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In a particle accelerator a proton moves with constant speed 0.75c in a circle of radius 628m . What is the net force on the proton?

Short Answer

Expert verified

F=2.04×10-13N

Step by step solution

01

NOT GIVEN

F is perpendicular to v ,

F=γma,

a=v2r,

γ=11-v2c2

From these relations, we will get

F=γmaF=γmv2rF=11-v2c2mv2rF=11-0.75×3×10823×1082×1.6276×10-27×0.75×3×1082628F=2.04×10-13N

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