91Ó°ÊÓ

The given data can be listed below as:

• The mass of the person is, m = 72 kg.
• The maximum height a human can jump is, $h_2=60 cm×\frac{{10}^{-2} m}{1 cm}=60×{10}^{-2}m$.

The potential energy is described as the energy that an object possesses while at rest. Moreover, the potential energy is also described as the stored energy of an object.

The equation of the gravitational potential energy is expressed as:

$U=mg(h_2-h_1)$

Here, U is the gravitational potential energy, m is the mass of the mountain climber, g is the acceleration due to gravity,$h_2$ is the maximum height a human can jump and$h_1$ is the standing position of the human.

Substitute the values in the above equation.

$$\begin{gathered} \mathrm{U}=\left(72\mathrm{kg}\right)\left(9.8\mathrm{m}/{\mathrm{s}}^2\right)\left(0.60\mathrm{m}-0\mathrm{m}\right) \\ =\left(705.6\mathrm{kg}×\mathrm{m}/{\mathrm{s}}^2\right)\left(0.6\mathrm{m}\right) \\ =423\mathrm{kg}×{\mathrm{m}}^2/{\mathrm{s}}^2×\frac{1\mathrm{J}}{1\mathrm{kg}×{\mathrm{m}}^2/{\mathrm{s}}^2} \\ =423J \end{gathered}$$

Thus, the increase in the gravitational potential energy in such a jump is 423 J.

Here, the energy is coming from the kinetic energy which the person provides himself while starting the jump. The kinetic energy comes because of the potential elastic energy from the muscles of that person.

Thus, the energy comes from the kinetic energy.