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Two organ pipes, open at one end but closed at the other, are each 1.14m long. One is now lengthened by 2.00 cm . Find the beat frequency that they produce when playing together in their fundamentals.

Short Answer

Expert verified

The beat frequency came out to be 1.3 H³ú.

Step by step solution

01

Given Data

The length of the pipe is-1.14​â¶Ä³¾

Increase in length- 2.00 c³¾

02

Formula of fundamental frequency

The formula of fundamental frequency is f=vλ.

As pipes are closed from the other end, λ=4L .

03

Calculate the beat frequency

Beat frequency can be expressed asf=v41L1−1L2 .

f=v411.14″¾âˆ’11.16″¾f=344″¾/s4×0.02″¾1.14″¾â€‰Ã—1.16″¾f=1.3 H³ú

So, the beat frequency is1.3 H³ú .

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