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You throw a small rock straight up from the edge of a highway bridge that crosses a river. The rock passes you on its way down, 6.00 s after it was thrown. What is the speed of the rock just before it reaches the water 28.0 m below the point where the rock left your hand? Ignore air resistance.

Short Answer

Expert verified

Speed of the rock just before it reaches the water is 37.62 m/s.

Step by step solution

01

Identification of given values

Displacement (s) =-28 m

Time = 6 s

02

calculation for the initial velocity

After 6 seconds displacement is zero

We have equation of motions=ut+12at2

Acceleration, a = -9.81 m/s²

Time, t = 6 s

After 6 sceond Displacement, s = 0

s=ut+12at20=u×6+12×-9.81×62u=29.43m/s

03

calculation for speed

As we know thatv2=u2+2as

Here s = -28 m

v2=u2+2asv2=29.432+2×-9.81×-28v=37.62m/s

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