/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q30E An L-R-C series circuit consists... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 4: Q30E (page 1045)

An L-R-C series circuit consists of a source with voltage amplitude 120 V and angular frequency 50.0 rad/s, a resistor with R = 400 鈩�, an inductor with L = 3.00 H, and a capacitor with capacitance C. (a) For what value of C will the current amplitude in the circuit be a maximum? (b) When C has the value calculated in part (a), what is the amplitude of the voltage across the inductor?

Short Answer

Expert verified

The current amplitude in the circuit will be maximum at and the corresponding voltage amplitude is 45V.

Step by step solution

01

Step-1: Formulas used  

Ohm鈥檚 law is given by I=VZ, which is used to get the amplitude of current.

Impedance of the circuit is given by Z=R2+(蝇尝-1蝇颁)2.

Voltage amplitude across inductor VL=I蝇尝.

02

Step-2: Calculation of C when current in the circuit will be maximum

Current will be maximum when impedance is maximum and that will happen when

蝇尝=1蝇颁C=1蝇2L=150rad/s23H=133.3渭贵

03

Step-3: Calculation of amplitude of the voltage across inductor

The maximum current I represents the amplitude current and could be calculated by

I=120V400惟=0.3A

Now, the voltage across inductor is

VL=0.3A50rad/s3H=45V

Hence, (a)the value of C for maximum current is C=133.3渭贵and (b)the voltage amplitude is 45V.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A battery-powered global positioning system (GPS) receiver operating 9.0 V on draws a current of 0.13 A. How much electrical energy does it consume during 30 minutes?

A 1.50-mcylindrical rod of diameter 0.500cmis connected to

a power supply that maintains a constant potential difference of 15.0Vacross

its ends, while an ammeter measures the current through it. You observe that

at room temperature (20.0鈭�C)the ammeter reads 18.5Awhile at 92.0鈭�Cit

reads 17.2A. You can ignore any thermal expansion of the rod. Find (a) the

resistivity at and (b) the temperature coefficient of resistivity at for the material of the rod.

A beam of protons traveling at 1.20 km/s enters a uniform magnetic field, traveling perpendicular to the field. The beam exits the magnetic field, leaving the field in a direction pependicurlar to its original direction (Fig. E27.24). The beam travels a distance of 1.10 cm while in the field. What is the magnitude of the magnetic field?

When switch Sin Fig. E25.29 is open, the voltmeter V reads 3.08 V. When the switch is closed, the voltmeter reading drops to 2.97 V, and the ammeter A reads 1.65 A. Find the emf, the internal resistance of the battery, and the circuit resistance R. Assume that the two meters are ideal, so they don鈥檛 affect the circuit.

Fig. E25.29.

A silver wire 2.6 mm in diameter transfers a charge of 420 C in 80

min. Silver containsfree electrons per cubic meter. (a) What is the

current in the wire? (b) What is the magnitude of thedrift velocity of the

electrons in the wire?
See all solutions

Recommended explanations on Physics Textbooks

Fundamentals of Physics

Read Explanation

Particle Model of Matter

Read Explanation

Famous Physicists

Read Explanation

Astrophysics

Read Explanation

Rotational Dynamics

Read Explanation

Mechanics and Materials

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.