91Ó°ÊÓ

The specific heat of the solid phase depends on temperature.

The relationship between the mass, temperature, and heat is given as follows.

\(Q = mc\Delta T\) …… (i)

Here,\(Q\)is the heat transfer,\(m\)is the mass,\(c\)is the specific heat and\(\Delta T\)is the change in the temperature between room temperature and freezing point of the cryoprotectant.

Derive the expression for the specific heat from the equation (i).

\(c = \frac{Q}{{m\Delta T}}\) …… (ii).

Let's assume the mass and change in the temperature is constant. Therefore, the specific heat depends on the generated heat.

Since the value of the specific heat is less then the average specific heat (from the table: \(2 \times {10^3}\;{{\rm{J}} \mathord{\left/{\vphantom {{\rm{J}} {{\rm{kg}} \cdot {\rm{K}}}}} \right.\\} {{\rm{kg}} \cdot {\rm{K}}}}\)). The less amount of the heat is required to for cryoprotectant to come to equilibrium with the cold plate. Therefore, the time required for cryoprotectant to come to equilibrium with the cold plate will be shorter.