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Before going in for his annual physical, a 70.0 kg man whose body temperature is 37.0°C consumes an entire 12.0°C can of a soft drink (mostly water) at . (a) What will his body temperature be after equilibrium is attained? Ignore any heating by the man’s metabolism. The specific heat of the man’s body is 3480 Jkg⋅K. (b) Is the change in his body temperature great enough to be measured by a medical thermometer?

Short Answer

Expert verified

a) The temperature of the body after thermal equilibrium is 36.85 °C.

b) Yes, if the thermometer is very sensitive to the change in the temperature with 0.15°C.

Step by step solution

01

Given  Data

mass of man: mbody=70 kg

temperature of man: T1body=370C

volume of can: V=0.355 L

mass of water in can: mw=0.355kg

temperature of water: T1w=12 0C

specific heat of man’s body: Cbody=3480 J/kg0C

02

Heat energy equation at equilibrium

If no external heat energy is involved, then, at equilibrium, the sum total of all the changes in heat energy is equal to zero.

03

Use the heat energy equation to find the final temperature

Given that mbody=70 kg and T1body=37 0C. Volume of water is V=0.355 L and its density is1 kgl. So, this means that mw=0.355 kg. Also given that T1w=120C and Cbody=3480 Jkg0C.

According to the heat energy equation at equilibrium

mb×Cb×δ°Õb=-mw×Cw×δ°ÕwmbCb(T-Tb)=-mwCw(T-Tw)T=(mbCbTb+mwCwTw)(mbCb+mwCw)

Substituting values, we get

T=70kg×3480J/kg°C×37°C+0.355kg×4190J/kg°C×12°C70kg×3480J/kg°C×37°C0.355kg×4190J/kg°C×12°C=36.85°C

The decrease in temperature is

∆T=37°C-36.85°C=0.15°C

04

Temperature change and medical thermometers

The thermometers are designed according to the sensitivity to the temperature change. Such a small change in the temperature can be measured by a thermometer if it is very sensitive to the temperature changes.

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