91Ó°ÊÓ

• The acceleration of the jet fighter pilot is 5g .
• The speed of the sound is $331m/s$.

This law describes that a body will continue to move at a uniform speed unless it is resisted by an external force.

The equation of the straight line may be beneficial for identifying the time required for the acceleration and speed of the jet fighter pilot.

Here,$v_x$is the speed of Mach 3 which is and which is$\text{3}×\left(\text{331m/s}\right)=\text{993m/s}$ the initial speed is 0 m/s. The acceleration of the jet fighter is,and the time taken for the fighter jet is 5s .

a) From Newton’s first law, the equation for the motion of the jet fighter is expressed as:

$$\begin{gathered} v_x=v_{ox}-a_{x}t \\ t=\frac{v_{x-v_{ox}}}{t} \end{gathered}$$

Substituting the values in the above expression, we get-

$\begin{array}{rcl}t& =& \frac{993m/s-0m/s}{49.0m/s^2}\\ & =& 20.3s\end{array}$

Thus, the time needed which last long enough to cause himto black out is 20.3s.

b) From Newton’s first law, the velocity of the jet fighter is expressed as:

$v_x=v_{0x}+a_{x}t$

Substituting the values in the above expression, we get-

$\begin{array}{rcl}{v}_x& =& 0m/s+\left(49.0m/s^2\right)\left(5.0s\right)\\ & =& 245m/s\end{array}$

Thus, the greatest speed he can reach is$=245m/s$