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An ore sample weighs \(17.50 \mathrm{~N}\) in air. When the sample is suspended by a light cord and totally immersed in water, the tension in the cord is \(11.20 \mathrm{~N}\). Find the total volume and the density of the sample.

Short Answer

Expert verified
The volume of the ore sample is 0.00064 cubic meters and its density is 27343.75 kilograms per cubic meter.

Step by step solution

01

Calculate the Buoyant Force

The buoyant force can be calculated by finding the difference between the weight of the object in air and the apparent weight of the object in water. The formula is \(F_b = Weight_{air} - Weight_{water}\). So, \(F_b = 17.50N - 11.20N = 6.3N\)
02

Calculate the Volume of the Sample

The buoyant force is equal to the weight of the water displaced by the sample. To find the volume of displaced water, which equals the volume of the sample, use the formula \(Volume= \frac{F_b}{density_{water} \cdot g}\), where \(g\) is the acceleration due to gravity (approximately \(9.8 m/s^2\)), and the density of water is approximated to \(1000 kg/m^3\). Therefore, \(Volume = \frac{6.3N}{1000 kg/m^3 * 9.8 m/s^2} = 0.00064 m^3\).
03

Calculate the Density of the Sample

The density of the sample can be determined by dividing its weight by its volume. The formula is \(Density = \frac{Weight_{air}}{Volume} = \frac{17.50N}{0.00064 m^3} = 27343.75 kg/m^3\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Physics Problem Solving
Physics problems, such as calculating the buoyant force on a submerged object, often involve a multi-step process that requires understanding of fundamental principles and the ability to apply them in a systematic way.

During problem-solving, it's crucial first to identify what is sought and then determine what is given. In the ore sample question, we start by looking for the buoyant force which is a stepping stone to further calculations. We recognize this force as the key to unlocking the volume and density of the sample.

  • Identify the Concepts: Understand that buoyant force is the force exerted by a fluid that opposes an object's weight.
  • List Known Variables: Here we know the weights in air and water, and we have constants like the density of water and gravitational acceleration.
  • Apply Relevant Formulas: Use formulas like the one for buoyant force, \( F_b = Weight_{air} - Weight_{water} \), to start with.
  • Carry out Calculations: Perform step-by-step calculations to find volume and density thereafter.
  • Check Results: Finally, verify the calculations against physical reality to ensure they make sense.

Breaking problems down in this way makes them more manageable and helps to avoid oversights and mistakes.
Density Calculation
Density is a fundamental concept in physics that represents the mass per unit volume of a substance. The formula to calculate the density (\( \rho \)) of an object is: \( \rho = \frac{mass}{volume} \).

However, when the mass is not directly known, as in the ore sample problem, we can substitute mass with weight divided by the acceleration due to gravity (\( g \)), realizing that weight is mass affected by gravity: \( \rho = \frac{Weight}{g \cdot Volume} \).

Practical Considerations for Density Calculation

When dealing with real-world objects, remember that:
  • The object's weight must be measured or given.
  • The volume can sometimes be calculated indirectly, like in this exercise where we find it through buoyant force.
  • Units must be consistent to avoid errors in calculation.
  • Measuring instruments and conditions (like temperature and pressure) can affect density, so consider these factors when precision is paramount.
Understanding how to manipulate the density formula is crucial for solving a variety of physics problems.
Archimedes' Principle
Archimedes' Principle is a key concept when calculating buoyant forces. It states that the upward buoyant force exerted on an object completely or partially submerged in a fluid is equal to the weight of the fluid that the object displaces.

This principle is what allows the calculation of buoyancy in the ore sample problem. According to Archimedes' Principle, the buoyant force on the ore sample can be found by determining the weight of the volume of water displaced when the ore is fully submerged.

Application in Calculations

The principle allows us to set up equations where the buoyant force (\( F_b \)) equals the weight of the displaced fluid, leading to the formula \( F_b = density_{fluid} \cdot volume_{displaced} \cdot g \).
  • This formula is the basis for finding the volume of the sample since the weight of the displaced water has the same magnitude as the buoyant force acting on the ore.
  • Once the volume is known, we can easily work out the density of the sample.
Understanding how Archimedes' Principle applies to real-world scenarios aids in comprehending the behavior of objects in fluids and is a cornerstone of fluid mechanics.

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Most popular questions from this chapter

In intravenous feeding, a needle is inserted in a vein in the patient's arm and a tube leads from the needle to a reservoir of fluid (density \(\left.1050 \mathrm{~kg} / \mathrm{m}^{3}\right)\) located at height \(h\) above the arm. The top of the reservoir is open to the air. If the gauge pressure inside the vein is \(5980 \mathrm{~Pa}\), what is the minimum value of \(h\) that allows fluid to enter the vein? Assume the needle diameter is large enough that you can ignore the viscosity (see Section 12.6 ) of the fluid.

On another planet that you are exploring, a large tank is open to the atmosphere and contains ethanol. A horizontal pipe of cross sectional area \(9.0 \times 10^{-4} \mathrm{~m}^{2}\) has one end inserted into the tank just above the bottom of the tank. The other end of the pipe is open to the atmosphere. The viscosity of the ethanol can be neglected. You measure the volume flow rate of the ethanol from the tank as a function of the depth \(h\) of the ethanol in the tank. If you graph the volume flow rate squared as a function of \(h,\) your data lie close to a straight line that has slope \(1.94 \times 10^{-5} \mathrm{~m}^{5} / \mathrm{s}^{2} .\) What is the value of \(g,\) the acceleration of a free-falling object at the surface of the planet?

Water is flowing in a pipe with a varying cross-sectional area, and at all points the water completely fills the pipe. At point 1 the cross-sectional area of the pipe is \(0.070 \mathrm{~m}^{2},\) and the magnitude of the fluid velocity is \(3.50 \mathrm{~m} / \mathrm{s}\). (a) What is the fluid speed at points in the pipe where the cross-sectional area is (a) \(0.105 \mathrm{~m}^{2}\) and (b) \(0.047 \mathrm{~m}^{2}\) ? (c) Calculate the volume of water discharged from the open end of the pipe in 1.00 hour.

A cubical block of density \(\rho_{\mathrm{B}}\) and with sides of length \(L\) floats in a liquid of greater density \(\rho_{\mathrm{L}}\). (a) What fraction of the block's volume is above the surface of the liquid? (b) The liquid is denser than water (density \(\rho_{\mathrm{W}}\) ) and does not mix with it. If water is poured on the surface of that liquid, how deep must the water layer be so that the water surface just rises to the top of the block? Express your answer in terms of \(L, \rho_{\mathrm{B}}, \rho_{\mathrm{L}},\) and \(\rho_{\mathrm{W}}\). (c) Find the depth of the water layer in part (b) if the liquid is mercury, the block is made of iron, and \(L=10.0 \mathrm{~cm}\).

A uniform lead sphere and a uniform aluminum sphere have the same mass. What is the ratio of the radius of the aluminum sphere to the radius of the lead sphere?

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