91影视

The given data can be listed below as,

• The radius of Hurricane is,$r_1=350\mathrm{km}$.
• The near the center radius is,$r_2=30\mathrm{km}$.
• The wind speed is, $v_{wind}=200km/h$.

The total energy per unit mass of a fluid flowing at any point in its interior is the sum of the fluid's kinetic energy, potential energy, and pressure energy and is equal to a constant value.

The particular distance d from the axis, the angular momentum is express as,

$\mathrm{螕}=md$

The constancy of angular momentum, it is the product of the radius and speed is constant, it is express as,

$v_{\text{rim}}=v_{\text{wind}}\left(\frac{r_2}{r_1}\right)$

Substitute all the value in the above equation.

$\begin{array}{r}{v}_{rim}=200\mathrm{km}/\mathrm{h}脳\left(\frac{30\mathrm{km}}{350\mathrm{km}}\right)\\ =17.14\mathrm{km}/\mathrm{h}\end{array}$

Hence the wind speed at the rim of the hurricane is 17.14 km/h.

The pressure is lower at the eye. The water level is same then it is express as,

$$\begin{gathered} p_1+\frac{1}{2}蚁v\stackrel{2}{1}+蚁g{h}_1=p_2+\frac{1}{2}蚁v_2^2+蚁g{h}_2 \\ {p}_1-p_2=\frac{1}{2}{蚁}_{air}\left(v_3^2-v_2^2\right) \\ p=\frac{1}{2}{蚁}_{air}\left(v_3^2-v_2^2\right) \end{gathered}$$

Substitute all the value in the above equation.

$$\begin{gathered} p=\frac{1}{2}脳1.2kg/m^3\left({\left(2000km/h\right)}^2-{\left(17km/h\right)}^2\right){\left(\frac{1m/s}{3.6km/s}\right)}^2 \\ =1.83脳{10}^{3}Pa \end{gathered}$$

The kinetic energy of the swirling air in the eye could be converted completely to gravitational potential energy then it is express as,

$\begin{array}{l}v=\sqrt{2gh}\\ v^2=2gh\\ h=\frac{v^2}{2g}\end{array}$

Substitute all the value in the above equation.

$\frac{v^2}{2g}=160鈥�m$

Hence the high would air goes is, 160 m.

According to Bernoulli鈥檚 equation, if pressure decreases then the fluid velocity increases. The pressure distinction at better altitudes is even greater.