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Chapter 1: 11 (page 28)

Question- Neptunium. In the fall of 2002, scientists at Los Alamos National Laboratory determined that the critical mass of neptunium-237 is about 60 kg. The critical mass of a fissionable material is the minimum amount that must be brought together to start a nuclear chain reaction. Neptunium-237 has a density of 19.5 g/cm3. What would be the radius of a sphere of this material that has a critical mass?

Short Answer

Expert verified

The radius of sphere is 0.0270 m.

Step by step solution

01

Calculation of Volume of 60 kg material 

Given data:

The mas of neptunium-237 is m=60Kg.

The density of neptunium -237 is 蚁=19.5g/cm3.

The volume of the sphere can be calculated as

V=m蚁V=60kg19.5g/cm3脳1000kg/m31g/cm3V=3.07脳10-3m3

02

Calculating the radius of sphere

The radius of sphere will be,

V=43蟺R33.07脳10-3m3=43蟺R3R3=7.33脳10-4m3R=0.0270m

Thus, the radius of the sphere is 0.0270 m.

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