of the milk.

At a certain point in a horizontal pipeline, the water's speed is \(2.50 \mathrm{~m} / \mathrm{s}\) and the gauge pressure is \(1.80 \times 10^{4} \mathrm{~Pa}\). Find the gauge pressure at a second point in the line if the cross-sectional area at the second point is twice that at the first.

On another planet that you are exploring, a large tank is open to the atmosphere and contains ethanol. A horizontal pipe of cross sectional area \(9.0 \times 10^{-4} \mathrm{~m}^{2}\) has one end inserted into the tank just above the bottom of the tank. The other end of the pipe is open to the atmosphere. The viscosity of the ethanol can be neglected. You measure the volume flow rate of the ethanol from the tank as a function of the depth \(h\) of the ethanol in the tank. If you graph the volume flow rate squared as a function of \(h,\) your data lie close to a straight line that has slope \(1.94 \times 10^{-5} \mathrm{~m}^{5} / \mathrm{s}^{2} .\) What is the value of \(g,\) the acceleration of a free-falling object at the surface of the planet?

A firehose must be able to shoot water to the top of a building \(28.0 \mathrm{~m}\) tall when aimed straight up. Water enters this hose at a steady rate of \(0.500 \mathrm{~m}^{3} / \mathrm{s}\) and shoots out of a round nozzle. Neglect air resistance. (a) What is the maximum diameter this nozzle can have? (b) If the only nozzle available has a diameter twice as great, what is the highest point the water can reach?

What gauge pressure is required in the city water mains for a stream from a fire hose connected to the mains to reach a vertical height of \(15.0 \mathrm{~m} ?\) (Assume that the mains have a much larger diameter than the fire hose.

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