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A patient with a dislocated shoulder is put into a traction apparatus as shown in Fig. P1.63.The pulls A→andB→

have equal magnitudes and must combine to produce an outward traction force of 12.8 N on the patient’s arm.

How large should these pulls be?

Short Answer

Expert verified

The patient’s arm should be pulled is,A=B=7.55N.

Step by step solution

01

Identification of given data

  • The outward traction force is,Rx=Ax+Bx=128N.
  • The displacement vector of arm is,Ax+Bx.
02

Concept of Traction force

Tactile force, or traction, is the force utilized to induce motion between an object and a tangential surface.

Wet friction is the most typical method of generating motion between two bodies, however shear force applied to the tangential surface may also be utilized.

03

Determine magnitude of pull

The resultant force can be evaluated as,

Rx=Ax+BxRx=Acos32°+Bcos32°

Since,A=B.

So,

2Acos32°=RxA=Rx2cos32°A=12.8N2cos32°A=7.55N

The magnitude of force in Ax,

Ax=Acos32°Ax=7.55cos32°Ax=6.40N

Thus, the magnitude of each pull is greater than magnitude pull in x-direction.

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