91影视

The length of the pipe is given as $\mathit{L}\mathbf{=}\mathit{v}\mathbf{4}{\mathit{f}}_{\mathbf{1}}$were. ${\mathit{f}}_{\mathbf{1}}$is the fundamental frequency of an organ pipe, V is the speed of the sound, L is length of the pipe.

The new speed of the sound for the original temperature is ${\mathit{v}}^{\mathbf{\text{'}}}\mathbf{=}\mathbf{4}\mathit{f}\mathit{L}$were, v' is the new speed of the sound for the original temperature, F is the frequency.

The fundamental frequency of an organ pipe is 349 Hz and the speed of the sound is 344 Substitute 349 Hz for $f_1$ and 344${\mathrm{ms}}^{-1}$for v to find the L

$\mathrm{L}=344脳4脳349=0.246\mathrm{m}$

Thus, the length of the pipe for the given fundamental note is 0.246 m

The frequency of fundamental note is 370 Hz, The new speed of the sound for the original temperature is $v^{\text{'}}=4fL$Substitute 370 Hz for f and 0.246 m for L to find the v'

${\mathrm{v}}^{\text{'}}=4\left(370\right)(0.246)=364.08{\mathrm{ms}}^{-1}$

Formula to calculate air temperature corresponding to the pitch is

Substitute 364.08 $\mathrm{T}={\mathrm{v}}^{\text{'}}-\mathrm{v}0.6{\mathrm{ms}}^{-1}$ for v' and 344 ${\mathrm{ms}}^{-1}$for v to find T

role="math" localid="1664346666978" $$\begin{gathered} \mathrm{T}=364.08-344 \\ =35.5^{0}C \end{gathered}$$

Therefore, the air temperature corresponding the pitch is$35.5^{0}C$