91Ó°ÊÓ

The given data can be expressed below as:

• The ball travels about 200 m.
• Both the first and the second motion of the ball occurred in 5.0 s.

This law illustrates that an object will continue to move in a uniform motion unless an external force acts upon the object.

The equation of velocity gives the acceleration of the ball and the equation of displacement gives the distance the ball rolled.

From the Newton’s first law, the equation of velocity of the ball is expressed as:

v = u + at

Here, v is the final velocity of the ball which is 150 m/s, u is the initial velocity of the ball which is zero as the ball was at rest and t is the time taken for rolling the ball.

Substituting the values in the above expression, we get-

$$\begin{gathered} 200m/s=0+\left(5.0s\right)a \\ a=40m/s^2 \end{gathered}$$

Hence, the equation of the displacement of the ball along a straight line is expressed as:

$s=ut+05a{t}^2$

Substituting the values in the above expression, we get-

$$\begin{gathered} s=0+0.5×40m/s^2×{\left(5\right)}^2 \\ =500m \end{gathered}$$

Thus, the ball rolled during the first of motion 500 m.