/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q48E An ingenious bricklayer builds a... [FREE SOLUTION] | 91影视

91影视

An ingenious bricklayer builds a device for shooting bricks up to the top of the wall where he is working. He places a brick on a vertical compressed spring with force constant k=450N/mand negligible mass. When the spring is released, the brick is propelled upward. If the brick has mass 1.80kgand is to reach a maximum height of 3.6m above its initial position on the compressed spring, what distance must the bricklayer compress the spring initially? (The brick loses contact with the spring when the spring returns to its uncompressed length. Why?)

Short Answer

Expert verified

0.531m

Step by step solution

01

Identification of given data

Mass of brick ism=1.8kg

Spring constant isk=450N/m

Maximum height ish=3.6m

02

Significance of law of conservation of energy

Energy cannot be created or destroyed; it can only be transformed from one form into another or transferred from one object to another, according to the physical rule of conservation of energy.

When an object is compressed or under strain, such as when a rubber band is stretched, elastic potential energy is stored (when you squeeze a spring). The kinetic energy, also known as the energy of motion, is created when the potential energy is "released."

ElasticPotentiaEnergy12kx2=PotentialEnergymgh ...(i)

Where,kis spring constant, xis the initial compression, mis the mass, gis the acceleration due to gravity and his the height

03

Determining the distance must the bricklayer compress the spring initially

Using the equation (i)

12kx2=mgh

Substitute all the values in equation (i)

role="math" localid="1660031175673" x=21.8kg9.8m/s23.6m450N/m=0.531m

Hence the distance must the bricklayer compresses the spring initially is0.531m

The brick loses contact with the spring when the spring returns to its uncompressed length because at the uncompressed length of the spring the speed is maximum. After crossing this position, the speed gradually decreases. The spring losses the potential energy that would be gained by the brick in the form of kinetic energy. When bricks gain kinetic energy it lose contact with spring.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Neutron stars, such as the one at the center of the Crab Nebula, have about the same mass as our sun but have a much smaller diameter. If you weigh 675Non the earth, what would you weigh at the surface of a neutron star that has the same mass as our sun and a diameter of 20km?

For a spherical planet with mass M, volume V, and radius R,derive an expression for the acceleration due to gravity at the planet鈥檚 surface, g, in terms of the average density of the planet, =M/V, and the planet鈥檚 diameter, D=2R. The table gives the values of Dand gfor the eight major planets:

(a) Treat the planets as spheres. Your equation for as a function of and shows that if the average density of the planets is constant, a graph of versus will be well represented by a straight line. Graph as a function of for the eight major planets. What does the graph tell you about the variation in average density? (b) Calculate the average density for each major planet. List the planets in order of decreasing density, and give the calculated average density of each. (c) The earth is not a uniform sphere and has greater density near its center. It is reasonable to assume this might be true for the other planets. Discuss the effect this nonuniformity has on your analysis. (d) If Saturn had the same average density as the earth, what would be the value of at Saturn鈥檚 surface?

In describing the size of a large ship, one uses such expressions as 鈥渋t displaces 20,000 tons.鈥 What does this mean? Can the weight of the ship be obtained from this information?

The mass of Venus is 81.5% that of the earth, and its radius is 94.9% that of the earth. (a) Compute the acceleration due to gravity on the surface of Venus from these data. (b) If a rock weighs 75.0 N on earth, what would it weigh at the surface of Venus?

Question- Neptunium. In the fall of 2002, scientists at Los Alamos National Laboratory determined that the critical mass of neptunium-237 is about 60 kg. The critical mass of a fissionable material is the minimum amount that must be brought together to start a nuclear chain reaction. Neptunium-237 has a density of 19.5 g/cm3. What would be the radius of a sphere of this material that has a critical mass?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.