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Chapter 4: Q4E (page 713)

You have a pure (24-karat) gold ring of mass 10.8 g. Gold has an atomic mass of 197 g/mol and an atomic number of 79. (a) How many protons are in the ring, and what is their total positive charge? (b) If the ring carries no net charge, how many electrons are in it?

Short Answer

Expert verified
  1. The total number and charge of protons in the ring are 2.61脳10244.18脳105Crespectively.
  2. The number of electrons in the ring when there is no charge is2.61脳1024electrons.

Step by step solution

01

(a) Determination of the total number and charge of protons in the ring.

The number atoms in 1 mole of a substance are the Avogadro number NA.

So, the number of lead atoms is,

N=nNA

Here, n is the number of moles and NA is the Avogadro Number.

Now,the atomic mass of lead is,

M = 197g/mol

So the number of atoms in a mass of m = 10.8 is,

N=6.022脳1023atoms/mol10.8g197g/mol=3.300脳1022atoms

Atomic number is 79, thus the number of protons is,

np=(79protons/atom)3.300脳1022atoms=2.61脳1024protons.

Thus,Charge of the protons is,

Q=np1.60脳10鈭�19C/proton=4.18脳105C

02

(b) Determination of the number of electrons in the ring when there is no charge.

The number of electrons is always equal to the number of protons. So,

ne=np=2.61脳1024electrons

Thus, the number of electron son the ring is 2.61脳1024electrons .

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