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Chapter 1: Q2E (page 357)

The center of gravity of a 5.00-kgirregular object is shown in Fig. E11.2. You need to move the center of gravity 2.20鈥�鈥�cmto the left by gluing on a 1.50-kgmass, which will then be considered as part of the object. Where should the center of gravity of this additional mass be located?

Short Answer

Expert verified

Thus, the center of gravity is left shifted by a length of 9.53 cm.

Step by step solution

01

Step-by-Step SolutionStep 1: Center of Gravity

There is a point inside any object where the whole weight of that body is concentrated, balancing all other parts of that body. This point is considered to be the Center of Gravity.

02

Find the distance

Given that the irregular object has mass m1=5.00kg, When the mass m2=1.50kgis added, the center of gravity shifts to the left bydata-custom-editor="chemistry" xcm=2.20cm

Let the whole set up illustrated as a free body diagram shown in the figure as:

Now, for the center of gravity, we have:

xcm=m1x1+m2x2m1+m2-2.20=5.000+1.50x5.00+1.50-2.20=1.506.50xx=-9.53cm

Thus, the center of gravity of the object, after adding extra mass, is shifted to the left by 9.53 cm.

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