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The ammonia molecule(NH3)has a dipole moment of5.0脳1030C.m. Ammonia molecules in the gas phase are placed in a uniform electric fieldwith magnitude1.6106N/m. (a) What is the change in electric potential energy 32kTwhen the dipole moment of a molecule changes its orientation with respect tofrom parallel to perpendicular? (b) At what absolute temperature T is the average translational kinetic energyof a molecule equal to the change in potential energy calculated in part (a)? (Note: Above this temperature, thermal agitation prevents the dipoles from aligning with the electric field.)

Short Answer

Expert verified

a) The change in electric potential is

b) The Absolute Temperature T is 0.39K.

Step by step solution

01

Potential Energy of a dipole

The initial energy is given by;

Ui=pEcosi

02

Change in electric potential energy

The change in the electric potential between the final and the initial position,

Therefore, the initial energy is;

As the angle between the p and E is 0,

Therefore, potential is

Now the change in electric potential energy is;

Hence, the change in electric potential is

03

Absolute temperature T

As the change is K.E is equivalent to the change in P.E

k is Steven-Boltzmann constant.

On putting the value;

Hence, the Absolute Temperature T is 0.39K.

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