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In a diffraction experiment with waves of wavelength ,there will be no intensity minima (that is, no dark fringes) if the slit width is small enough. What is the maximum slit width for which this occurs? Explain your answer.

Short Answer

Expert verified

When maximum slit width is equal to wavelength of light, there will be no minima.

Step by step solution

01

Define single slit diffraction

When monochromatic light sent through a narrow slit, produces a diffraction pattern on a distant screen which is single slit diffraction.

Condition of dark fringes (destructive interference) in single slit diffraction is as follow,

补蝉颈苍胃=苍位

Where is slit width, is the diffraction angle of minima; is the order of minima andis wavelength of the light.

02

Determine no minima condition

If the diffraction angle for 1st minima is 90then there will be no minima in field of view as for 1st minima diffracted light become parallel to slit and screen.

No minima occur when=90 . From this one can say,

asin90=1a=

The above equation is the criterion for 鈥渘o-minima鈥.

Therefore, Maximum slit width for which there will be no minima is equal to the wavelength of light.

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