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91Ó°ÊÓ

You are given two vectors A→=−3.00i^+6.00j^andB→=7.00i^+2.00j^ . Let counter- clockwise angles be positive. (a) What angle doesA→ make with the +x-axis? (b) What angle doeslocalid="1662185215101" B→ make with the +x-axis? (c) Vectorlocalid="1662185222673" C→ is the sum of localid="1662185243350" A→andlocalid="1662185251585" B→ , so localid="1662185235469" C→=A→+B→What angle does localid="1662185258976" C→make with the +x-axis?

Short Answer

Expert verified

Answer

(a) A→ makes an angle of 116.6o with +x-axis.

(b) B→ makes an angle of 15.9o with +x-axis.

(c) C→ makes an angle of 63.4o with +x-axis.

Step by step solution

01

Step-by-Step Solution Step 1: Identification of given data

The given vectors areA→=−3.00i^+6.00j^andB→=7.00i^+2.00j^.

02

Vector Quantities and their magnitudes.

Consider a vector quantity V→=Vxi^+Vyj^ , Here Vx and Vy are the components along x, and y directions respectively and i^,j^ are the unit vectors along x, and y directions respectively. The direction of this vector is expressed as,

tanθ=VyVx

03

Estimation of angle between x-axis and  A→

Part (a)

The expression for the direction of a vector is given by,

tanθ=AyAx

Here, Ax and Ayare the components of A→.

Substitute -3.00 for Ax , 6.00 for Ay.

tanθ=6.00−3.00=−2θ=tan−1−2+180°=116.6°

Thus, A→ makes an angle of 116.6o with x-axis.

04

Estimation of angle between x-axis and  B→

Part (b)

The expression for the direction of a vector is given by,

tanθ=ByBx

Here, By and Bx are the components of B→.

Substitute 7.00 for Bx , 2.00 for By.

tanθ=2.007.00=0.285θ=tan−10.285=15.9°

Thus, B→ makes an angle of 15.9o with x-axis.

05

Estimation of angle between x-axis and  C→

Part (c)

The sum of the given vectors is expressed as,

C→=A→+B→

Substitute −3.00i^+6.00j^ for A→, 7.00i^+2.00j^ for B→.

C→=−3.00i^+6.00j^+7.00i^+2.00j^=−3.00+7.00i^+6.00+2.00j^=4.00i^+8.00j^

The expression for the direction of a vector is given by,

tanθ=CyCx

Here, Cx and Cy are the components of C→.

Substitute 4.00 for Cx , 8.00 for Cy .

tanθ=8.004.00=2.00θ=tan−12.00=63.4°

Thus, C→ makes an angle of 63.4o with x-axis.

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