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Chapter 1: Q8-20E (page 264)

You are standing on a sheet of ice that covers the football stadium parking lot in Buffalo; there is negligible friction between your feet and the ice. A friend throws you a0.600kg ball that is traveling horizontally at 10.0m/s. Your mass is 70.0kg. (a) If you catch the ball, with what speed do you and the ball move afterward? (b) If the ball hits you and bounces off your chest, so afterward it is moving horizontally at 8.0m/s in the opposite direction, what is your speed after the collision?

Short Answer

Expert verified

(a) The speed of you and ball move afterward is0.0849m/s.

(b) The speed after collision is 0.154m/s.

Step by step solution

01

Step 1:Given in the question:

Mass of ball is mA=0.400kg

Mass of yours mB=70.0kg

Let X be in the direction the ball is traveling initially.

02

 Step 2: Law of conservation of momentum:

When two bodies collide with each other then the total momentum before the collision is equal to the total momentum after the collision.

03

Step 3:(a) Speed of you and ball move afterward:

The speed of you and the ball move afterward is written as:

P1x=P2xmAv1=mA+mBv20.600脳10=0.600+70v26=70.6v2

v2=670.6=0.0849m/s

Hence,the speed of you and ball move afterward is0.0849m/s

04

(b) Speed after collision:

Here, the horizontal speed of ball when it hit you and bounces off your chest is v=8.0m/s.

The speed after collision is calculated as follows:

P1x=P2xmAv1=mAv+mBvB20.600脳10=0.600-8+70脳vB2

vB2=6+4.870=0.154m/s

Hence, the speed after collision is 0.154m/s.

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