91影视

The energy stored in capacitor and it is given by ${\mathbf{U}}_{\mathbf{c}}\mathbf{=}\frac{\mathbf{1}}{\mathbf{2}}{\mathbf{CV}}^{\mathbf{2}}$Where${\mathbf{U}}_{\mathbf{c}}$is the energy stored in capacitor.

The circuit is at the initial flow of current, the inductor doesn't store any energy at the initial state, so the energy in the coil is zero. Hence, we get the total energy stored in the circuit by$\mathrm{U}={\mathrm{U}}_{\mathrm{L}}+{\mathrm{U}}_{\mathrm{C}}$

The energy stored in capacitor is${\mathrm{U}}_{\mathrm{C}}=\frac{1}{2}{\mathrm{CV}}^2$.Substitute the values we get,

$$\begin{gathered} {\mathrm{U}}_{\mathrm{C}}=\frac{1}{2}\left(7.00脳{10}^{-6}\mathrm{F}\right){\left(16.0\mathrm{V}\right)}^2 \\ =\left(0.896脳{10}^{-3}\mathrm{J}\right)\left(\frac{1\mathrm{mJ}}{1.0脳{10}^{-3}\mathrm{J}}\right) \\ =8.96脳{10}^{-4}\mathrm{J} \end{gathered}$$

The total energy is given as$\mathrm{U}={\mathrm{U}}_{\mathrm{L}}+{\mathrm{U}}_{\mathrm{C}}$

$\mathrm{U}=0+8.96脳{10}^{-4}\mathrm{J}=8.96脳{10}^{-4}\mathrm{J}$

Therefore, the total energy is$8.96脳{10}^{-4}\mathrm{J}$

The current is maximum when the capacitor is fully discharged, which means it stores zero energy. In this case, the inductor stores all energy is the circuit. So, it becomes${\mathrm{U}}_{\mathrm{L}}=8.96脳{10}^{-4}\mathrm{J}$

The energy in inductor is related to the current in the circuit by${\mathrm{U}}_{\mathrm{L}}=\frac{1}{2}{\mathrm{Li}}^2$This current is the maximum current, so we solve this equation for I and we could get the maximum current by

$$\begin{gathered} {\mathrm{I}}_{\max }=\sqrt{\frac{2{\mathrm{U}}_{\mathrm{L}}}{\mathrm{L}}} \\ =\sqrt{\frac{2\left(8.96脳{10}^{-4}\mathrm{J}\right)}{\left(3.75脳{10}^{-3}\mathrm{mH}\right)}} \\ =0.691\mathrm{A} \end{gathered}$$

The current is the change of the charge with time. The current is the maximum when the capacitor has zero energy, in this case, there is no charge on the plates of the capacitor as the energy is zero. So, the charge is zero$\mathrm{Q}=0$