91Ó°ÊÓ

The given data can be listed below as,

• The hole below the water surface is, h₂= h= 0.900m .
• The area of the hole is, A=1.320 cm² .
• The amount of water is, V = 10.0 L .

The total energy per unit mass of a fluid flowing, i.e., the sum of the fluid's kinetic energy, potential energy, and pressure energy at any point in its interior is equal to a constant value.

Part (a)

The pressure at the top of the water is equal to the atmospheric pressure and speed of water at the surface is zero (1m³ = 1000L) . The Bernoulli’s equation is expressed as,

$p_1+\frac{1}{2}\mathrm{ÒÏ}{v}_1^2+\mathrm{ÒÏ}g{h}_1=p_2+\frac{1}{2}\mathrm{ÒÏ}{v}_2^2+\mathrm{ÒÏ}g{h}_2$

Here, ${\mathrm{ÒÏ}}_{1}and{\mathrm{ÒÏ}}_2$are the pressure at the top and bottom level of the water surface, and h₁ and h₂ are the heights of the top and bottom level of the water surface, $\mathrm{ÒÏ}$is the density of water, and g is the gravitational acceleration.

Substitute all the value in the above equation.