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Suppose that the charge shown in Fig. 21.28a is fixed in position. A small, positively charged particle is then placed at some location and released. Will the trajectory of the particle follow an electric field line? Why or why not? Suppose instead that the particle is placed at some point in Fig. 21.28b and released (the positive and negative charges shown are fixed in position). Will its trajectory follow an electric field line? Again, why or why not? Explain any differences between your answers for the two situations.

Short Answer

Expert verified

Yes, the straight filed lines are the trajectory the particle follows.

No, because the tangent to the curve is the trajectory of the particle.

Step by step solution

01

Determination of the trajectory of the particle in fig (a)

Force that is exerted on charged particles is,

F=qE

Solve for acceleration,

maa=qEEa=qEm

The direction of the acceleration of the particle is the same as the electric field. So, for positively charged particle, the trajectory is parallel to electric field line.

The field lines emanating from the positive charge is constant and thus the force exerted produces constant acceleration. Thus, the trajectory does follow the electric field lines.

02

 Step 2: Determination of the trajectory of the particle in fig (a) and fig (b)

The direction of force exerted on a charged particle is the same as the direction of electric field lines.

In between two charges, in fig (b), the direction of field line is tangential to the curves of the lines. So, the trajectory is tangential to the curved lines not following the electric field lines.

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