/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q2E The vitreous humor, a transparen... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 5: Q2E (page 1105)

The vitreous humor, a transparent, gelatinous fluid that fills most of the eyeball, has an index of refraction of 1.34. Visible light ranges in wavelength from 380 nm (violet) to 750 nm (red), as measured in air. This light travels through the vitreous humor and strikes the rods and cones at the surface of the retina. What are the ranges of (a) the wavelength, (b) the frequency, and (c) the speed of the light just as it approaches the retina within the vitreous humor?

Short Answer

Expert verified
  1. The range of the wavelength is from 284 nm to 560 nm .
  2. The range of the frequency is from 4.00脳1014Hzto 7.89脳1014Hz.
  3. The speed of the light as it approaches the retina is 2.24脳108m/s.

Step by step solution

01

(a) Determination of wavelength.

The speed changes, so the wavelength also changes accordingly.

The refractive index n = 1.34 . So the shift in wavelength is,

For vitreous humour,

位v=位0,vn=380nm1.34=284nm

For retina,

位v=位0,rn=750nm1.34=560nm

Thus, the range of wavelength is from 284 nm to 560 nm

02

(b) Determination of the frequency.

The frequency expression is,

f=v位

The frequency in air with v=c=3脳108m/s,

fr=c位r=3.00脳108m/s750脳10-9m=4.00脳1014Hz

The frequency for vitreous humour,

fr=c位v=3.00脳108m/s750脳10-9m=7.89脳1014Hz

Thus, the frequency ranges from 4.00脳1014Hzto 7.89脳1014Hz.

03

(c) Determination of the speed of light as it approaches the retina.

The expression for the speed is,

v=cn

Substitute all the values in the above equation,

v=3.00脳108m/s1.34=2.24脳108m/s

Thus, the speed with which light reaches the retina is2.24脳108m/s

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Short-wave radio antennas A and B are connected to the same transmitter and emit coherent waves in phase and with the same frequency f . You must determine the value of f and the placement of the antennas that produce a maximum intensity through constructive interference at a receiving antenna that is located at point P, which is at the corner of your garage. First you place antenna A at a point 240.0 m due east of P. Next you place antenna B on the line that connects A and P, a distance x due east of P, where x<240.0 m. Then you measure that a maximum in the total intensity from the two antennas occurs when x=210.0 m, 216.0 m, and 222.0 m. You don鈥檛 investigate smaller or larger values of x. (Treat the antennas as point sources.) (a) What is the frequency f of the waves that are emitted by the antennas? (b) What is the greatest value of x, with x<240.0 m, for which the interference at P is destructive?

Two radio antennas A and B radiate in phase. Antenna B is 120 m to the right of antenna A. Consider point Q along the extension of the line connecting the antennas, a horizontal distance of 40 m to the right of antenna B. The frequency, and hence the wavelength, of the emitted waves can be varied. (a) What is the longest wavelength for which there will be destructive interference at point Q? (b) What is the longest wavelength for which there will be constructive interference at point Q?

34.19 A person swimming 0.80cm below the surface of the water in a swimming pool looks at the diving board that is directly overhead and sees the image of the board that is formed by refraction at the surface of the water. This image is a height of 5.20 m above the swimmer. What is the actual height of the diving board above the surface of the water?

A spherical, concave shaving mirror has a radius of curvature of 32.0 cm. (a) What is the magnification of a person鈥檚 face when it is 12.0 cmto the left of the vertex of the mirror? (b) Where is the image? Is the image real or virtual? (c) Draw a principal-ray diagram showing the formation of the image.

Coherent light that contains two wavelengths, 660nm (red) and 470nm (blue), passes through two narrow slits that are separated by 0.300mm. Their interference pattern is observed on a screen 4.00m from the slits. What is the distance on the screen between the first-order bright fringes for the two wavelengths?
See all solutions

Recommended explanations on Physics Textbooks

Translational Dynamics

Read Explanation

Engineering Physics

Read Explanation

Kinematics Physics

Read Explanation

Physical Quantities And Units

Read Explanation

Oscillations

Read Explanation

Classical Mechanics

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.