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Chapter 4: Q8E (page 777)

Three equal 1.20 碌C point charges are placed at the corners of an equilateral triangle with sides 0.400 m long. What is the potential energy of the system? (Take as zero the potential energy of the three charges when they are infinitely far apart.)

Short Answer

Expert verified

The potential energy of the system is 0.097 J.

Step by step solution

01

Potential energy formula

The potential energy of a body is given by

U=14蟿蟿蔚0鈭�i<jqiqjrij

Consider the three charges arethe same so the potential energy will be as follows:

U=14蟺蔚0鈭�I<JqiqjrijU=14蟺蔚0qiqjr12+q2q3r23+q1q3r13U=14蟿蟿蔚03q2r

Here,蔚0 is the permittivity of the free space.

Here, 14蟺蔚0=9脳109N.m2C2.

02

Determine the potential energy of the system

Substitute the values and solve as:

U=9脳109N.m2C231.20脳10-6C20.4m=0.097J

Therefore, the potential energy of the system is 0.097 J

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